Giair phương trình:
\(\dfrac{3x}{x-2}-\dfrac{x}{x+5}+\dfrac{2x^2}{7x-10-x^2}=0\)
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Giair các phương trình saua,dfrac{3x^2+7x-10}{x}0 b,dfrac{4x-17}{2x^2+1}0 c,dfrac{left(x^2+2xright)-left(3x-6right)}{x+2}0d,dfrac{x^2-x-6}{x-3}0 e,dfrac{2x-5}{x+5}3 f,dfrac{5}{3x+2}2x-1g,dfrac{x^2-6}{x}x+dfrac{3}{2} h,dfrac{4}{x-2}-x+20 Giups mình với , mik đang cần gấp
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Giair các phương trình sau
\(a,\dfrac{3x^2+7x-10}{x}=0\) \(b,\dfrac{4x-17}{2x^2+1}=0\) \(c,\dfrac{\left(x^2+2x\right)-\left(3x-6\right)}{x+2}=0\)
\(d,\dfrac{x^2-x-6}{x-3}=0\) \(e,\dfrac{2x-5}{x+5}=3\) \(f,\)\(\dfrac{5}{3x+2}=2x-1\)
\(g,\dfrac{x^2-6}{x}=x+\dfrac{3}{2}\) \(h,\dfrac{4}{x-2}-x+2=0\)
Giups mình với , mik đang cần gấp
a) ĐKXĐ: \(x\ne0\)
Ta có: \(\dfrac{3x^2+7x-10}{x}=0\)
Suy ra: \(3x^2+7x-10=0\)
\(\Leftrightarrow3x^2-3x+10x-10=0\)
\(\Leftrightarrow3x\left(x-1\right)+10\left(x-1\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(3x+10\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\3x+10=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\3x=-10\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{10}{3}\end{matrix}\right.\)
Vậy: \(S=\left\{1;-\dfrac{10}{3}\right\}\)
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a/ \(\dfrac{3x^2+7x-10}{x}=0\)
\(< =>3x^2+7x-10=0\)
\(< =>3x^2+10x-3x-10=0\)
\(< =>\left(3x^2+10x\right)-\left(3x+10\right)=0\)
\(< =>x\left(3x+10\right)-\left(3x+10\right)=0\)
\(< =>\left(3x+10\right)\left(x-1\right)=0\)
\(=>\left\{{}\begin{matrix}3x+10=0=>x=-\dfrac{10}{3}\\x-1=0=>x=1\end{matrix}\right.\)
Vậy tập nghiệm của .....
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Giải các phương trình sau:
\(e.\dfrac{12}{1-9x^2}=\dfrac{1-3x}{1+3x}-\dfrac{1+3x}{1-3x}\)
\(f.\dfrac{6x+1}{x^2-7x+10}+\dfrac{5}{x-2}=\dfrac{3}{x-5}\)
\(g.\dfrac{2}{x+2}-\dfrac{2x^2+16}{x^3+8}=\dfrac{5}{x^2-2x+4}\)
\(h.\dfrac{8}{x-8}+\dfrac{11}{x-11}=\dfrac{9}{x-9}+\dfrac{10}{x-10}\)
e) ĐK : \(\left\{{}\begin{matrix}1+3x\ne0\\1-3x\ne0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}3x\ne-1\\3x\ne1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x\ne\dfrac{-1}{3}\\x\ne\dfrac{1}{3}\end{matrix}\right.\)
\(\Leftrightarrow\dfrac{12}{\left(1-3x\right)\left(1+3x\right)}=\dfrac{\left(1-3x\right)^2-\left(1+3x\right)^2}{\left(1+3x\right)\left(1-3x\right)}\)
\(\Leftrightarrow12\left(1+3x\right)\left(1-3x\right)=\left(1-3x\right)\left(1+3x\right)\left(1-3x-1-3x\right)\left(1-3x+1+3x\right)\)
\(\Leftrightarrow12=\left(-6x\right).2\Leftrightarrow6=-6x\)
\(\Leftrightarrow x=-1\left(TM\right)\)
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1) giải phương trình :
a) left(2+3right)left(dfrac{3x+8}{2-7x}+1right)left(x-5right)left(dfrac{3x+8}{2-7x}+1right)
b) dfrac{7x+10}{x+1}left(x^2-x-2right)-dfrac{7x+10}{x+1}left(2x^2-3x-5right)0
c) dfrac{2x+5}{x+3}+1dfrac{4}{x^2+2x-3}-dfrac{3x-1}{1-x}
d) dfrac{13}{2x^2+x-21}+dfrac{1}{2x+7}+dfrac{6}{9-x^2}0
i) dfrac{x-49}{50}+dfrac{x-50}{49}dfrac{49}{x-50}+dfrac{50}{x-49}
k) dfrac{1+dfrac{x}{x+3}}{1-dfrac{x}{x+3}}3
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1) giải phương trình :
a) \(\left(2+3\right)\left(\dfrac{3x+8}{2-7x}+1\right)=\left(x-5\right)\left(\dfrac{3x+8}{2-7x}+1\right)\)
b) \(\dfrac{7x+10}{x+1}\left(x^2-x-2\right)-\dfrac{7x+10}{x+1}\left(2x^2-3x-5\right)=0\)
c) \(\dfrac{2x+5}{x+3}+1=\dfrac{4}{x^2+2x-3}-\dfrac{3x-1}{1-x}\)
d) \(\dfrac{13}{2x^2+x-21}+\dfrac{1}{2x+7}+\dfrac{6}{9-x^2}=0\)
i) \(\dfrac{x-49}{50}+\dfrac{x-50}{49}=\dfrac{49}{x-50}+\dfrac{50}{x-49}\)
k) \(\dfrac{1+\dfrac{x}{x+3}}{1-\dfrac{x}{x+3}}=3\)
b: \(\Leftrightarrow\dfrac{7x+10}{x+1}\left(x^2-x-2-2x^2+3x+5\right)=0\)
\(\Leftrightarrow\left(7x+10\right)\left(-x^2+2x+3\right)=0\)
\(\Leftrightarrow\left(7x+10\right)\left(x^2-2x-3\right)=0\)
=>(7x+10)(x-3)=0
hay \(x\in\left\{-\dfrac{10}{7};3\right\}\)
d: \(\Leftrightarrow\dfrac{13}{2x^2+7x-6x-21}+\dfrac{1}{2x+7}-\dfrac{6}{\left(x-3\right)\left(x+3\right)}=0\)
\(\Leftrightarrow\dfrac{13}{\left(2x+7\right)\left(x-3\right)}+\dfrac{1}{\left(2x+7\right)}-\dfrac{6}{\left(x-3\right)\left(x+3\right)}=0\)
\(\Leftrightarrow26x+91+x^2-9-12x-14=0\)
\(\Leftrightarrow x^2+14x+68=0\)
hay \(x\in\varnothing\)
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8 tháng 2 2023 lúc 21:19
Giair phương trình1) 2x2-3x-20 7) (2x2-3x-4)2(x2-x)22) 4x2-7x-20 8) dfrac{2}{x+1}-dfrac{3}{x+2}dfrac{1}{3x+3}3) 4x2+5x-60 9) dfrac{x}{x-3}dfrac{1}{x+2}4) 4x2+5x-90 10) dfrac{4}{2x-3}-dfrac{7}{3x-5}05) 5x2-18x-80 11) dfrac{7}{x+2}+dfrac{2}{x+3}dfrac{1}{x^2+5x+6}6) (3x2+2x+4)2(x2-4)2 12) dfrac{4}{...
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Giair phương trình
1) 2x2-3x-2=0 7) (2x2-3x-4)2=(x2-x)2
2) 4x2-7x-2=0 8) \(\dfrac{2}{x+1}-\dfrac{3}{x+2}=\dfrac{1}{3x+3}\)
3) 4x2+5x-6=0 9) \(\dfrac{x}{x-3}=\dfrac{1}{x+2}\)
4) 4x2+5x-9=0 10) \(\dfrac{4}{2x-3}-\dfrac{7}{3x-5}=0\)
5) 5x2-18x-8=0 11) \(\dfrac{7}{x+2}+\dfrac{2}{x+3}=\dfrac{1}{x^2+5x+6}\)
6) (3x2+2x+4)2=(x2-4)2 12) \(\dfrac{4}{x-2}+\dfrac{x}{x+1}=\dfrac{x^2-2}{x^2-x-2}\)
Giúp em vs em đag cần câu tl gấp
em c.ơn trước
Giải các phương trình sau:
\(h.\dfrac{3\left(2x-1\right)}{4}-\dfrac{3x+1}{10}+1=\dfrac{2\left(3x+2\right)}{5}\)
\(i.\dfrac{\left(2x+1\right)^2}{5}-\dfrac{\left(x-1\right)^2}{3}=\dfrac{7x^2-14x-5}{15}\)
\(k.x+\dfrac{2x+\dfrac{x-1}{5}}{3}=1-\dfrac{3x-\dfrac{1-2x}{3}}{5}\)
\(i.\dfrac{\left(2x+1\right)^2}{5}-\dfrac{\left(x-1\right)^2}{3}=\dfrac{7x^2-14x-5}{15}\)
\(\Leftrightarrow\dfrac{4x^2+4x+1}{5}-\dfrac{x^2-2x+1}{3}=\dfrac{7x^2-14x-5}{15}\)
\(\Leftrightarrow\dfrac{12x^2+12x+3}{15}-\dfrac{5x^2-10x+5}{15}=\dfrac{7x^2-14x-5}{15}\)
\(\Leftrightarrow12x^2+12x+3-5x^2+10x-5=7x^2-14x-5\)
\(\Leftrightarrow36x=-3\)
\(\Leftrightarrow x=-\dfrac{1}{12}\)
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\(k.x+\dfrac{2x+\dfrac{x-1}{5}}{3}=1-\dfrac{3x-\dfrac{1-2x}{3}}{5}\)
\(\Leftrightarrow\dfrac{15x}{15}+\dfrac{10x+x-1}{15}=\dfrac{15}{15}-\dfrac{9x-1+2x}{15}\)
\(\Leftrightarrow15x+9x-1=14-7x\)
\(\Leftrightarrow31x=15\)
\(\Leftrightarrow x=\dfrac{15}{31}\)
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giải các phương trình sau
1/ \(\dfrac{x-1}{2}-\dfrac{7x+3}{15}=\dfrac{2x+1}{3}+\dfrac{3-2x}{5}\)
2/ \(\dfrac{2\left(3x+1\right)+1}{4}-5=\dfrac{2\left(3x-1\right)}{5}-\dfrac{3x+2}{10}\)
Gi ải các phương trình sau
a)x-3(2x-6)=21-(5x+3)
b)(x-2)(x+2)-(x-1)2=2(x+1)
c)\(\dfrac{9x+4}{6}\)=1-\(\dfrac{3x-5}{9}\)
d)\(\dfrac{6x+1}{x^2-7x+10}\)+\(\dfrac{5}{x-2}\)=\(\dfrac{3}{x-5}\)
a: \(x-3\left(2x-6\right)=21-\left(5x+3\right)\)
=>\(x-6x+18=21-5x-3\)
=>18=18(luôn đúng)
=>\(x\in R\)
b: \(\left(x-2\right)\left(x+2\right)-\left(x-1\right)^2=2\left(x+1\right)\)
=>\(x^2-4-x^2+2x-1=2x+2\)
=>2x-5=2x+2
=>-7=0(vô lý)
=>\(x\in\varnothing\)
c: \(\dfrac{9x+4}{6}=1-\dfrac{3x-5}{9}\)
=>\(\dfrac{3\left(9x+4\right)}{18}=\dfrac{18}{18}-\dfrac{2\left(3x-5\right)}{18}\)
=>3(9x+4)=18-2(3x-5)
=>27x+12=18-6x+10
=>27x+12=-6x+28
=>33x=16
=>\(x=\dfrac{16}{33}\left(nhận\right)\)
d: ĐKXĐ: \(x\notin\left\{2;5\right\}\)
\(\dfrac{6x+1}{x^2-7x+10}+\dfrac{5}{x-2}=\dfrac{3}{x-5}\)
=>\(\dfrac{6x+1}{\left(x-2\right)\left(x-5\right)}+\dfrac{5}{x-2}=\dfrac{3}{x-5}\)
=>\(6x+1+5\left(x-5\right)=3\left(x-2\right)\)
=>6x+1+5x-25=3x-6
=>11x-24=3x-6
=>8x=18
=>\(x=\dfrac{9}{4}\left(nhận\right)\)
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a: x−3(2x−6)=21−(5x+3)
=>x−6x+18=21−5x−3
=>18=18(luôn đúng)
=>x∈R
b: (x−2)(x+2)−(x−1)2=2(x+1)
=>x2−4−x2+2x−1=2x+2
=>2x-5=2x+2
=>-7=0(vô lý)
=>x∈∅
c: 3(9x+4)18=1818−2(3x−5)18
=>3(9x+4)=18-2(3x-5)
=>27x+12=18-6x+10
=>27x+12=-6x+28
=>33x=16
=>6x+1x2−7x+10+5x−2=3x−5
=>x=94(nhận)
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bài 1 giải các phương trình sau:h,left(dfrac{3}{4}x-1right)left(dfrac{5}{3}x+2right)0bài 2 giải các phương trình sau:b,3x-152x(x-5) m,(1-x)(5x+3)(3x-7)(x-1)d,x(x+6)-7x-420 p,left(2x-1right)^2-40f,x^3+2x^2-left(x-2right)0 r,left(2x-1right)^249h,(3x-1)(6x+1)(x+7)(3x-1) t,left(5x-3right)^2-left(4x-7right)^20j,left(2x-5right)^2-left(x+2right)^20 u,x^2-10x+160w,x...
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bài 1 giải các phương trình sau:
h,\(\left(\dfrac{3}{4}x-1\right)\left(\dfrac{5}{3}x+2\right)=0\)
bài 2 giải các phương trình sau:
b,3x-15=2x(x-5) m,(1-x)(5x+3)=(3x-7)(x-1)
d,x(x+6)-7x-42=0 p,\(\left(2x-1\right)^2-4=0\)
f,\(x^3+2x^2-\left(x-2\right)=0\) r,\(\left(2x-1\right)^2=49\)
h,(3x-1)(6x+1)=(x+7)(3x-1) t,\(\left(5x-3\right)^2-\left(4x-7\right)^2=0\)
j,\(\left(2x-5\right)^2-\left(x+2\right)^2=0\) u,\(x^2-10x+16=0\)
w,\(x^2-x-12=0\)
Bài `1:`
`h)(3/4x-1)(5/3x+2)=0`
`=>[(3/4x-1=0),(5/3x+2=0):}=>[(x=4/3),(x=-6/5):}`
______________
Bài `2:`
`b)3x-15=2x(x-5)`
`<=>3(x-5)-2x(x-5)=0`
`<=>(x-5)(3-2x)=0<=>[(x=5),(x=3/2):}`
`d)x(x+6)-7x-42=0`
`<=>x(x+6)-7(x+6)=0`
`<=>(x+6)(x-7)=0<=>[(x=-6),(x=7):}`
`f)x^3-2x^2-(x-2)=0`
`<=>x^2(x-2)-(x-2)=0`
`<=>(x-2)(x^2-1)=0<=>[(x=2),(x^2=1<=>x=+-2):}`
`h)(3x-1)(6x+1)=(x+7)(3x-1)`
`<=>18x^2+3x-6x-1=3x^2-x+21x-7`
`<=>15x^2-23x+6=0<=>15x^2-5x-18x+6=0`
`<=>(3x-1)(5x-1)=0<=>[(x=1/3),(x=1/5):}`
`j)(2x-5)^2-(x+2)^2=0`
`<=>(2x-5-x-2)(2x-5+x+2)=0`
`<=>(x-7)(3x-3)=0<=>[(x=7),(x=1):}`
`w)x^2-x-12=0`
`<=>x^2-4x+3x-12=0`
`<=>(x-4)(x+3)=0<=>[(x=4),(x=-3):}`
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`m)(1-x)(5x+3)=(3x-7)(x-1)`
`<=>(1-x)(5x+3)+(1-x)(3x-7)=0`
`<=>(1-x)(5x+3+3x-7)=0`
`<=>(1-x)(8x-4)=0<=>[(x=1),(x=1/2):}`
`p)(2x-1)^2-4=0`
`<=>(2x-1-2)(2x-1+2)=0`
`<=>(2x-3)(2x+1)=0<=>[(x=3/2),(x=-1/2):}`
`r)(2x-1)^2=49`
`<=>(2x-1-7)(2x-1+7)=0`
`<=>(2x-8)(2x+6)=0<=>[(x=4),(x=-3):}`
`t)(5x-3)^2-(4x-7)^2=0`
`<=>(5x-3-4x+7)(5x-3+4x-7)=0`
`<=>(x+4)(9x-10)=0<=>[(x=-4),(x=10/9):}`
`u)x^2-10x+16=0`
`<=>x^2-8x-2x+16=0`
`<=>(x-2)(x-8)=0<=>[(x=2),(x=8):}`
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bài 2 giải các phương trình saub,dfrac{2left(3-7xright)}{1+x}dfrac{1}{2} m,dfrac{3x-1}{x+1}dfrac{2x+1}{x-1}d,dfrac{3x-14}{x+5}dfrac{2}{3} p,dfrac{4x+7}{x-1}dfrac{12x+5}{3x+4}f,dfrac{6}{x}-1dfrac{2x-3}{3} r,dfrac{1}{x+3}+dfrac{1}{x-1}dfrac{10}{left(x+3right)left(x-1right)}h,dfrac{1}{x-2}+3dfrac{x-3}{2-x} t,dfrac{3x}{x-2}-dfrac{x}{x-5}dfrac{3x}{left(x-2right)left(5-xright)}j,dfrac{5}{3x+2}2x-1 u,dfrac{x+3}{x+1}+dfrac{x-2}{x}dfrac{2...
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bài 2 giải các phương trình sau
b,\(\dfrac{2\left(3-7x\right)}{1+x}=\dfrac{1}{2}\) m,\(\dfrac{3x-1}{x+1}=\dfrac{2x+1}{x-1}\)
d,\(\dfrac{3x-14}{x+5}=\dfrac{2}{3}\) p,\(\dfrac{4x+7}{x-1}=\dfrac{12x+5}{3x+4}\)
f,\(\dfrac{6}{x}-1=\dfrac{2x-3}{3}\) r,\(\dfrac{1}{x+3}+\dfrac{1}{x-1}=\dfrac{10}{\left(x+3\right)\left(x-1\right)}\)
h,\(\dfrac{1}{x-2}+3=\dfrac{x-3}{2-x}\) t,\(\dfrac{3x}{x-2}-\dfrac{x}{x-5}=\dfrac{3x}{\left(x-2\right)\left(5-x\right)}\)
j,\(\dfrac{5}{3x+2}=2x-1\) u,\(\dfrac{x+3}{x+1}+\dfrac{x-2}{x}=\dfrac{2\left(x^2+x-1\right)}{x\left(x+1\right)}\)
w,\(\dfrac{5x}{2x+2}+1=-\dfrac{6}{x+1}\) s, \(\dfrac{6}{x-1}-\dfrac{4}{x-3}=\dfrac{2x}{\left(x-1\right)\left(x-3\right)}\)
ơ,\(\dfrac{1}{x-1}+\dfrac{2}{x+1}=\dfrac{x}{x^2-1}\) v,\(\dfrac{x}{2\left(x-3\right)}+\dfrac{x}{2\left(x+1\right)}=\dfrac{2x}{\left(x+1\right)\left(x-3\right)}\)
z,\(\dfrac{1}{x-1}-\dfrac{3x^2}{x^3-1}=\dfrac{2x}{x^2+x+1}\) ư,\(\dfrac{x+2}{x-2}-\dfrac{-2}{x^2-2x}=\dfrac{1}{x}\)
o,\(x+\dfrac{1}{x}=x^2+\dfrac{1}{x^2}\) ô,\(1-\dfrac{1}{1-x}=\dfrac{x^2}{x^2-1}\) zz,\(\dfrac{12}{8+x^3}=1+\dfrac{1}{x+2}\)
b: =>\(4\left(3-7x\right)=x+1\)
=>12-28x=x+1
=>-29x=-11
=>x=11/29
m:=>(3x-1)(x-1)=(2x+1)(x+1)
=>3x^2-4x+1=2x^2+3x+1
=>x^2-7x=0
=>x=0 hoặcx=7
d: =>9x-42=2x+10
=>7x=52
=>x=52/7
p: \(\Leftrightarrow\left(4x+7\right)\left(3x+4\right)=\left(12x+5\right)\left(x-1\right)\)
=>12x^2+16x+21x+28=12x^2-12x+5x-5
=>37x+28=7x-5
=>30x=-33
=>x=-11/10
j: =>(2x-1)(3x+2)=5
=>6x^2+4x-3x-2-5=0
=>6x^2-x-7=0
=>6x^2-7x+6x-7=0
=>(6x-7)(x+1)=0
=>x=7/6 hoặc x=-1
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