a, N(x) =3x^4 - 2x + 2x^3

+

   P(x) =             5x - 6x^3 -8

  _______________________

N(x) + P(x) = 3x^4 + 3x - 4x^3 - 8

@Huyền 

b, B(x) = -2x^3 . (x^3y -2x^2y^2 + 5xy^3

= -2xy^2 . x^3y + (-2xy^2 ) .2x^2y^2 + (-2xy^2) . 5xy^3

= -2x^4y^3 + (-4x^3y^4) +(-10x^2y^5)

@Huyền 

123

\(a,3xy^3-6xy^2+9x^2y^2=3xy^2\left(y-2+3x\right)\\ b,4x^2-y^2+10y-25=4x^2-\left(y^2-10y+25\right)=\left(2x\right)^2-\left(y-5\right)^2=\left(2x-y+5\right)\left(2x+y-5\right)\\ c,x^3-2x^2+x-4xy^2=x\left(x^2-2x+1-4y^2\right)=x\left[\left(x-1\right)^2-\left(2y\right)^2\right]=x\left(x-1-2y\right)\left(x-1+2y\right)\)

b: \(=\left(2x-y+5\right)\cdot\left(2x+y-5\right)\)

B.6x3-12x2+3x

chac zay

Bạn vui lòng viết đề đầy đủ, và gõ bằng công thức toán để được hỗ trợ tốt hơn.

đề theo mik nhìn 

\(x^2+2x^2y^2+2y^2-\left(x^2y^2+2x^2\right)-2=0\)

\(\Leftrightarrow x^2+2x^2y^2+2y^2-x^2y^2-2x^2-2=0\)

\(\Leftrightarrow x^2y^2-x^2+2y^2-2=0\)

\(\Leftrightarrow\left(x^2y^2-x^2\right)+\left(2y^2-2\right)=0\)

\(\Leftrightarrow x^2\left(y^2-1\right)+2\left(y^2-1\right)=0\)

\(\Leftrightarrow\left(x^2+2\right)\left(y^2-1\right)=0\)

\(\Leftrightarrow\left(x^2+2\right)\left(y-1\right)\left(y+1\right)=0\)

Dễ thấy: \(x^2+2\ge2>0\forall x\) (vô nghiệm)

\(\Rightarrow\left[{}\begin{matrix}y-1=0\\y+1=0\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}y=1\\y=-1\end{matrix}\right.\)

x2 + 2x2y2 + 2y2 − (x2y2+2x2) − 2=0

x2+2x2y2+2y2−x2y2−2x2−2=0

Dễ thấy:  (không có nghiệm)

⇒y−1=0 hoặc y+1=0⇒𝑦−1=0 hoặc 𝑦+1=0⇒y=1 hoặc y=−1

where is đề

a) 20x-5y=5(4x-y)

b) 5x(x-1)-3x(x-1)=(5x-3x)(x-1)=2x(x-1)

c) x(x+y)-6x-6y=x(x+y)-(6x+6y)=x(x+y)-6(x+y)=(x-6)(x+y)

d) 6x³-9x²=3x²(2x-3)

e) 4x²y - 8xy² + 10x²y²=2xy(2x-4y+5xy)

g) 20x²y-12x³=4x²(5y-3x)

h) 8x⁴+ 12x²y⁴- 16x³y⁴ = 4x²(2x²+3y⁴-4xy⁴)

k) 4xy² + 8xyz=4xy(y+2z)

l) 3x(x + 1) - 5y( x + 1 )=(x+1)(3x-5y)

m) 4x²-1=(2x-1)(2x+1)

o) 9-(x-y)²=(3-x+y)(3+x-y)

p) x³+27=(x+3)(x²+3x+9)

n) (x-y)²-4=(x-y-2)(x-y+2)

r) x⁴ + 2x² + 1=(x⁴+x²)+(x²+1)=x²(x²+1)+(x²+1)=(x²+1)²

s) 4x²  - 12xy + 9y²  = (2x-3y)²

t) x² - x - y² - y =(x²-y²)-(x+y)=(x-y)(x+y)-(x+y)=(x+y)(x-y-1)

v) x³ - x + y³ - y = (x³+y³)-(x+y)=(x+y)(x²-xy+y²)-(x+y)=(x+y)(x²-xy+y²-1)

a: \(20x-5y=5\left(4x-y\right)\)

b: \(5x\left(x-1\right)-3x\left(x-1\right)=2x\left(x-1\right)\)

c: \(x\left(x+y\right)-6x-6y=\left(x+y\right)\left(x-6\right)\)

d: \(6x^3-9x^2=3x^2\left(x-3\right)\)

e: \(4x^2y-8xy^2+10x^2y^2=2xy\left(2x-4y+5xy\right)\)

\(2x^2\left(x+1\right)+4\left(x+1\right)=2\left(x+1\right)\left(x^2+2\right)\)

\(-3x-6xy-9xz=-3x\left(1+2y+3z\right)\)

\(2x^2y-4xy^2+6xy=2xy\left(x-2y+3\right)\)

\(4x^3y^2-8x^3y^2+2x^4y=-4x^3y^2+2x^4y=2x^3y\left(x-2y\right)\)

1) \(2x^2\left(x+1\right)+4\left(x+1\right)=2\left(x+1\right)\left(x^2+2\right)\)

2) \(-3x-6xy-9xz=-3x\left(1+2y+3z\right)\)

3) \(2x^2y-4xy^2+6xy=2xy\left(x-2y+3\right)\)

4) \(4x^3y^2-8x^3y^2+2x^4y=-4x^3y^2+2x^4y=-2x^3y\left(2y-x\right)\)

Chọn B.

Ta có y = 6x³ – 2x² + 1 nên y’ = (6x³ – 2x² + 1)’ – (2x²)’ + 1’ = 18x² – 4x

mik làm r nhé

-3x³ + 2x² - x⁴ + 2x - 6x³ + 4x - 2 + 5x⁴ 

= -3x³  - 6x³ + 2x² - x⁴ + 5x⁴ + 2x + 4x - 2

=  -9x³ + 2x² +  4x⁴ + 6x - 2 

Sắp xếp các hạng tử có lũy thừa gảm dần : 

= 4x⁴  - 9x³  + 2x² + 6x - 2