a,  \(=7.7.5.5.5^2=7^2.5^4\)

b, \(=2.3.2.3.3.2^2=3^3.2^4\)

c, \(=5^4\)

xin tiick

Viết các số hoặc các tính sau dưới dạng lũy thừa hoặc hoặc tích các lũy thứa         a) 7.35.5.25              B) 2.3.8.12              C) 5³.5

a) \(7\cdot7\cdot5\cdot5\cdot5\cdot5=7^2\cdot5^4\)

b) \(2\cdot3\cdot2\cdot2\cdot2\cdot2\cdot2\cdot3=2^6\cdot3^2\)

c) \(5^3\cdot5=5^3\cdot5^1=5^{3+1}=5^4\)

@Ngien

\(a,4\cdot9=36=6^2\)

\(b,1000\cdot10=10000=100^2\)

\(c,5^3\cdot5=5^4\)

Trả lời :

a) 4 = 2²                9 = 3²

b) 1000 . 10 . 10 = 10³ . 10² = 10⁵

c) 5³ . 5 = 5⁴

~~Học tốt~~

\(4=4^1\)\(;9=9^1\)

\(1000x10x10\)\(=10^3\)\(x10^1\)\(x10^1\)\(=10^5\)

\(5^3\)\(x5=5^4\)

5.p.p.5.p.2.q.q = 5².p³.q².2 

\(5.p.p.5.p^2.q.4.q=\left(5.5.4\right).\left(p.p.p^2\right).\left(q.q\right)=100p^4.q^2\)

5.p.p.5.p².q.4.q

= 5².p⁴.2².q²

= 10².p⁴.q²

a: \(3\cdot3\cdot3\cdot3\cdot3=3^5\)

b: \(y\cdot y\cdot y\cdot y=y^4\)

c: \(5\cdot p\cdot5\cdot p\cdot2\cdot q\cdot4\cdot q=25\cdot2\cdot4\cdot p^2q^2=2\cdot\left(10qp\right)^2\)

d: \(a\cdot a+b\cdot b+c\cdot c+d\cdot d\cdot d\cdot d=a^2+b^2+c^2+d^4\)

a) 3.3.3.3.3 = 3\(^5\)

b) y.y.y.y = y\(^4\)

c) 5.p.5.p.2.q.4.q = 5\(^2\).p\(^2\).q\(^2\).2\(^3\) 

(2\(^3\) ở đây là vì 2.4 = 2.2.2 = 2\(^3\))

d) a.a + b.b + c.c.c + d.d.d.d = a\(^2\)+b\(^2\)+c\(^3\)+d\(^4\)

\(a,5\cdot p\cdot5\cdot p\cdot2q\cdot4q\)

\(=5^2\cdot p^2\cdot2\cdot q\cdot2^2\cdot q\)

\(=5^2\cdot2^3\cdot p^2\cdot q^2\)

\(b,a\cdot a+b\cdot b+c\cdot c\cdot c+d\cdot d\cdot d\cdot d\)

\(=a^2+b^2+c^3+d^4\)

#Urushi

l) 27^8=(3³)⁸=3²⁴

=>27⁸:3²²=3²⁴:3²²

=3^24-22=3²

m) 8^4=(2³)⁴=2¹²

4⁵=(2²)⁵=2¹⁰

=>8⁴:4⁵=2¹²:2¹⁰

=2^12-10=2²

a) \(27^8:3^{22}\)

\(=\left(3^3\right)^8:3^{22}\)

\(=3^{24}:3^{22}=3^{24-22}\)

\(=3^2\)

b) \(8^4:4^5\)

\(=\left(2^3\right)^4:\left(2^2\right)^5\)

\(=2^{12}:2^{10}=2^{12-10}=2^2\)

Oong ơi cái này lớp 6 nha ông!

#Phương

( 3 . 7 )³ = 21³

luỹ thừa lớp 6 nhé em

64=2^6

128=2^7

125=5^3

625=5^4

81=3^4

243=3^5

1024=2^10

64=2⁴

128=2⁷

125=5³

625=5⁴

81=3⁴

243=3⁵

1024=2¹⁰

2^6 => 64

2^7 => 128

5^3=>125

5^4 => 625

3^4 => 81

3^5 => 243

2^10 => 1024

K NHA

\(a,2^5.8^4=2^5.2^{12}=2^{17}\)

\(b,25^6.125^3=5^{12}.5^9=5^{21}\)

\(c,625^5.25^7=5^{20}.5^{14}=5^{34}\)

\(d,12^3.3^3=\left(12.3\right)^3=36^3\)