3\(\frac{3:\left(0,2-0,1\right)}{2,5.\left(0,8+1,2\right)}+\frac{\left(34,06-33,84\right)\div4}{6,84\div\left(28,57-25,15\right)}\)
Những câu hỏi liên quan
P= 26:[\(\frac{3:\left(0,2-0,1\right)}{2,5.\left(0,8+1,2\right)}+\frac{\left(34,06-33,81\right).4}{6,84.\left(28,57-25,15\right)}\)] +\(\frac{2}{3}:\frac{4}{21}\)
Tính bằng máy tính CASIO:
\(A=\dfrac{\left(1986^2-1992\right).\left(1986^2+3972-3\right).1987}{1983.1985.1987.1989}\)
\(B=26\left[\dfrac{3:\left(0,2-0,1\right)}{2,5.\left(0,8+1,2\right)}+\dfrac{\left(34,06-33,81\right).4}{6,84:\left(28,57-25,15\right)}\right]+\dfrac{2}{3}:\dfrac{4}{21}\)
A = \(26:[\frac{(3:10,2-0,1)}{25.\left(0,8+1,2\right)}+\frac{\left(34,06-33,81\right).4}{6,84:\left(38,57-25,15\right)}]+\frac{2}{3}:\frac{4}{21}\)
B = \(\frac{0,8:\left(\frac{4}{5}.1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{(6\frac{5}{9}-3\frac{1}{4}).2\frac{2}{17}}+\left(1,2.0,5\right)\)
A= 6702,431685
B=2,183
ai muon k thi k va ket ban voi mik nhe.
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bạn viết cả cách làm ra giúp mình nhé
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TÍNH NHANH
a) dfrac{11}{125}-dfrac{17}{18}-dfrac{5}{7}+dfrac{4}{9}+dfrac{17}{4}
b) 1-dfrac{1}{2}+2-dfrac{2}{3}+3-dfrac{3}{4}+4-dfrac{1}{4}-3-dfrac{1}{3}-2-dfrac{1}{2}-1
c) 26:left{{}begin{matrix}end{matrix}right.dfrac{3:left(0,2-0,1right)}{2,5.left(0,8+1,2right)}+dfrac{left(34,06-33,81right).4}{6,84:left(28,57-25,15right)}+dfrac{2}{3}:dfrac{4}{21}
Các bạn ơi câu c là tới phân số ... 4/...15 là đóng ngoặc nhé. Hai ps đó trong ngoặc đấy
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TÍNH NHANH
a) \(\dfrac{11}{125}-\dfrac{17}{18}-\dfrac{5}{7}+\dfrac{4}{9}+\dfrac{17}{4}\)
b) \(1-\dfrac{1}{2}+2-\dfrac{2}{3}+3-\dfrac{3}{4}+4-\dfrac{1}{4}-3-\dfrac{1}{3}-2-\dfrac{1}{2}-1\)
c) \(26:\left\{{}\begin{matrix}\\\end{matrix}\right.\dfrac{3:\left(0,2-0,1\right)}{2,5.\left(0,8+1,2\right)}+\dfrac{\left(34,06-33,81\right).4}{6,84:\left(28,57-25,15\right)}+\dfrac{2}{3}:\dfrac{4}{21}\)
Các bạn ơi câu c là tới phân số ... 4/...15 là đóng ngoặc nhé. Hai ps đó trong ngoặc đấy
Tính A=26:[3:(0,2-0,1) trên 2,5.(0,8+1,2) + (34,06-33,81).4 trên 6,84:(28,57-25,15)] + 2 trên 3 : 4 trên 21
frac{1}{9}x frac{2}{145}- 4frac{1}{3}x frac{2}{145}+ frac{2}{145}a) frac{11}{125}-frac{17}{18}-frac{5}{7}+ frac{4}{9}+ frac{17}{14}b) 1 - frac{1}{2}+ 2 - frac{2}{3}+ 3 -frac{3}{4}+ 4 -frac{1}{4}- 3 - frac{1}{3}-2 -frac{1}{2}- 1c) 26 : orbr{begin{cases}3:left(0,2-0,1right)2,5.left(0,8+1,2right)end{cases}}+ frac{left(34,06-33,81right).4}{6,84:left(28,57-25,15right)}tất cả +frac{2}{3}:frac{4}{21}
Đọc tiếp
\(\frac{1}{9}\)x \(\frac{2}{145}\)- \(4\frac{1}{3}\)x \(\frac{2}{145}\)+ \(\frac{2}{145}\)
a) \(\frac{11}{125}\)-\(\frac{17}{18}\)-\(\frac{5}{7}\)+ \(\frac{4}{9}\)+ \(\frac{17}{14}\)
b) 1 - \(\frac{1}{2}\)+ 2 - \(\frac{2}{3}\)+ 3 -\(\frac{3}{4}\)+ 4 -\(\frac{1}{4}\)- 3 - \(\frac{1}{3}\)-2 -\(\frac{1}{2}\)- 1
c) 26 : \(\orbr{\begin{cases}3:\left(0,2-0,1\right)\\2,5.\left(0,8+1,2\right)\end{cases}}\)+ \(\frac{\left(34,06-33,81\right).4}{6,84:\left(28,57-25,15\right)}\)tất cả +\(\frac{2}{3}:\frac{4}{21}\)
a)=\(\frac{1}{9}.\frac{2}{145}-\frac{13}{3}.\frac{2}{145}+\frac{2}{145}\)
=\(\frac{2}{145}\left(\frac{1}{9}-\frac{13}{3}+1\right)\)
=\(\frac{2}{145}.\frac{-29}{9}\)
=\(\frac{-2}{45}\)
Học tốt nha!!!^^
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b)\(\frac{11}{125}-\frac{17}{18}-\frac{5}{7}+\frac{4}{9}+\frac{17}{14}\)\(=\left(-\frac{17}{18}+\frac{4}{9}\right)+\left(\frac{-5}{7}+\frac{17}{14}\right)+\frac{11}{125}\)
\(=-\frac{1}{2}+\frac{1}{2}+\frac{11}{125}\)
\(=0+\frac{11}{125}\)
\(=\frac{11}{125}\)
Chúc học tốt lần 2 nha^^
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Xem thêm câu trả lời
1. Tính ( hợp lý nếu có thể )
a, A dfrac{7,5-0,6+dfrac{3}{7}+dfrac{3}{13}}{2,75-2,2+dfrac{11}{7}+dfrac{11}{3}}
b, B 26 : left[dfrac{3:left(0,2-0,1right)}{2,5.left(0,8+1,2right)}+dfrac{left(34,06-33,81right).4}{6.84:left(28,57-25,15right)}right]+ dfrac{2}{3} : dfrac{4}{21}
c, C left[left(dfrac{2}{193}-dfrac{3}{386}right).dfrac{193}{17}+dfrac{33}{34}right] : left[left(dfrac{7}{2001}+dfrac{11}{4002}right).dfrac{2001}{25}+dfrac{9}{2}right]
d, D dfrac{0.8:left(dfrac{4}{5}.1,25right)}{0.64-df...
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1. Tính ( hợp lý nếu có thể )
a, A = \(\dfrac{7,5-0,6+\dfrac{3}{7}+\dfrac{3}{13}}{2,75-2,2+\dfrac{11}{7}+\dfrac{11}{3}}\)
b, B = 26 : \(\left[\dfrac{3:\left(0,2-0,1\right)}{2,5.\left(0,8+1,2\right)}+\dfrac{\left(34,06-33,81\right).4}{6.84:\left(28,57-25,15\right)}\right]\)+ \(\dfrac{2}{3}\) : \(\dfrac{4}{21}\)
c, C = \(\left[\left(\dfrac{2}{193}-\dfrac{3}{386}\right).\dfrac{193}{17}+\dfrac{33}{34}\right]\) : \(\left[\left(\dfrac{7}{2001}+\dfrac{11}{4002}\right).\dfrac{2001}{25}+\dfrac{9}{2}\right]\)
d, D = \(\dfrac{0.8:\left(\dfrac{4}{5}.1,25\right)}{0.64-\dfrac{1}{25}}\) + \(\dfrac{\left(1.08-\dfrac{5}{25}\right):\dfrac{4}{7}}{\left(6\dfrac{5}{9}-3\dfrac{1}{4}\right).2\dfrac{2}{7}}\) + ( 11,2 . 0,5 ) : \(\dfrac{4}{5}\)
Giúp mk nha chỉ là tính toán thông thường tính ra là đc nhưng mà mk lại khó tính ra nên các bn giúp mk nha
Đây là tính hợp lí ... mà câu a là 27,5 chứ không phải 2,75...
\(A=\dfrac{7,5-0,6+\dfrac{3}{7}+\dfrac{3}{13}}{27,5-2,2+\dfrac{11}{7}+\dfrac{11}{3}}=\dfrac{\dfrac{15}{2}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{13}}{\dfrac{55}{2}-\dfrac{11}{5}+\dfrac{11}{7}+\dfrac{11}{3}}\\ =\dfrac{3\left(\dfrac{5}{2}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{13}\right)}{11\left(\dfrac{5}{2}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{13}\right)}=\dfrac{3}{11}\)
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b: \(=26:\left[\dfrac{3:0.1}{2.5\cdot2}+\dfrac{0.25\cdot4}{2}\right]+\dfrac{2}{3}\cdot\dfrac{21}{4}\)
\(=26:\left[\dfrac{30}{5}+1\right]+\dfrac{42}{12}\)
\(=\dfrac{26}{7}+\dfrac{42}{12}=\dfrac{101}{14}\)
c: \(=\left[\dfrac{4-3}{386}\cdot\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\dfrac{25}{4002}\cdot\dfrac{2001}{25}+\dfrac{9}{2}\right]\)
\(=\dfrac{\left(\dfrac{1}{34}+\dfrac{33}{34}\right)}{\dfrac{1}{2}+\dfrac{9}{2}}=1:5=\dfrac{1}{5}\)
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tính
\(\frac{0,5+0,\left(3\right)+0,1\left(6\right)}{2,5+1,\left(6\right)+0,8\left(3\right)}\)
0,5+0,(3)+0,1(6)/2,5+0,1(6)+0,8(3)
=0,5+1/3+1/6/2,5+1/6+5/6
=1/3,5=2/7
k mk nha
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Tính
\(\frac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)
Đặt GTBT là A, ta có:
\(A=\frac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)
\(A=\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{6}}{\frac{5}{2}+\frac{5}{3}-\frac{5}{6}}\)
\(A=\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{6}}{5\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{6}\right)}=\frac{1}{5}\)
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\(\frac{1}{5}\)nhé
hok tốt