Question

Tìm x: biết 

a, x/4= 16/128

b,  11/6= -x/5

c,  4,25:8= -3,5:x

Answer 1

a) \(\frac{x}{4}=\frac{16}{128}\)

\(x.128=4.16\)

\(x.128=64\)

\(x=64:128\)

\(x=\frac{1}{2}\)

Vậy \(x=\frac{1}{2}\)

b) \(\frac{11}{6}=\frac{-x}{5}\)

\(11.5=\left(-x\right).6\)

\(55=\left(-x\right).6\)

\(-x=55:6\)

\(-x=\frac{55}{6}\)

\(\Rightarrow x=-\frac{55}{6}\)

Vậy \(x=-\frac{55}{6}\)

c) \(4,25:8=-3,5:x\)

\(\frac{17}{32}=-3,5:x\)

\(x=\frac{-35}{10}:\frac{17}{32}\)

\(x=-6\frac{10}{17}\)

Vậy \(x=-6\frac{10}{17}\)

 

Answer 2

\(a.\)

\(\frac{x}{4}=\frac{16}{128}\)

\(\Rightarrow x=\frac{16.4}{128}\)

\(\Rightarrow x=\frac{1}{2}\)

Vậy :       \(x=\frac{1}{2}\)

\(b.\)

\(\frac{11}{6}=\frac{-x}{5}\)

\(\Rightarrow x=\frac{11.5}{-6}\)

\(\Rightarrow x=-\frac{55}{6}\)

Vậy :        \(x=-\frac{55}{6}\)

\(c.\)

\(\frac{4,25}{8}=\frac{-3,5}{x}\)

\(\Rightarrow x=\frac{-3,5.8}{4,25}\)

\(\Rightarrow x=-6\frac{10}{7}\)

Vậy :         \(x=-6\frac{10}{7}\)