3)tìm x biết
a) \(\dfrac{x}{7}=\dfrac{18}{14}\)
b) \(6:x=1\dfrac{3}{4}:5\)
c) 5,7:0,35= (-x) :0,45
Tìm x trong các tỉ lệ thức sau:
a)\(\dfrac{x}{7}=\dfrac{18}{14}\) b)6:x =\(1\dfrac{3}{4}\):5 c)5,7:0,35=(-x):0,45
a)\(\dfrac{x}{7}=\dfrac{18}{14}\)
\(\Rightarrow x=\dfrac{7.18}{14}=9\)
b)\(6:x=1\dfrac{3}{4}\)
\(\Leftrightarrow\dfrac{6}{x}=\dfrac{7}{4}\)
\(\Rightarrow x=\dfrac{6.4}{7}=\dfrac{24}{7}\)
c)5,7:0,35=(-x):0,45
\(\Leftrightarrow\dfrac{114}{7}=\dfrac{-x}{0,45}\)
\(\Rightarrow\left(-x\right)=\dfrac{114.0,45}{7}=\dfrac{-513}{70}\)
Tìm 2 số x và y biết
a) \(\dfrac{x}{3}=\dfrac{y}{7}và\) x+y=20
b) \(\dfrac{x}{5}=\dfrac{y}{2}\) và x-y=6
Tìm x biết:
a) \(\dfrac{x}{7}=\dfrac{18}{14}\)
b) 6:x= \(1\dfrac{3}{4}:5\)
c) 5,7:0,35=(-x):0,45
a)\(\dfrac{x}{3}=\dfrac{y}{7}=\dfrac{x+y}{3+7}=\dfrac{20}{10}=2\)
\(\dfrac{x}{3}=2\Rightarrow x=6\)
\(\dfrac{y}{7}=2\Rightarrow y=14\)
b)\(\dfrac{x}{5}=\dfrac{y}{2}=\dfrac{x-y}{5-2}=\dfrac{6}{3}=2\)
\(\dfrac{x}{5}=2\Rightarrow x=10\)
\(\dfrac{y}{2}=2\Rightarrow y=4\)
tìm x trong tỉ lệ thức sau :
a, \(\dfrac{x}{7}\)= \(\dfrac{18}{14}\)
b, 6 : x = 1\(\dfrac{3}{4}\) : 5
c, 5,7 : 0,35 = -x : 0,45
\(a,x=\dfrac{18.7}{14}\)
\(x=\dfrac{8}{2}=4\)
\(b,\)\(x=6.5:1\dfrac{3}{4}\)
\(x=30:\dfrac{7}{4}\)
\(x=30.\dfrac{4}{7}=\dfrac{120}{7}\)
\(c,-x=\)\(\dfrac{5,7.0,45}{0,35}\)
\(-x=\)\(\dfrac{2,565}{0,35}\)
\(x=\dfrac{-2,565}{0,35}\)
a)\(\dfrac{x}{7}=\dfrac{18}{14}\) b) 6:x=\(1\dfrac{3}{4}\):5 c) 5,7 : 0,35= -x: 0,45
\(\Rightarrow\) x.14= 18.7 \(\Rightarrow\) 6:x=\(\dfrac{7}{20}\) \(\Rightarrow\)\(\dfrac{114}{7}=\dfrac{-x}{0,45}\)
\(\Rightarrow\)x.14=126 \(\Rightarrow\)x=\(\dfrac{10}{21}\) \(\Rightarrow53,1=\left(-x\right).7\)
\(\Rightarrow\)x=9 \(\Rightarrow x=7,3\)
CHÚC BẠN HỌC TỐT
a, \(\dfrac{x}{7}\)=\(\dfrac{18}{14}\)
\(x.14=7.18\)
\(x.14=126\)
\(\Rightarrow x=9\)
b,\(6:x=1^3_4:5\)
\(6:x=\dfrac{7}{20}\)
\(x=\dfrac{7}{120}\)
Bài 1:
a,\(\dfrac{x}{7}\)=\(\dfrac{18}{14}\) b, 6:x=1\(\dfrac{3}{4}\):5 c,5,7:0,35=(-x):0,45
Bài 2:tìm các số x,y,z,biết \(\dfrac{x}{2}\)=\(\dfrac{y}{4}\)=\(\dfrac{z}{6}\)và x-y+z=8
Giúp mình với nhé!Cần Gấp ♥
Câu 2:
Áp dụng tính chất của dãy tỉ số bằng nhau, ta được:
\(\dfrac{x}{2}=\dfrac{y}{4}=\dfrac{z}{6}=\dfrac{x-y+z}{2-4+6}=\dfrac{8}{8}=1\)
Do đó: x=2; y=4; z=6
Tìm x trong các tỉ lệ thức sau:
a) \(\frac{x}{7}\)= \(\frac{18}{14}\)
b) 6 : x = \(1\frac{3}{4}\) : 5
c) 5,7 : 0,35 = (-x) : 0,45
a) \(\frac{x}{7}=\frac{18}{14}\)
\(\frac{x}{7}=\frac{9}{7}\)
\(\Rightarrow x=9\)
b) \(6:x=1\frac{3}{4}:5\)
\(6:x=\frac{7}{4}.\frac{1}{5}\)
\(6:x=\frac{7}{20}\)
\(x=6:\frac{7}{20}\)
\(x=\frac{120}{7}\)
vay \(x=\frac{120}{7}\)
c) \(\frac{5,7}{0,35}=\frac{-x}{0,45}\)
\(\Rightarrow-0,35x=5,7.0,45\)
\(\Rightarrow-0,35x=2,565\)
\(\Rightarrow x=\frac{-2,565}{0,35}\)
\(\Rightarrow x=\frac{-513}{70}\)
vay \(x=\frac{-513}{70}\)
Tìm x, biết:
a) \(\dfrac{2}{5}\) + \(\dfrac{3}{4}\): x = \(\dfrac{-1}{2}\)
b) \(\dfrac{5}{7}\) - \(\dfrac{2}{3}\) . x = \(\dfrac{4}{5}\)
c) \(\dfrac{1}{2}\) x + \(\dfrac{2}{3}\) x = \(\dfrac{-2}{3}\)
d) \(\dfrac{4}{7}\)x - x= \(\dfrac{-9}{14}\)
a, 2/5 + 3/4 : x = -1/2
3/4 : x = -1/2 - 2/5
3/4 : x = -9/10
x = 3/4 : -9/10
x = -5/6
b, 5/7 - 2/3 . x = 4/5
2/3 . x = 4/5 + 5/7
2/3 . x = 53/35
x = 53/35 : 2/3
x = 159/70
c và d mình làm dược nhưng ko ghi được cái suy ra
Tìm số nguyên x, y biết:
\(a,\dfrac{x}{5}=\dfrac{-18}{10}\) b, \(\dfrac{6}{x-1}=\)\(\dfrac{-3}{7}\) c, \(\dfrac{y-3}{12}\)=\(\dfrac{3}{y-3}\) d, \(\dfrac{x}{25}\)=\(\dfrac{-5}{x^2}\)
\(a,\dfrac{x}{5}=\dfrac{-18}{10}\\ \Rightarrow x=-\dfrac{18}{10}.5\\ \Rightarrow x=-9\\ b,\dfrac{6}{x-1}=\dfrac{-3}{7}\\ \Rightarrow6.7=-3\left(x-1\right)\\ \Rightarrow42=-3x+3\\ \Rightarrow42+3x-3=0\\ \Rightarrow3x+39=0\\ \Rightarrow3x=-39\\ \Rightarrow x=-13\\ c,\dfrac{y-3}{12}=\dfrac{3}{y-3}\\ \Rightarrow\left(y-3\right)^2=36\\ \Rightarrow\left[{}\begin{matrix}y-2=6\\y-2=-6\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}y=8\\y=-4\end{matrix}\right.\)
\(d,\dfrac{x}{25}=\dfrac{-5}{x^2}\\ \Rightarrow x^3=-125\\ \Rightarrow x^3=\left(-5\right)^3\\ \Rightarrow x=-5\)
Bài 1:tìm x,biết
a) \(\frac{x}{7}\)=\(\frac{18}{14}\)b) 6:x=\(1\frac{3}{4}\):5 c) 5,7:0,35(-x):0,45
Bài 2:tìm các số x,y,z biết \(\frac{x}{2}\)=\(\frac{y}{4}\)=\(\frac{z}{6}\)và x-y+z=8
Giúp Mình nhé! Cần Gấp♥
Bài 1 :
a) \(\frac{x}{7}=\frac{18}{14}\)
=> x.14 = 7.18
x.14 = 126
x = 126:14
x = 9
b) \(\frac{6}{x}=\frac{7}{4}\)
=> \(x=\frac{6.4}{7}=\frac{24}{7}\)
c) Theo mình đề thế này mới đúng \(\frac{5,7}{0,35}=\frac{\left(-x\right)}{0,45}\)
=> 5,7.0,45 = 0,35.(-x)
2,565 = 0,35.(-x)
(-x) = 2,565:0,35
(-x) = 513/70
=> -x = -513/70
x = 513/70
Bài 2 : Áp dụng tính chất dãy tỉ số bằng nhau ta có :
\(\frac{x}{2}=\frac{y}{4}=\frac{z}{6}=\frac{x-y+z}{2-4+6}=\frac{8}{4}=2\)
\(\frac{x}{2}=2\)
x = 2.2
x = 4
\(\frac{y}{4}=2\)
y = 2.4
y = 8
\(\frac{z}{6}\) = 2
z = 2.6
z = 12
Vậy x=4 ; y=8 và z=12
\(\frac{x}{7}=\frac{18}{14}\Rightarrow x=18\cdot7:17=9\)
1. tìm các số chưa biết :
a) \(\dfrac{4}{3}\)= \(\dfrac{8}{x}\)=\(\dfrac{-y}{21}\)=\(\dfrac{-40}{z}\)=\(\dfrac{16}{t}\)=\(\dfrac{y}{111}\)
b) \(\dfrac{-7}{6}=\dfrac{x}{18}=\dfrac{-98}{y}=\dfrac{14}{y}=\dfrac{-14}{z}=\dfrac{t}{102}=\dfrac{4}{-78}\)
2. tìm x biết :
a) \(\dfrac{2}{x}=\dfrac{x}{8}\)
b) \(\dfrac{2x-9}{240}=\dfrac{39}{80}\)
c) \(\dfrac{x-1}{9}=\dfrac{8}{3}\)
mn giúp mk nha :>
Bài 2:
\(a,\dfrac{2}{x}=\dfrac{x}{8}\\ \Rightarrow x.x=8.2\\ \Rightarrow x^2=16\\ \Rightarrow x=\pm4\)
\(b,\dfrac{2x-9}{240}=\dfrac{39}{80}\\ \Rightarrow80\left(2x-9\right)=240.39\\ \Rightarrow160x-720=9360\\ \Rightarrow160x=10080\\ \Rightarrow x=63\)
\(c,\dfrac{x-1}{9}=\dfrac{8}{3}\\ \Rightarrow3\left(x-1\right)=8.9\\ \Rightarrow3\left(x-1\right)=72\\ \Rightarrow x-1=24\\ \Rightarrow x=25\)