tìm x
3x=9
4x=64
a,(3x+y-z)-94x-2y+6z)
b,(4x mũ 2 + x mũ 2 y -5 y mũ 2 ) - (5/3 x mũ 3 -6xy mũ 2 -x mũ 2 y )
a, \(=-91x-y+5z\)
b, \(=4x^2+x^2y-5y^2-\dfrac{5}{3}x^3+6xy^2+x^2y\)
\(=4x^2+2x^2y-5y^2-\dfrac{5}{3}x^3+6xy^2\)
(3x-1)^2=64 . tìm x
Ta có: \(\left(3x-1\right)^2=64\) \(\Rightarrow\left(3x-1\right)^2=8^2\) \(\Rightarrow3x-1=8\Rightarrow3x=8+1=9\)\(\Rightarrow x=9\div3\Rightarrow x=3\)
Tick nha
tìm x :
64 - x ( 3x - 27) : 2 = 40
\(64-x(3x-27)\div2=40\)
\(\Rightarrow x(3x-27)\div2=64-40\)
\(\Rightarrow x(3x-27)\div2=24\)
\(\Rightarrow x(3x-27)=24\div2\)
\(\Rightarrow x(3x-27)=12\)
\(\Rightarrow4x+27x=12\)
\(\Rightarrow x(27+4)=12\)
\(\Rightarrow31x=12\)
\(\Rightarrow x\in\varnothing\)
Tìm các số nguyên x biết:
3x+36=-7x - 64
Tìm x: 2^7x phần 2^3x=64
\(\frac{2^{7x}}{2^{3x}}=64\)
\(\Rightarrow\frac{\left(2^7\right)^x}{\left(2^3\right)^x}=2^6\)
\(\Rightarrow\left(\frac{128}{8}\right)^x=2^6\)
\(\Rightarrow16^x=2^6\)
\(\Rightarrow2^{4x}=2^6\)
\(\Rightarrow4x=6\)
\(\Rightarrow x=\frac{6}{4}=\frac{3}{2}\)
Ta co 27x / 23x = 64
===> 27x-3x = 64
===> 24x = 64 = 26
=====> 4x = 6
===> x = 1,5
Tìm x:
(3x - 2)^3 = 64
(3x - 2)3 = 64
<=> (3x - 2)3 = 43
<=>3x-2 = 4
=> 3x = 4+2
=> 3x = 6
=> x = 6 : 2
=> x = 3
bn ơi! mk nhầm
phải là 4:2 chứ ko phải 6:2
mong bn thông cm
bn giải lại đk ko, mik cũng làm như v nhưng tính lại kq sai
Hic
(3x-1)mũ 2 =64
tìm x
Ta có:64=8\(^2\)
\(\Rightarrow\)3x-1=8
3x=8+1
3x=9
x=9:3
x=3
Vậy x=3.
\(\left(3x-1\right)^2=64\)
\(\Rightarrow\left(3x-1\right)^2=8^2\)
\(\Rightarrow3x-1=8\)
\(\Rightarrow3x=9\)
\(\Rightarrow x=3\)
Vậy x = 3
Ta có:
\(\left(3x-1\right)^2=64\)
\(\Rightarrow\)\(\left(3x-1\right)^2=8^2\)
\(\Rightarrow\)\(3x-1=8\)
\(3x=8+1\)
\(3x=9\)
\(x=9:3\)
\(x=3\)
Vậy x = 3
♥♥♥ chúc bạn học tốt ♥♥♥
tìm x
b) (5x-1)^2 :2=8
c) (1-3x)^3 =-64
\(b,\left(5x-1\right)^2:2=8\\ \Leftrightarrow\left(5x-1\right)^2=16\\ \Leftrightarrow\left[{}\begin{matrix}5x-1=4\\5x-1=-4\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{3}{5}\end{matrix}\right.\\ c,\left(1-3x\right)^3=-64\\ \Leftrightarrow1-3x=-4\\ \Leftrightarrow3x=5\\ \Leftrightarrow x=\dfrac{5}{3}\)
Tìm các số nguyên x, biết:
3x + 36 = -7x - 64
-5x - 178 = 14x + 145
\(3x+36=-7x-64\)
\(10x=-100\)
\(x=-10\)
\(-5x-178=14x+145\)
\(-19x=323\)
\(x=-17\)
3x+36=−7x−643x+36=−7x−64
10x=−10010x=−100
x=−10x=−10
−5x−178=14x+145−5x−178=14x+145
−19x=323−19x=323
x=−17
Tìm x thuộc N biết :
(3x-4).2 mũ 3=64
\(\left(3x-4\right).2^3=64\)
\(\Rightarrow3x-4=64:8=8\)
\(\Rightarrow3x=4+8=12\)
\(\Rightarrow x=4\)
(3x-4).2^3 = 64
=> (3x-4).8 = 64
=) 3x-4 = 8
=> 3x = 12
=> x = 12:3
=> x = 4 (tmđk)
Vậy, x = 4
\(\left(3x-4\right).2^3=64\)
\(3x-4=\frac{64}{2^3}\)
\(3x-4=\frac{2^6}{2^3}\)
\(3x-4=2^{6-3}\)
\(3x-4=2^3\)
\(3x=8+4\)
\(3x=12\)
\(x=4\)
vậy \(x=4\)