Cho tam giac abc va AH la duong cao. Goi M va N lan luot la hai Trung diem cua HB va HC. Tu M va N ve hai duong thang cung vuong goc voi BC va Lan luot cat 2 canh AB, AC tai E,F. Chung Minh
a) tu giac EMNF la hinh Chu nhat
b)tam giac AEF = tam giac HEF
Bai 1:cho tam giac vuong abc co AB/AC=3/4 va AC-AB=3cm.biet do dai duong vuong goc ke tu A xuong canh huyen BC la 7,2 cm .Tinh do dai 2 hinh chieu cua 2 canh goc vuong AB va AC tren duong thang BC
Bai 2:cho M la 1 diem trong tam giac ABC .Biet MB=DC.So sanh do dai cac doan AB va BC
Cho tam giac ABC vuong o A, duong cao AH. Ke HD vuong goc AB va HE vuong goc AC(D thuoc AD, E thuoc AC).?
Goi O la giao diem cua AH va DE
1) cm: AH=DE
2) goi P va Q lan luot la trung diem cua BH va CH. Cm tu giac DEQP la hinh thang vuong
3) CM O la truc tam rtam giac APQ . Cm Sabc=2Sdeqp
cho tam giac ABC vuong tai A ;co AB=8 cm,AC=15cm;duong cao AH
a) tinh BC,BH,AH
b) goi M,N lan luot la hinh chieu cua H len AB,AC.Tu giac AMNH la hinh gi? Tinh do dai doan MN
c)Chung minh AM*AB=AN*AC
Cho tam giac ABC vuong tai A, AH la duong cao. M la diem tren doan thang AH. Tren doan thang BM, CM lan luot lay cac diem d, E sao cho CD = CA, BE = BA. Goi N la giao diem BE va CD. Chung minh ND = NE
cho tam giac ABC vuong o A, duong cao AH. Ke HD vuong goc AB ,HE vuong goc AC (D thuoc AB , E thuoc AC ) . Goi O la giao diem cua AH va DE
a)CM:AH=DE
b)goi P va Q lan luot la trung diem cua AH,DE. CM tu giac DEQP la hinh thang vuong
c) CM :O la truc tam cua tam giac ABQ
CM: dien tich tam giac ABC bang 2 lan dien tich tu giac DEQP
cho tam giac vuong tai A va AB =6cm AC = 8cm , AH la duong cao
a, tinh BCva AH
b, ke HE vuong goc AB tai E , HF vuong goc AC tai F va goc D la trung diem cua BC .cm AD vuong goc EF
c, Goi M ,N lan luot la trung diem cua BH va CH . tu giac MNFE la hinh gi ? Vi sao ?
d, Tinh dien tich tu giac MNFE
cho tam giac ABC vuong tai A,duong cao AH 1,HB=2,HC=6 a,tinh AB, AH b,goc C va gocB cua tam giac ABC 2,goi E,Flan luot la hinh chieu cua H tren AB,AC.chung minhAB mu 3 tren AC mu 3=BE tren CF. giai cau 2 ho minh nhe canh nhanh cang tot thank ae.
1:
a: \(AH=\sqrt{2\cdot6}=2\sqrt{3}\left(cm\right)\)
\(AB=\sqrt{2\cdot8}=4\left(cm\right)\)
b: Xét ΔABC vuông tại A có sin C=AB/BC=1/2
nên góc C=30 độ
=>góc B=60 độ
2: \(\dfrac{BE}{CF}=\dfrac{BH^2}{AB}:\dfrac{CH^2}{AC}\)
\(=\dfrac{BH^2}{AB}\cdot\dfrac{AC}{CH^2}\)
\(=\left(\dfrac{BH}{CH}\right)^2\cdot\dfrac{AC}{AB}=\dfrac{AB^4}{AC^4}\cdot\dfrac{AC}{AB}=\dfrac{AB^3}{AC^3}\)
cho tam giac ABC vuong tai A ( AB < AC ) tren canh BC lat diem K / AB = BK . Goi H la TD AK . Keo dai BH cat AC ai I
a neu goc ABC = 60 . tinh so do ACB
b cm 2 tam giac ABH = KBH . tu do suy ra HK vuong vs BI
c qua K ke duong thang song song AC , cat BH va AB lan luot N va D . cm KA la tia pg IKD
d ke AM vuong goc vs BC tai M . cm 3 diem A , N .M thang hang
a) Xét \(\Delta ABC\)có \(\widehat{A}=90^o\)
\(\Rightarrow\widehat{ABC}+\widehat{ACB}=90^o\)
\(\Rightarrow60^o+\widehat{ACB}=90^o\)
\(\Rightarrow\widehat{ACB}=90^o-60^o=30^o\)
b) Xét \(\Delta ABH\)và \(\Delta KBH\)có:
AB = BK (gt)
BH là cạnh chung
AH = KH (H là trung điểm của AK)
\(\Rightarrow\Delta ABH=\Delta KBH\left(c.c.c\right)\)
\(\Rightarrow\widehat{AHB}=\widehat{KHB}\)(2 góc tương ứng)
Mà \(\widehat{AHB}+\widehat{KHB}=180^o\)(kề bù)
\(\Rightarrow\widehat{AHB}=\widehat{KHB}=\frac{180^o}{2}=90^o\)
\(\Rightarrow AK\perp BH\)hay \(HK\perp BI\)
c)
