câu 1:\(\sqrt{7x^2+20x-86}+x\sqrt{31-4x-x^2}=x+1\)
câu 2:\(\sqrt[3]{\frac{12x^2+12x+9}{4}}=x+\sqrt[4]{\frac{4x^3-2}{3}}\)
Những câu hỏi liên quan
GPT:
1/ \(\sqrt{7x^2+20x-86}+x\sqrt{31-4x-x^2}=x+1\)
2/ \(\sqrt[3]{\frac{12x^2+12x+9}{4}}=x+\sqrt[4]{\frac{4x^3-2}{3}}\)
1/ \(\sqrt{7x^2+20x-86}+x\sqrt{31-4x-x^2}=x+1\)
2/ \(\sqrt[3]{\frac{12x^2+12x+9}{4}}=x+\sqrt[4]{\frac{4x^3-2}{3}}\)
em mới lớp 10, nên anh chị, thầy cô giải cách nào dễ hiểu giúp em nha
Gidipt 1) sqrt(x ^ 2 - x) = sqrt(3 - x)
2) sqrt(x ^ 2 - 4x + 3) = x - 2
3) sqrt(4 * (1 - x) ^ 2) - 6 = 0
4) sqrt(x ^ 2 - 4x + 4) = sqrt(4x ^ 2 - 12x + 9)
5) sqrt(x ^ 2 - 4) + sqrt(x ^ 2 + 4x + 4) = 0
6) 1sqrt(x + 2sqrt(x - 1)) + sqrt(x - 2sqrt(x - 1)) = 2
1: =>x^2-x=3-x
=>x^2=3
=>x=căn 3 hoặc x=-căn 3
2: =>x^2-4x+3=x^2-4x+4 và x>=2
=>3=4(vô lý)
3: =>2|x-1|=6
=>|x-1|=3
=>x-1=3 hoặc x-1=-3
=>x=-2 hoặc x=4
4: =>|2x-3|=|x-2|
=>2x-3=x-2 hoặc 2x-3=-x+2
=>x=1 hoặc x=5/3
5: =>\(\sqrt{x+2}\left(\sqrt{x-2}+\sqrt{x+2}\right)=0\)
=>x+2=0
=>x=-2
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2. Giải PT:
a) \(\frac{9x-7}{\sqrt{7x+5}}=\sqrt{7x+5}.\)
b) \(\sqrt{4x-20}+3\sqrt{\frac{x-5}{9}}-\frac{1}{3}\sqrt{9x-45}=4.\)
c) \(2x-x^2+\sqrt{6x^2-12x+7}=0.\)
d) \(\left(x+1\right)\left(x+4\right)-3\sqrt{x^2+5x+2}=6.\)
\(a,\frac{9x-7}{\sqrt{7x+5}}=\sqrt{7x+5}\)\(ĐKXĐ:x\ge-\frac{5}{7}\)
\(\Leftrightarrow9x-7=7x+5\)
\(\Leftrightarrow9x-7x=5+7\)
\(\Leftrightarrow2x=12\)
\(\Leftrightarrow x=6\)
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\(b,\sqrt{4x-20}+3\sqrt{\frac{x-5}{9}}-\frac{1}{3}\sqrt{9x-45}=4\)
\(\Leftrightarrow\sqrt{4\left(x-5\right)}+3.\frac{\sqrt{x-5}}{\sqrt{9}}-\frac{1}{3}\sqrt{9\left(x-5\right)}=4\)
\(\Leftrightarrow2\sqrt{x-5}+\sqrt{x-5}-\sqrt{x-5}=4\)
\(\Leftrightarrow\sqrt{x-5}\left(2+1-1\right)=4\)
\(\Leftrightarrow2\sqrt{x-5}=4\)
\(\Leftrightarrow\sqrt{x-5}=2\)
\(\Leftrightarrow x-5=4\)
\(\Leftrightarrow x=9\)
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Tìm GTLN:
a) A sqrt{3-2x^2}
b) B sqrt{-9x^2+6x+3}
c) B 5+sqrt{-4x^2-4x}
d) C sqrt{-x^2+x+frac{3}{4}}
e) D sqrt{x^2+2x+1}+sqrt{x^2-2x+1}
g) G sqrt{25x^2-20x+4}+sqrt{25x^2}
f) F sqrt{4x^2-4x+1}+sqrt{4x^2-12x+9}
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Tìm GTLN:
a) A= \(\sqrt{3-2x^2}\)
b) B= \(\sqrt{-9x^2+6x+3}\)
c) B= \(5+\sqrt{-4x^2-4x}\)
d) C= \(\sqrt{-x^2+x+\frac{3}{4}}\)
e) D= \(\sqrt{x^2+2x+1}+\sqrt{x^2-2x+1}\)
g) G= \(\sqrt{25x^2-20x+4}+\sqrt{25x^2}\)
f) F= \(\sqrt{4x^2-4x+1}+\sqrt{4x^2-12x+9}\)
c)\(C=5+\sqrt{-4x^2-4x}\)
\(C=5+\sqrt{1-\left(4x^2+4x+1\right)}\)
\(C=5+\sqrt{1-\left(2x+1\right)^2}\)
Ta có: \(-\left(2x+1\right)^2\le0\)
\(\sqrt{1-\left(2x+1\right)^2}\le1\)
\(\sqrt{1-\left(2x+1\right)^2}+5\le6\Leftrightarrow C\le6\)
Vậy \(C_{max}=6\) khi \(2x+1=0\Leftrightarrow x=-\frac{1}{2}\)
f) \(F=\sqrt{4x^2-4x+1}+\sqrt{4x^2-12x+9}\)
\(F=\sqrt{\left(2x-1\right)^2}+\sqrt{\left(2x-3\right)^2}\)
\(F=\left|2x-1\right|+\left|3-2x\right|\ge\left|2x+1+3-2x\right|=4\)
\(F_{min}=4\) khi \(\left(2x-1\right)\left(3-2x\right)\ge0\Leftrightarrow\frac{1}{2}\le x\le\frac{3}{2}\)
Mấy còn lại tương tự =)))
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giải phương trình
a, \(\sqrt{4x-20}+3\sqrt{\dfrac{x-5}{9}}-\dfrac{1}{3}\sqrt{9x-45}=4\)
b, \(2x-x^2+\sqrt{6x^2-12x+7}=0\)
c, \(\dfrac{9x-7}{\sqrt{7x+5}}=\sqrt{7x+5}\)
$\sqrt{7x^2+20x-86}+x\sqrt{31-4x-x^2}=x+1$
2) giải pt
3) \(\sqrt{4x+1}=x+1\)
4) \(2\sqrt{x-1}+\dfrac{1}{3}\sqrt{9x-9}=15\)
5) \(\sqrt{4x^2-12x+9}=7\)
6) \(5\sqrt{9x-9}-\sqrt{4x-4}-\sqrt{x-1}=36\)
giúp mk vs ah
3: Ta có: \(\sqrt{4x+1}=x+1\)
\(\Leftrightarrow x^2+2x+1=4x+1\)
\(\Leftrightarrow x\left(x-2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\left(nhận\right)\\x=2\left(nhận\right)\end{matrix}\right.\)
4: Ta có: \(2\sqrt{x-1}+\dfrac{1}{3}\sqrt{9x-9}=15\)
\(\Leftrightarrow3\sqrt{x-1}=15\)
\(\Leftrightarrow x-1=25\)
hay x=26
5: Ta có: \(\sqrt{4x^2-12x+9}=7\)
\(\Leftrightarrow\left|2x-3\right|=7\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=7\\2x-3=-7\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=10\\2x=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=5\\x=-2\end{matrix}\right.\)
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giải phương trình :1, sqrt{4-x^2}+2sqrt[3]{x^4-4x^3+4x^2}left(x-1right)^2+1-left|xright|2, 2x^3+9x^2-6xleft(1+2sqrt{6x-1}right)+2sqrt{6x-1}+803, x^3-3x+1sqrt{8-3x^2}4, left(4x^2+x-1right)sqrt{x^2+x+2}left(4x^2+3x+5right)sqrt{x^2-1}5, sqrt[3]{3-x^3}2x^3+x-36, sqrt[3]{x^2+3x+3}+sqrt[3]{2x^2+3x+2}6x^2+12x+87, frac{x^2+2x-8}{x^2-2x+3}left(x+1right)left(sqrt{x+2}-2right)8, frac{4x-1}{sqrt{4x-3}}+frac{11-2x}{sqrt{5-x}}frac{15}{2}9, ...
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giải phương trình :
1, \(\sqrt{4-x^2}+2\sqrt[3]{x^4-4x^3+4x^2}=\left(x-1\right)^2+1-\left|x\right|\)
2, \(2x^3+9x^2-6x\left(1+2\sqrt{6x-1}\right)+2\sqrt{6x-1}+8=0\)
3, \(x^3-3x+1=\sqrt{8-3x^2}\)
4, \(\left(4x^2+x-1\right)\sqrt{x^2+x+2}=\left(4x^2+3x+5\right)\sqrt{x^2-1}\)
5, \(\sqrt[3]{3-x^3}=2x^3+x-3\)
6, \(\sqrt[3]{x^2+3x+3}+\sqrt[3]{2x^2+3x+2}=6x^2+12x+8\)
7, \(\frac{x^2+2x-8}{x^2-2x+3}=\left(x+1\right)\left(\sqrt{x+2}-2\right)\)
8, \(\frac{4x-1}{\sqrt{4x-3}}+\frac{11-2x}{\sqrt{5-x}}=\frac{15}{2}\)
9, \(x^2-4x+14+\sqrt{x+4}=2\sqrt{1+12x}+\sqrt{1+\sqrt{1+12x}}\)
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vậy đến bố tổ conf biết
k thì 2 nha
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