Question

phân tích thành nhân tử 

1) 2x²(x+1) + 4(x+1)

2) -3x - 6xy - 9xz

3) 2x²y - 4xy² + 6xy

4) 4x³y² - 8x³y² + 2x⁴y 

Answer 1

\(2x^2\left(x+1\right)+4\left(x+1\right)=2\left(x+1\right)\left(x^2+2\right)\)

\(-3x-6xy-9xz=-3x\left(1+2y+3z\right)\)

\(2x^2y-4xy^2+6xy=2xy\left(x-2y+3\right)\)

\(4x^3y^2-8x^3y^2+2x^4y=-4x^3y^2+2x^4y=2x^3y\left(x-2y\right)\)

Answer 2

1) \(2x^2\left(x+1\right)+4\left(x+1\right)=2\left(x+1\right)\left(x^2+2\right)\)

2) \(-3x-6xy-9xz=-3x\left(1+2y+3z\right)\)

3) \(2x^2y-4xy^2+6xy=2xy\left(x-2y+3\right)\)

4) \(4x^3y^2-8x^3y^2+2x^4y=-4x^3y^2+2x^4y=-2x^3y\left(2y-x\right)\)