Cách viết khác : \(\frac{16}{81}=\frac{2^4}{3^4}=\left(\frac{2}{3}\right)^4\)

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\(\left(\frac{16}{81}\right)=\left(\frac{2}{3}\right)^4\)

\(\frac{16}{81}=\left(\frac{-4}{-9}\right)^2=\left(\frac{2^2}{3^2}\right)^2=\left(\frac{\left(-2\right)^4}{\left(-3\right)^4}\right)=...\)

\(\frac{16}{81}=\frac{2^4}{3^4}=\left(\frac{2}{3}\right)^4\)

\(\frac{25}{9}=\left(\frac{5}{3}\right)^2\)

\(\dfrac{16}{81}=\left(\dfrac{2}{3}\right)^4\)

\(\dfrac{16}{81}=\left(-\dfrac{4}{9}\right)^2\)

\(\dfrac{16}{81}=\left(\dfrac{2}{3}\right)^4\)

\(\frac{16}{81}=\left(\frac{2}{3}\right)^4\)

Lời giải:

Ta có:

Lời giải :

      Ta có :

 \(\frac{16}{81}\)\(=\)\(\left(\frac{4}{9}\right)^2\)\(=\)\(\left(\frac{-4}{9}\right)^2\)\(=\)\(\left(\frac{2}{3}\right)^4\)\(=\)\(\left(\frac{-2}{3}\right)^4\)

\(\dfrac{16}{81}=\left(\dfrac{4}{9}\right)^2=\left(\dfrac{2}{3}\right)^4\)

\(\dfrac{16}{81}=\left(\dfrac{-4}{-9}\right)^2=\left(\dfrac{-2}{-3}\right)^4\)

\(\dfrac{16}{81}=\left(\dfrac{-4}{9}\right)^2=\left(\dfrac{-2}{3}\right)^4\)

\(\dfrac{16}{81}=\left(\dfrac{4}{-9}\right)^2=\left(\dfrac{2}{-3}\right)^4\)

Một số cách viết khác

\(\dfrac{16}{81}=\left(\dfrac{4}{9}\right)^2=\left(-\dfrac{4}{9}\right)^2=\left(\dfrac{2^2}{3^2}\right)^2=...\)

\(\frac{16}{81}=\left(-\frac{4}{9}\right)^2=\left(\frac{2}{3}\right)^4=\left(-\frac{2}{3}\right)^4\)

\(\frac{16}{81}=\left(\frac{-4}{9}\right)^2=\left(\frac{2}{3^{ }}\right)^4=\left(\frac{-2}{3^{ }}\right)^4\)

a)  \(\frac{6}{5}.{\left( {1,2} \right)^8} = 1,2.{(1,2)^8} = {(1,2)^{1 + 8}} = {(1,2)^9}\)

b) \({\left( {\frac{{ - 4}}{9}} \right)^7}:\frac{{16}}{{81}} = {\left( {\frac{{ - 4}}{9}} \right)^7}:{\left( {\frac{{ - 4}}{9}} \right)^2} = {\left( {\frac{{ - 4}}{9}} \right)^{7 - 2}} = {\left( {\frac{{ - 4}}{9}} \right)^5}\)

2 mũ 3 phần 3 mũ 4 nha tk mình nhé