3^x+3^x+2=270
3^x + 3^x + 2 = 270
\(\Leftrightarrow3^x\cdot10=270\)
hay x=3
3 mũ x+2 + 3 mũ x = 270
\(3^{x+2}+3^x=270\\\Rightarrow 3^x\cdot\cdot3^2+3^x=270\\\Rightarrow 3^x\cdot(3^2+1)=270\\\Rightarrow 3^x\cdot(9+1)=270\\\Rightarrow 3^x\cdot10=270\\\Rightarrow 3^x=270:10\\\Rightarrow 3^x=27\\\Rightarrow 3^x=3^3\\\Rightarrow x=3\)
tìm x
x+1/3=4/5
x-1/2=2/7
4/7×x=1/3
x:2/5=2/9
20×7:(5×x-3×5)=4
x-270=420:105
x-140:35=270
Tìm x :
x + 1/3 = 4/5
x = 4/5 - 1/3
x = 12/15 - 5/15
x = 7/15
x - 1/2 = 2/7
x = 2/7 + 1/2
x = 4/14 + 7/14
x = 11/14
4/7 × x = 1/3
x = 1/3 : 4/7
x = 1/3 × 7/4
x = 7/12
x : 2/5 = 2/9
x = 2/9 × 2/5
x = 4/45
20 × 7 : ( 5 × x - 3 × 5 ) = 4
140 : 5 × ( x - 3 ) = 4
5 × ( x - 3 ) = 140 : 4
5 × ( x - 3 ) = 35
x - 3 = 35 : 5
x - 3 = 7
x = 7 + 3
x = 10
x - 270 = 420 : 105
x - 270 = 4
x = 4 + 270
x = 274
x - 140 : 35 = 270
x - 4 = 270
x = 270 + 4
x = 274
x + 1/3 = 4/5
x = 4/5 - 1/3
x = 7/15
x - 1/2 = 2/7
x = 2/7 + 1/2
x = 11/14
4/7 * x = 1/3
x = 1/3 : 4/7
x = 7/12
x : 2/5 = 2/9
x = 2/9 * 2/5
x 4 / 45
20 * 7 : ( 5*x - 3 * 5) =4
= 140 :(5*x -3 *5) =4
5*x- 3*5 = 140 : 4
5*x - 3 * 5 = 35
5* x = 35 + 3 * 5
5 * x = 50
x = 50 : 5
x = 10
x - 270 = 402 : 105
x - 270 = 4
x = 270 + 4
x = 274
x- 140 : 35 = 270
x - 4 = 270
x = 270 + 4
x = 274
Tìm x biết: 3^(x +1) 3^(x +2)-2.3^x=270
(^ là mũ)
3^x+^2+3^x=270
x= bao nhiêu
3x+1 + 3x+2 - 2 x 3x = 270
\(3^{x+1}\) + 3\(^{x+2}\) - 2 \(\times\) 3\(^x\) = 270
3\(^x\).(3 + 32 - 2) = 270
3\(^x\).10 = 270
3\(^x\) = 270 : 10
3\(^x\) = 27
3\(^x\) = 33
\(x\) = 3
Vậy \(x\) = 3
3x+1+3x+2-2 . 3x=270
3x . 3+3x . 32-2 . 3x=270
3x . (3+9-2) =270
3x . 10 =270
3x =270 : 10 = 27 = 33
=>x=3
Giải pt
\(\frac{270}{x-12}-\frac{270}{x}=\frac{2}{3}\)
\(\Leftrightarrow-2x^2+24x+9720=0\)
\(\Leftrightarrow2x^2-24x-9720=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x_1=6+12\sqrt{34}\\x_2=6-12\sqrt{34}\end{matrix}\right.\) \(\left(tmđk\right)\)
(x – 2) x 3 – 270 : 45 = 120
\(\left(x-2\right)\times3-270:45=120\)
\(\Rightarrow3x-6-6=120\)
\(\Rightarrow3x=120+6+6\)
\(\Rightarrow3x=132\)
\(\Rightarrow x=44\)
(x−2)×3−270:45=120(x−2)×3−270:45=120
⇒3x−6−6=120⇒3x−6−6=120
⇒3x=120+6+6⇒3x=120+6+6
⇒3x=132⇒3x=132
⇒x=44
3x+2+3x=270
3^x+2 + 3^x = 270
3^x . 9 + 3^x = 270
3^x ( 1+9)= 270
3^x . 10 = 270
3^x = 27
3^x = 3^3
=> x= 3
Ta có: 3x+2+3x=270
=>3x.(32+1)=270
=>3x.10=270
=>3x=27=33
=>x=3
\(3^{x+2}+3^x=270\)
\(\Leftrightarrow3^x\times3^2+3^x=270\)
\(\Leftrightarrow3^x\times\left(3^2+1\right)=270\)
\(\Leftrightarrow\)\(3^x\times10=270\)
\(\Leftrightarrow\) \(3^x=270\div10\)
\(\Leftrightarrow\)\(3^x=27\)
\(\Leftrightarrow3^x=3^3\)
\(\Leftrightarrow x=3\)
Vay x=3