a) \(\dfrac{x}{4}=\dfrac{16}{128}\Rightarrow x=\dfrac{4.16}{128}=\dfrac{1}{2}=0,5\)

b)\(1\dfrac{5}{6}=\dfrac{-x}{5}\\ \Leftrightarrow\dfrac{11}{6}=\dfrac{-x}{5}\Rightarrow-x=\dfrac{5.11}{6}=\dfrac{55}{6}\Rightarrow x=-\dfrac{55}{6}\)

c) \(\dfrac{4,25}{8}=\dfrac{-3,5}{x}\Rightarrow x=\dfrac{8.\left(-3,5\right)}{4,25}=-\dfrac{112}{17}\)

a,X/4=16/28

=»x/4=4/7

=4/7.4

=7

b,1/5/6=-x/5

-x/5=11/6

X=11/6.5

X=55/6

\(a,\dfrac{x}{4}=\dfrac{16}{128}\\ \Leftrightarrow128x=4.16\\ \Leftrightarrow128x=64\\ \Leftrightarrow x=\dfrac{1}{2}\)

Vậy...

\(b,1\dfrac{5}{6}=\dfrac{-x}{5}\\ \Leftrightarrow-6x=25\\ \Leftrightarrow x=-\dfrac{25}{6}\)

Vậy...

\(c,4,25:8=-3,5:x\\ \Leftrightarrow4,25x=-3,5.8\\ \Leftrightarrow x=-28:4,25\\ \Leftrightarrow x=-\dfrac{112}{17}\)

Vậy...

\(a.\)

\(\dfrac{x}{4}=\dfrac{16}{128}\)

\(\Rightarrow x=\dfrac{16.4}{128}=\dfrac{1}{2}\)

\(b.\)

\(1\dfrac{5}{6}=-\dfrac{x}{5}\)

\(\Rightarrow\dfrac{11}{6}=-\dfrac{x}{5}\)

\(\Rightarrow x=\dfrac{11.\left(-5\right)}{6}=-\dfrac{55}{6}\)

\(c.\)

\(4,25:8=-3,5:x\)

\(\Rightarrow\dfrac{4,25}{8}=\dfrac{-3,5}{x}\)

\(\Rightarrow x=\dfrac{-3,5.8}{4,25}=-\dfrac{112}{17}\)

\(a)\dfrac{x}{4}=\dfrac{16}{128}\)

\(\Rightarrow\dfrac{16}{128}.4=\dfrac{1}{2}\)

\(b)1\dfrac{5}{6}=\dfrac{-x}{5}\)

\(\Rightarrow x=\dfrac{11}{6}.\left(-5\right)=\dfrac{-55}{6}\)

\(c)4,25:8=-3,5:x\)

\(\Rightarrow\dfrac{4,25}{8}=\dfrac{-3,5}{x}\)

\(\Rightarrow x=\dfrac{-3,5.8}{4,25}=\dfrac{-112}{17}\)

Chúc bạn học tốt!

a)\(\dfrac{x}{4}=\dfrac{16}{128}\)

\(\Leftrightarrow\dfrac{x}{4}=\dfrac{1}{8}\)

\(\Rightarrow x=\dfrac{1.4}{8}=\dfrac{1}{2}\)

b)\(1\dfrac{5}{6}=\dfrac{-x}{5}\)

\(\Leftrightarrow\dfrac{11}{6}=\dfrac{-x}{5}\)

\(\Rightarrow-x=\dfrac{11.5}{6}=\dfrac{-55}{6}\)

c)\(4,25:8=-3,5:x\)

\(\Leftrightarrow\dfrac{17}{32}=\dfrac{-3,5}{x}\)

\(\Rightarrow x=\dfrac{\left(-3,5\right).32}{17}=-\dfrac{112}{17}\)

Tìm x

a)\(\dfrac{x}{4}\)=\(\dfrac{16}{128}\)

\(\Rightarrow\)x.128=16.4

x.128=64

x=64:128

x=\(\dfrac{1}{2}\)

Vậy x=\(\dfrac{1}{2}\)

b)\(1\dfrac{5}{6}\)=\(\dfrac{-x}{5}\)

\(\dfrac{11}{6}\)=\(\dfrac{-x}{5}\)

-x:5=\(\dfrac{11}{6}\)

-x=\(\dfrac{11}{6}\).5

-x=\(\dfrac{55}{6}\)

\(\Rightarrow\)x=\(\dfrac{-55}{6}\)

Vậy x=\(\dfrac{-55}{6}\)

c)4,25:8 = -3,5:x

-3,5:x=\(\dfrac{17}{4}\)

x=-3,5:\(\dfrac{17}{4}\)

x=\(\dfrac{14}{17}\)

Vậy x=\(\dfrac{14}{17}\)

a, Ta có : \(\dfrac{x}{4}\)= \(\dfrac{16}{128}\)

\(\Rightarrow\)4 . 16 = x . 128

\(\Rightarrow\) x = (4 . 16 ) : 128

\(\Rightarrow\) x = \(\dfrac{1}{2}\)

b, Ta có : 1\(\dfrac{5}{6}\) = \(\dfrac{-x}{5}\)

\(\Leftrightarrow\dfrac{11}{6}\) = \(\dfrac{-x}{5}\)

\(\Rightarrow\)11 . 5 = 6 . ( \(-x\) )

\(\Rightarrow\)\(-x\) = (11. 5) : 6

\(\Rightarrow\) \(-x\) = \(\dfrac{-55}{6}\)

\(\Rightarrow\) \(x\) = \(\dfrac{55}{6}\)

c,Ta có : 4 , 25 : 8 = \(-3,5\) : x

\(\Rightarrow\) \(\dfrac{17}{32}\) = \(\dfrac{-3,5}{x}\)

\(\Rightarrow\) 17 . x = \(-3,5\) . 32

\(\Rightarrow\) x = ( \(-3,5\) . 32 ): 17

\(\Rightarrow\) x = \(\dfrac{-112}{17}\)

a) \(\left|x\right|=3,5\)

\(\Rightarrow\left[{}\begin{matrix}x=3,5\\x=-3,5\end{matrix}\right.\)

b) \(\left|1-x\right|+0,73=3\)

\(\Rightarrow\left|1-x\right|=3-0,73\)

\(\Rightarrow\left|1-x\right|=2,27\)

\(\Rightarrow\left[{}\begin{matrix}1-x=2,27\\1-x=-2,27\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=-1,27\\x=3,27\end{matrix}\right.\)

c) \(\dfrac{-5}{8}+x=\dfrac{4}{9}\)

\(\Rightarrow x=\dfrac{4}{9}-\left(\dfrac{-5}{8}\right)\)

\(\Rightarrow x=\dfrac{77}{72}\)

1)

a) \(1\dfrac{5}{6}=\dfrac{-x}{5}\)

\(\Rightarrow\dfrac{11}{6}=\dfrac{-x}{5}\)

\(\Rightarrow-x=\dfrac{5.11}{6}=\dfrac{55}{6}\)

\(\Rightarrow x=-\dfrac{55}{6}\)

b) 4,25 : 8 = -3,5 : x

\(\dfrac{4,25}{8}=\dfrac{-3,5}{x}\)

\(x=\dfrac{-3,5.8}{4,25}\)

\(x=\dfrac{-28}{4,25}\)

2.

\(-\dfrac{12}{1,6}=\dfrac{55}{-7\dfrac{1}{3}}\)

\(\Rightarrow-\dfrac{12}{1,6}=\dfrac{55}{-\dfrac{22}{3}}\)

Ta có thể lặp đc các tỉ lệ thức sau:

\(-\dfrac{12}{1,6}=\dfrac{55}{-\dfrac{22}{3}}\)

\(\dfrac{-\dfrac{22}{3}}{1,6}=\dfrac{55}{-12}\)

\(-\dfrac{12}{55}=\dfrac{1,6}{-\dfrac{22}{3}}\)

\(\dfrac{1,6}{-12}=\dfrac{-\dfrac{22}{3}}{55}\)

a)4/5+x=2/3

x=2/3-4/5

x=-2/15

b)-5/6-x=2/3

x=-5/6-2/3

x=-3/2

c)1/2x+3/4=-3/10

1/2x=-3/10-3/4

1/2x=-21/20

x=-21/20:1/2

x=-21/10

d)x/3-1/2=1/5

x/3=1/5+1/2

x/3=7/10

10x/30=21/30

10x=21

x=21:10

x=21/10

a: =>x-3/4=1/6-1/2=1/6-3/6=-2/6=-1/3

=>x=-1/3+3/4=-4/12+9/12=5/12

b: =>x(1/2-5/6)=7/2

=>-1/3x=7/2

hay x=-21/2

c: (4-x)(3x+5)=0

=>4-x=0 hoặc 3x+5=0

=>x=4 hoặc x=-5/3

d: x/16=50/32

=>x/16=25/16

hay x=25

e: =>2x-3=-1/4-3/2=-1/4-6/4=-7/4

=>2x=-7/4+3=5/4

hay x=5/8

a) \(\frac{x}{4}=\frac{16}{128}\)

\(x.128=4.16\)

\(x.128=64\)

\(x=64:128\)

\(x=\frac{1}{2}\)

Vậy \(x=\frac{1}{2}\)

b) \(\frac{11}{6}=\frac{-x}{5}\)

\(11.5=\left(-x\right).6\)

\(55=\left(-x\right).6\)

\(-x=55:6\)

\(-x=\frac{55}{6}\)

\(\Rightarrow x=-\frac{55}{6}\)

Vậy \(x=-\frac{55}{6}\)

c) \(4,25:8=-3,5:x\)

\(\frac{17}{32}=-3,5:x\)

\(x=\frac{-35}{10}:\frac{17}{32}\)

\(x=-6\frac{10}{17}\)

Vậy \(x=-6\frac{10}{17}\)

\(a.\)

\(\frac{x}{4}=\frac{16}{128}\)

\(\Rightarrow x=\frac{16.4}{128}\)

\(\Rightarrow x=\frac{1}{2}\)

Vậy :       \(x=\frac{1}{2}\)

\(b.\)

\(\frac{11}{6}=\frac{-x}{5}\)

\(\Rightarrow x=\frac{11.5}{-6}\)

\(\Rightarrow x=-\frac{55}{6}\)

Vậy :        \(x=-\frac{55}{6}\)

\(c.\)

\(\frac{4,25}{8}=\frac{-3,5}{x}\)

\(\Rightarrow x=\frac{-3,5.8}{4,25}\)

\(\Rightarrow x=-6\frac{10}{7}\)

Vậy :         \(x=-6\frac{10}{7}\)