1) 2(x + 5) + 3(x + 7) = 41
2x + 10 + 3x + 21 = 41
5x + 31 = 41
5x = 10
x = 2
6) 7(x - 1) + 5(3 - x) = 11x - 10
7x - 7 + 15 - 5x = 11x - 10
2x + 8 = 11x - 10
-9x = -18
x = 2

2) 5(x + 6) + 2(x - 3) = 38
5x + 30 + 2x - 6 = 38
7x + 24 = 38
7x = 14
x = 2

7) 4(2 + x) + 3(x - 2) = 12
8 + 4x + 3x - 6 = 12
7x + 2 = 12
7x = 10
x = 10/7

3) 7(5 + x) + 2(x - 10) = 15
35 + 7x + 2x - 20 = 15
9x + 15 = 15
9x = 0
x = 0

8) 5(2 + x) + 4(3 - x) = 10x - 15
10 + 5x + 12 - 4x = 10x - 15
x + 22 = 10x - 15
9x = 37
x = 37/9

4) 3(x + 4) + (8 - 2x) = 22
3x + 12 + 8 - 2x = 22
x + 20 = 22
x = 2

9) 7(x - 2) + 5(3 - x) = 11x - 6
7x - 14 + 15 - 5x = 11x - 6
2x + 1 = 11x - 6
-9x = -7
x = 7/9

5) 4(x + 5) + 3(7 - x) = 49
4x + 20 + 21 - 3x = 49
x + 41 = 49
x = 8

10) 5(3 - x) + 5(x + 4) = 6 + 4x
15 - 5x + 5x + 20 = 6 + 4x
35 = 6 + 4x
4x = 29
x = 29/4

a,

128-3x-12=23

3x=128-12-23

3x=93

x=93:3

= 31

b,

(12x+84+55):5=35

12x+84+55=35.5

12x+84+55=175

12x=175-55-84

12x=36

x=36:12

x=3

a: \(4x^3+12=120\)

=>\(4x^3=108\)

=>\(x^3=27=3^3\)

=>x=3

b: \(\left(x-4\right)^2=64\)

=>\(\left[{}\begin{matrix}x-4=8\\x-4=-8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-4\end{matrix}\right.\)

c: (x+1)^3-2=5^2

=>\(\left(x+1\right)^3=25+2=27\)

=>x+1=3

=>x=2

d: 136-(x+5)^2=100

=>(x+5)^2=36

=>\(\left[{}\begin{matrix}x+5=6\\x+5=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=-11\end{matrix}\right.\)

e: \(4^x=16\)

=>\(4^x=4^2\)

=>x=2

f: \(7^x\cdot3-147=0\)

=>\(3\cdot7^x=147\)

=>\(7^x=49\)

=>x=2

g: \(2^{x+3}-15=17\)

=>\(2^{x+3}=32\)

=>x+3=5

=>x=2

h: \(5^{2x-4}\cdot4=10^2\)

=>\(5^{2x-4}=\dfrac{100}{4}=25\)

=>2x-4=2

=>2x=6

=>x=3

i: (32-4x)(7-x)=0

=>(4x-32)(x-7)=0

=>4(x-8)*(x-7)=0

=>(x-8)(x-7)=0

=>\(\left[{}\begin{matrix}x-8=0\\x-7=0\end{matrix}\right.\)

=>\(\left[{}\begin{matrix}x=8\\x=7\end{matrix}\right.\)

k: (8-x)(10-2x)=0

=>(x-8)(x-5)=0

=>\(\left[{}\begin{matrix}x-8=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=5\end{matrix}\right.\)

m: \(3^x+3^{x+1}=108\)

=>\(3^x+3^x\cdot3=108\)

=>\(4\cdot3^x=108\)

=>\(3^x=27\)

=>x=3

n: \(5^{x+2}+5^{x+1}=750\)

=>\(5^x\cdot25+5^x\cdot5=750\)

=>\(5^x\cdot30=750\)

=>\(5^x=25\)

=>x=2

123 - 5 . ( x + 4 ) = 38

5 . ( x + 4 ) = 123 - 38

5 . ( x + 4 ) = 85

x + 4 = 85 : 5

x + 4 = 17

      x = 17 - 4

      x = 13

( 3x - 2⁴ ) . 7³ = 2 . 7⁴

( 3x - 16 ) . 343 = 2 . 2401

( 3x - 16 ) . 343 = 4802

3x - 16 = 4802 : 343

3x - 16 = 14

3x = 14 + 16

3x = 30

  x = 30 : 3

  x = 10

123 - 5( x + 4 ) = 38

=> 5( x + 4 ) = 123 - 38

=> x + 4 = 85 ÷ 5

=> x = 17 - 4 

=> x = 13

(3x - 2⁴ ) · 7³ = 2·7⁴

=> ( 3x - 16 ) = 2 . 7⁴ ÷ 7³

=> 3x - 16 = 14

=> 3x = 16 + 14

=> x = 30 ÷ 3 

=> x = 10

Giúp mình đi cảm ơn nhìu

Nhanh giùm mình nhé

Giúp mình đi mãi nộp rui

a) 123 - 5 (x + 4) = 38

5 (x + 4) = 123 - 38

5 (x + 4) = 85

x + 4 = 85 : 5

x + 4 = 17

x = 17 - 4

x = 13

b) (3x - 2⁴) . 7³ = 2 . 7⁴

3x - 2⁴ = 2 . 7⁴ : 7³

3x - 2⁴ = 2 . 7

3x - 16 = 14

3x = 14 + 16

3x = 30

x = 30 : 3

x = 10

c) (x : 3 - 4) . 5 = 15

x : 3 - 4 = 15 : 5

x : 3 - 4 = 3

x : 3 = 3 + 4

x : 3 = 7

x = 7 . 3

x = 21

\(a,123-5.\left(x+4\right)=38\)

\(5.\left(x+4\right)=123-38=85\)

\(x+4=85:5=17\)

\(x=17-4=13\)

a)123-5.(x+4)=38

118.(x+4)=38

x+=118-38

x+4=80

x=80-4

x=76

a, (5/7+ 2/7) + ( 3/8+5/8)

= 1              + 1