1. ĐKXĐ: \(x\ne5\)

\(\dfrac{3x+1}{x-5}+\dfrac{-2x-6}{x-5}\)

\(=\dfrac{3x+1-2x-6}{x-5}\)

\(=\dfrac{x-5}{x-5}\)

\(=1\)

2. ĐKXĐ:  \(x\ne\pm1\)

\(\dfrac{x+1}{2x-2}-\dfrac{x^2+3}{2x^2-2}\)

\(=\dfrac{x+1}{2\left(x-1\right)}-\dfrac{x^2+3}{2\left(x^2-1\right)}\)

\(=\dfrac{\left(x+1\right)^2}{2\left(x-1\right)\left(x+1\right)}-\dfrac{x^2+3}{2\left(x-1\right)\left(x+1\right)}\)

\(=\dfrac{x^2+2x+1-x^2-3}{2\left(x-1\right)\left(x+1\right)}\)

\(=\dfrac{2x-2}{\left(2x-2\right)\left(x+1\right)}\)

\(=\dfrac{1}{x+1}\)

x=0 

Trắc nghiệm
Câu 1:B

Câu 2:C

Câu 3:A

Câu 4:C

Câu 5:A 

Câu 6:B

Câu 7:D

Câu 8:D

a: BC=căn 6^2+8^2=10cm

AM=BC/2=5cm

b:

ΔAEH vuông tại A có AI là trung tuyến

nên IH=IA

=>góc IHA=góc IAH

góc IAH+góc MAB

=góc MBA+góc IHA=90 độ

=>góc IAM=90 độ

=>AI vuông góc AM

1 telling

2 to come

3 having

4  talking

5 to speak

6 giving

7  carry

8 to study

9 waiting

10  to start

11 to help

12 going 

13 to bring

14to visit

15 going

--------------------------------

1 preparing

2 working - finishing

3 to give - smoking

4 talking - eating

5 arguing -  working

6  to think - making

7 to come - standing

8  solving

9to lock - going

10 to persuade - change

-------------------------------------

1 watching - reading

2 playing - doing

3  to go

4 Did you see

5 to dream - were

6 showing - to send

7 going

8 doing

9  reading

10 to seeing

#\(Vion.Serity\)

#\(yGLinh\)

1 telling

2 to come

3 having

4  talking

5 to speak

6 giving

7  carry

8 to study

9 waiting

10  to start

11 to help

12 going 

13 to bring

14to visit

15 going

--------------------------------

1 preparing

2 working - finishing

3 to give - smoking

4 talking - eating

5 arguing -  working

6  to think - making

7 to come - standing

8  solving

9to lock - going

10 to persuade - change

-------------------------------------

1 watching - reading

2 playing - doing

3  to go

4 Did you see

5 to dream - were

6 showing - to send

7 going

8 doing

9  reading

10 to seeing

a a b a b a d a

1.a
2.a
3.b

4.b
5.b
6.a
7.d
8.a
 

\(1,\Rightarrow3:\dfrac{9}{4}=\dfrac{3}{4}:x\\ \Rightarrow\dfrac{4}{3}=\dfrac{3}{4}:x\\ \Rightarrow x=\dfrac{3}{4}:\dfrac{4}{3}=\dfrac{9}{16}\\ 2,\)

Nửa chu vi là \(50:2=25\left(cm\right)\)

Gọi cd là a, cr là b (cm)(a,b>0)

Ta có \(a:b=3:2\Rightarrow\dfrac{a}{3}=\dfrac{b}{2}\) và \(a+b=25\left(cm\right)\)

Áp dụng t/c dtsbn:

\(\dfrac{a}{3}=\dfrac{b}{2}=\dfrac{a+b}{3+2}=\dfrac{25}{5}=5\\ \Rightarrow\left\{{}\begin{matrix}a=15\\b=10\end{matrix}\right.\)

Vậy ...

B2:chiều dài là 15

Chiều rộng là 10