Question

1. Tính ( hợp lý nếu có thể )

a, A = \(\dfrac{7,5-0,6+\dfrac{3}{7}+\dfrac{3}{13}}{2,75-2,2+\dfrac{11}{7}+\dfrac{11}{3}}\)

b, B = 26 : \(\left[\dfrac{3:\left(0,2-0,1\right)}{2,5.\left(0,8+1,2\right)}+\dfrac{\left(34,06-33,81\right).4}{6.84:\left(28,57-25,15\right)}\right]\)+ \(\dfrac{2}{3}\) : \(\dfrac{4}{21}\)

c, C = \(\left[\left(\dfrac{2}{193}-\dfrac{3}{386}\right).\dfrac{193}{17}+\dfrac{33}{34}\right]\) : \(\left[\left(\dfrac{7}{2001}+\dfrac{11}{4002}\right).\dfrac{2001}{25}+\dfrac{9}{2}\right]\)

d, D = \(\dfrac{0.8:\left(\dfrac{4}{5}.1,25\right)}{0.64-\dfrac{1}{25}}\) + \(\dfrac{\left(1.08-\dfrac{5}{25}\right):\dfrac{4}{7}}{\left(6\dfrac{5}{9}-3\dfrac{1}{4}\right).2\dfrac{2}{7}}\) + ( 11,2 . 0,5 ) : \(\dfrac{4}{5}\)

Giúp mk nha chỉ là tính toán thông thường tính ra là đc nhưng mà mk lại khó tính ra nên các bn giúp mk nha

Answer 1

Đây là tính hợp lí ... mà câu a là 27,5 chứ không phải 2,75...

\(A=\dfrac{7,5-0,6+\dfrac{3}{7}+\dfrac{3}{13}}{27,5-2,2+\dfrac{11}{7}+\dfrac{11}{3}}=\dfrac{\dfrac{15}{2}-\dfrac{3}{5}+\dfrac{3}{7}+\dfrac{3}{13}}{\dfrac{55}{2}-\dfrac{11}{5}+\dfrac{11}{7}+\dfrac{11}{3}}\\ =\dfrac{3\left(\dfrac{5}{2}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{13}\right)}{11\left(\dfrac{5}{2}-\dfrac{1}{5}+\dfrac{1}{7}+\dfrac{1}{13}\right)}=\dfrac{3}{11}\)

Answer 2

b: \(=26:\left[\dfrac{3:0.1}{2.5\cdot2}+\dfrac{0.25\cdot4}{2}\right]+\dfrac{2}{3}\cdot\dfrac{21}{4}\)

\(=26:\left[\dfrac{30}{5}+1\right]+\dfrac{42}{12}\)

\(=\dfrac{26}{7}+\dfrac{42}{12}=\dfrac{101}{14}\)

c: \(=\left[\dfrac{4-3}{386}\cdot\dfrac{193}{17}+\dfrac{33}{34}\right]:\left[\dfrac{25}{4002}\cdot\dfrac{2001}{25}+\dfrac{9}{2}\right]\)

\(=\dfrac{\left(\dfrac{1}{34}+\dfrac{33}{34}\right)}{\dfrac{1}{2}+\dfrac{9}{2}}=1:5=\dfrac{1}{5}\)