Bài 2:

a: =>x:16=30,34+3,4-24,3=9,44

=>x=151,04

b: Đề thiếu rồi bạn

#)Giải :

           \(71+65.4=\frac{x+140}{x}+260\)

\(\frac{x+140}{x}+260=71+65.4\)

\(\frac{x+140}{x}+260=71+260\)

             \(\frac{x+140}{x}=71\)

         \(\frac{x}{x}+\frac{140}{x}=71\)

           \(1+\frac{140}{x}=71\)

                   \(\frac{140}{x}=71-1\)

                   \(\frac{140}{x}=70\)

                          \(x=140:70\)

                          \(x=2\)

             #~Will~be~Pens~#

\(71+65.4=\frac{x+140}{x}+260\)

\(\Rightarrow\frac{x+140}{x}+260=71+65.4\)

\(\frac{x+140}{x}+260=331\)

\(\frac{x+140}{x}=331-260=71\)

\(\frac{x}{x}+\frac{140}{x}=71\)

\(1+\frac{140}{x}=71\)

\(\frac{140}{x}=71-1=70\)

\(x=\frac{140}{70}=2\)

Vậy x=2

\(71+65\text{ x }4=\frac{x+140}{x}+260\)

\(\frac{x+140}{x}+260=71+65\text{ x }4\)

\(\frac{x+140}{x}+260=71+260\)

\(\frac{x+140}{x}=71\)

\(71x=x+140\)

\(71x-x=140\)

\(70x=140\)

\(x=140\text{ : }70\)

\(x=2\)

\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=\frac{23}{16}\)

\(4x+\frac{15}{16}=\frac{23}{16}\)

\(4x=\frac{1}{2}\)

\(x=\frac{1}{8}\)

             Vậy \(x=\frac{1}{8}\)

\(\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=\frac{23}{16}\)

\(\Rightarrow\left(x+x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=\frac{23}{16}\)

\(\Rightarrow5x+\frac{15}{32}=\frac{23}{16}\)

\(\Rightarrow5x=\frac{23}{16}-\frac{15}{32}\)

\(\Rightarrow5x=\frac{31}{32}\)

\(\Rightarrow x=\frac{31}{32}.\frac{1}{5}=\frac{31}{160}\)

Có 4x thôi Nguyễn Quang Trung

Bạn chắc bạn viết đúng đề bài không?

\(\frac{x-5}{73}+\frac{x-9}{142}=\frac{x-5}{136}+\frac{x-9}{71}\Leftrightarrow142x-710+73x-657=71x-355+136x-1224\)

\(\Leftrightarrow215x-1367=207x-1579\Leftrightarrow8x=212\Leftrightarrow x=26,5\)

146 ko phải 136

=> \(\frac{56}{3}\) - [x.(1,73+3,27)] = \(\frac{71}{4}\)

=> 5x = \(\frac{56}{3}\) - \(\frac{71}{4}\) =\(\frac{11}{12}\)

=> x= \(\frac{11}{12}\) : 5= \(\frac{11}{60}\) Vậy x= \(\frac{11}{60}\)

\(18\frac{2}{3}-5x=\frac{71}{4}\)

\(5x=\frac{56}{3}-\frac{71}{4}=\frac{11}{12}\)

\(x=\frac{11}{12}\div5=\frac{11}{60}\)

bạn k rồi mk mới làm nhanh cho hihi

truoc tien quy dong roi tinh hoac so sanh voi 1/2 kich nhe

câu này ở trong Violympic nên mình nói luôn đáp án là 1/8

Ta có: \(\frac{x+1}{79}+\frac{x+4}{76}=-\frac{x+7}{73}-\frac{x+9}{71}-4\)

\(\Leftrightarrow\frac{x+1}{79}+\frac{x+4}{76}+\frac{x+7}{73}+\frac{x+9}{71}+4=0\)

\(\Leftrightarrow\frac{x+1}{79}+1+\frac{x+4}{76}+1+\frac{x+7}{73}+1+\frac{x+9}{71}+1=0\)

\(\Leftrightarrow\frac{x+80}{79}+\frac{x+80}{76}+\frac{x+80}{73}+\frac{x+80}{71}=0\)

\(\Leftrightarrow\left(x+80\right)\left(\frac{1}{79}+\frac{1}{76}+\frac{1}{73}+\frac{1}{71}\right)=0\)

Vì \(\frac{1}{79}+\frac{1}{76}+\frac{1}{73}+\frac{1}{71}>0\)

nên x+80=0

hay x=-80

Vậy: x=-80

ko có kết quả sao bạn

       \(\frac{x-144}{10}+\frac{x-130}{12}+\frac{x-112}{14}+\frac{x-106}{16}+\frac{x-96}{17}=15\)

\(\Leftrightarrow\)\(\frac{x-144}{10}-1+\frac{x-130}{12}-2+\frac{x-112}{14}-3+\frac{x-106}{16}-4+\frac{x-96}{17}-5=0\)

\(\Leftrightarrow\)\(\frac{x-154}{10}+\frac{x-154}{12}+\frac{x-154}{14}+\frac{x-154}{16}+\frac{x-154}{17}=0\)

\(\Leftrightarrow\)\(\left(x-154\right)\left(\frac{1}{10}+\frac{1}{12}+\frac{1}{14}+\frac{1}{16}+\frac{1}{17}\right)=0\)

\(\Leftrightarrow\)\(x-154=0\)  (do   1/10 + 1/12 + 1/14 + 1/16 + 1/17  khác   0)

\(\Leftrightarrow\)\(x=154\)

Vậy...

Hình như đề có gì sai nha bạn.