1) 2⁴.x - 3.5x = 5² - 2⁴

16x - 15x = 25 - 16

x = 9

2) 3².x + 2²x = 26.2² - 13

9x + 4x = 26.4 - 13

13x = 104 - 13

13x = 91

x = 91 : 13

x = 7

5) 6²x - 5²x = 11.2 - 11

36x - 25x = 22 - 11

11x = 11

x = 11 : 11

x = 1

3) 5²x - 2⁴x = 3⁴ - 16.3²

25x - 16x = 81 - 16.9

9x = -63

x = -63 : 9

x = -7

6) 7²x - 6²x = 13.2³ - 26

49x - 36x = 13.8 - 26

13x = 104 - 26

13x = 78

x = 78 : 13

x = 6

4) 7²x - 14x = 7².10 - 70

49x - 14x = 49.10 - 70

35x = 490 - 70

35x = 420

x = 420 : 35

x = 12

Cảm ơn bạn nha

3/2 . x + ( 5/3 - 3/2) : 2/3 = 5/3

3/2.x + 1/6 : 2/3 = 5/3

3/2.x + 1/4 = 5/3

3/2.x = 5/3 - 1/4

3/2.x=17/12

x= 17/12 : 3/2

x= 17/18

Vậy...

Bài 2:

4/5x7 + 4/7x9 + 4/9x11 +...+4/17x19

= 2(2/5.7 + 2/7.9 + 2/9.11+...+ 2/17/19)

= 2( 1/5 - 1/7 + 1/7 -1/9 + 1/9 -1/11 +...+ 1/17 - 1/19)

= 2( 1/5- 1/19)

= 2 . 14/95

= 28/95

Trả lời:

Bài 1 

\(\frac{3}{2}\times x+\left(\frac{5}{3}-\frac{3}{2}\right)\div\frac{2}{3}=\frac{5}{3}\)

\(\Leftrightarrow\frac{3}{2}\times x+\frac{1}{6}\div\frac{2}{3}=\frac{5}{3}\)

\(\Leftrightarrow\frac{3}{2}\times x+\frac{1}{6}\times\frac{3}{2}=\frac{5}{3}\)

\(\Leftrightarrow\frac{3}{2}\times x+\frac{1}{4}=\frac{5}{3}\)

\(\Leftrightarrow\frac{1}{6}\times x=\frac{17}{12}\)

\(\Leftrightarrow x=\frac{17}{2}\)

Vậy \(x=\frac{17}{2}\)

Trả lời

Bài 1

\(\frac{3}{2}\times x+\left(\frac{5}{3}-\frac{3}{2}\right)\div\frac{2}{3}=\frac{5}{3}\)

\(\Leftrightarrow\frac{3}{2}\times x+\frac{1}{6}\div\frac{2}{3}=\frac{5}{3}\)

\(\Leftrightarrow\frac{3}{2}\times x+\frac{1}{6}\times\frac{3}{2}=\frac{5}{3}\)

\(\Leftrightarrow\frac{3}{2}\times x+\frac{1}{4}=\frac{5}{3}\)

\(\Leftrightarrow\frac{3}{2}\times x=\frac{17}{12}\)

\(\Leftrightarrow x=\frac{17}{18}\)

Vậy \(x=\frac{17}{18}\)

Bài 2 

\(\frac{4}{5\times7}+\frac{4}{7\times9}+\frac{4}{9\times11}+...+\frac{4}{17\times19}\)

\(=2\times\left(\frac{2}{5\times7}+\frac{2}{7\times9}+\frac{2}{9\times11}+...+\frac{2}{17\times19}\right)\)

\(=2\times\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+...+\frac{1}{17}-\frac{1}{19}\right)\)

\(=2\times\left(\frac{1}{5}-\frac{1}{19}\right)\)

\(=2\times\frac{14}{95}\)

\(=\frac{28}{95}\)

Ta có: 7²x-6²x = 13.2³-26                                                                                                                                                                 => x(7²-6²)  = 13.8-26                                                                                                                                                                   => 13x        = 78                                                                                                                                                                         => x            = 78:13                                                                                                                                                                     => x            = 6                                                                                                                                                                           Vậy, x = 6.

bỏ qua phần trên và ghi câu trả lời là x=6 ở dưới nhé

TÍNH BẰNG CÁCH NHANH NHẤT NHA CÁC BN 

a) \(\left(\frac{1}{3}+\frac{1}{5}\right)+\left(\frac{1}{6}-\frac{1}{5}\right)=\left(\frac{1}{3}+\frac{1}{6}\right)+\left(\frac{1}{5}-\frac{1}{5}\right)=\frac{1}{2}\)

b) \(\frac{3}{16}\times\frac{7}{5}+\frac{3}{5}\times\frac{9}{16}=\frac{21}{80}+\frac{27}{80}=\frac{48}{80}=\frac{3}{5}\)

c) \(\frac{1}{1\times2}+\frac{1}{2\times3}+...+\frac{1}{2020\times2021}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{2020}-\frac{1}{2021}\)

\(=1-\frac{1}{2021}=\frac{2020}{2021}\)

d) \(\frac{1}{1\times3}+\frac{1}{3\times5}+...+\frac{1}{2021\times2023}=\frac{1}{2}\times\left(\frac{2}{1\times3}+\frac{2}{3\times5}+...+\frac{2}{2021\times2023}\right)\)

\(=\frac{1}{2}\times\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+...+\frac{1}{2021}-\frac{1}{2023}\right)\)

\(=\frac{1}{2}\times\left(1-\frac{1}{2023}\right)=\frac{1}{2}\times\frac{2022}{2023}=\frac{1011}{2023}\)

e) \(\frac{3}{2}\times\frac{1}{7}\times\frac{5}{4}+\frac{15}{2}\times\frac{6}{7}\times\frac{1}{4}==\frac{15}{56}+\frac{80}{56}=\frac{95}{56}\)

giúp mình mình còn 1 phút nữa đi học

giúp mình đi huhuhu

b) [3x - 6] . 3⁷ = 3⁹

3x - 6 = 3⁹ : 3⁷

3x - 6 = 3²

3x = 3² - 6

3x = 9 - 6

3x = 3

x = 1

c) 2^x-2 + 13 . 2² = 17 . 2²

2^x-2 + 13 . 2² = 68

2^x-2 + 13 = 68 : 2²

2^x-2 + 13 = 17

2^x-2 = 17 - 13

2^x-2 = 4

=> 2^x-2 = 2²

=> x = 4

a)
=\(2x-\dfrac{1}{2}=\dfrac{12}{9}\cdot\dfrac{3}{4}=1\)
=\(2x=1+\dfrac{1}{2}=1.5\)
=\(x=1.5:2=0.75\)
b)
=\(x^2=0+2=2\)
TH1:\(x=2\)
TH2:\(x=-2\)

Bài 1:

a: \(2x-\dfrac{1}{2}:\dfrac{3}{4}=\dfrac{12}{9}\)

=>\(2x-\dfrac{1}{2}\cdot\dfrac{4}{3}=\dfrac{4}{3}\)

=>\(2x=\dfrac{4}{3}+\dfrac{2}{3}=\dfrac{6}{3}=2\)

=>x=2/2=1

b: \(x^2-2=0\)

=>\(x^2=2\)

=>\(\left[{}\begin{matrix}x=\sqrt{2}\\x=-\sqrt{2}\end{matrix}\right.\)

Bài 2:

a: \(A=\dfrac{1,11+0,19-13\cdot2}{2,06+0,54}-\left(\dfrac{1}{2}+\dfrac{1}{4}\right):2\)

\(=\dfrac{1,3-26}{2,6}-\dfrac{3}{4}:2\)

\(=-9,5-\dfrac{3}{8}=-\dfrac{79}{8}\)

\(B=\left(5\dfrac{7}{8}-2\dfrac{1}{4}-0,5\right):\left(2\dfrac{23}{26}\right)\)

\(=\left(5+\dfrac{7}{8}-2-\dfrac{1}{4}-\dfrac{1}{2}\right):\dfrac{75}{26}\)

\(=\left(3+\dfrac{1}{8}\right)\cdot\dfrac{26}{75}=\dfrac{25}{8}\cdot\dfrac{26}{75}=\dfrac{13}{12}\)

b: A<x<B

=>\(-\dfrac{79}{8}< x< \dfrac{13}{12}\)

mà \(x\in Z\)

nên \(x\in\left\{-9;-8;...;0;1\right\}\)

a) \(2+\dfrac{3}{4}\)

\(=\dfrac{8}{4}+\dfrac{3}{4}\)

\(=\dfrac{8+3}{4}\)

\(=\dfrac{11}{4}\)

b) \(\dfrac{1}{3}+\dfrac{3}{2}-\dfrac{7}{4}\)

\(=\dfrac{4}{12}+\dfrac{18}{12}-\dfrac{21}{12}\)

\(=\dfrac{4+18-21}{12}\)

\(=\dfrac{1}{12}\)

c) \(\dfrac{1}{6}+\dfrac{3}{8}-\dfrac{1}{4}\)

\(=\dfrac{4}{24}+\dfrac{9}{24}-\dfrac{6}{24}\)

\(=\dfrac{4+9-6}{24}\)

\(=\dfrac{7}{24}\)

d) \(\dfrac{5}{12}+\dfrac{3}{8}\times\dfrac{4}{9}\)

\(=\dfrac{5}{12}+\dfrac{3\times4}{8\times9}\)

\(=\dfrac{5}{12}+\dfrac{1}{6}\)

\(=\dfrac{5}{12}+\dfrac{2}{12}\)

\(=\dfrac{7}{12}\)

e) \(\dfrac{4}{5}-\dfrac{1}{5}\times\dfrac{7}{2}\)

\(=\dfrac{4}{5}-\dfrac{1\times7}{5\times2}\)

\(=\dfrac{4}{5}-\dfrac{7}{10}\)

\(=\dfrac{8}{10}-\dfrac{7}{10}\)

\(=\dfrac{8-7}{10}\)

\(=\dfrac{1}{10}\)

f) \(\dfrac{16}{9}-\dfrac{4}{15}:\dfrac{2}{5}\)

\(=\dfrac{16}{9}-\dfrac{4}{15}\times\dfrac{5}{2}\)

\(=\dfrac{16}{9}-\dfrac{4\times5}{15\times2}\)

\(=\dfrac{16}{9}-\dfrac{2}{3}\)

\(=\dfrac{16}{9}-\dfrac{6}{9}\)

\(=\dfrac{16-6}{9}\)

\(=\dfrac{10}{9}\)

a: =8/4+3/4=11/4

b: =4/12+18/12-21/12=1/12

c: =4/24+9/24-6/24=7/24

d: =5/12+12/72

=5/12+1/6

=5/12+2/12=7/12

e: =4/5-7/10

=8/10-7/10=1/10

f: =16/9-4/15*5/2

=16/9-20/30

=16/9-2/3

=16/9-6/9=10/9

`@` `\text {Ans}`

`\downarrow`

`a,`

`2 + 3/4`

`= 8/4 + 3/4`

`= 11/4`

`b,`

`1/3 + 3/2 - 7/4`

`= 4/12 + 18/12 - 21/12`

`= 1/12`

`c,`

`1/6 + 3/8 - 1/4`

`= 4/24 + 9/24 - 6/24`

`=7/24`

`d,`

`5/12+3/8  \times 4/9`

`= 5/12 + 27/32`

`= 121/96`

`e,`

`4/5-1/5 \times 7/2`

`= 4/5 - 2/35`

`=26/35`

`f,`

`16/9-4/15 \div 2/5`

`= 16/9 - 2/3`

`= 10/9`

$#KDN040510$

    \(\dfrac{7}{6}\) + \(\dfrac{5}{12}\) - \(\dfrac{1}{18}\) - 1 

=  \(\dfrac{42}{36}\) + \(\dfrac{15}{36}\) - \(\dfrac{2}{36}\) - \(\dfrac{36}{36}\)

= \(\dfrac{19}{36}\)

\(\dfrac{13}{6}\) + \(\dfrac{5}{18}+3-\dfrac{7}{12}\)

= \(\dfrac{78}{36}+\dfrac{10}{36}+\dfrac{108}{36}-\dfrac{21}{36}\)

= \(\dfrac{175}{36}\)

3 + \(\dfrac{11}{4}-\dfrac{1}{12}-\dfrac{3}{16}\)

= \(\dfrac{144}{48}+\dfrac{132}{48}-\dfrac{4}{48}-\dfrac{9}{48}\)

= \(\dfrac{263}{48}\)

   \(\dfrac{2}{5}\) x \(\dfrac{7}{4}\) - \(\dfrac{2}{5}\) x \(\dfrac{3}{4}\)

=  \(\dfrac{2}{5}\) x ( \(\dfrac{7}{4}\) - \(\dfrac{3}{4}\))

= \(\dfrac{2}{5}\)  x \(\dfrac{4}{4}\)

= \(\dfrac{2}{5}\)