\(8x^6-27y^3\)

\(=\left(2x^2\right)^3-\left(3y\right)^3\)

\(=\left(2x^2-3y\right)\left(4x^2+6x^2y+9y^2\right)\)

1, \(x^3+3^3=\left(x+3\right)\left(x^2-3x+9\right)\)

2, đề sai 

3, \(x^3+8=\left(x+2\right)\left(x^2-2x+4\right)\)

4, \(x^3-64=\left(x-4\right)\left(x^2+4x+16\right)\)

5, \(1000-y^3=\left(10-y\right)=\left(100+10y+y^2\right)\)

tương tự ... 

8, \(8x^3+27y^3=\left(2x+3y\right)\left(4x^2-6xy+9y^2\right)\)

=>3/4 x (8/9+2/3)=3/4 x 2/9 =6/36=1/6

Giúp mình nhé 

\(\dfrac{3}{4}\times\dfrac{8}{9}+\dfrac{3}{4}\times\dfrac{2}{3}\)

=\(\dfrac{3}{4}\times\left(\dfrac{8}{9}+\dfrac{2}{3}\right)\)

=\(\dfrac{3}{4}\times\dfrac{14}{9}=\dfrac{7}{6}\)

1) \(\dfrac{1}{27}+a^3=\left(\dfrac{1}{3}+a\right)\left(\dfrac{1}{9}-\dfrac{a}{3}+a^2\right)\)

2) \(=\left(2x+3y\right)\left(4x^2-6xy+9y^2\right)\)

3) \(=\left(\dfrac{1}{2}x+2y\right)\left(\dfrac{1}{4}x-xy+4y^2\right)\)

4) \(=\left(x^2+1\right)\left(x^4-x^2+1\right)\)

5) \(=\left(x^3+1\right)\left(x^6-x^3+1\right)\)

6) \(=\left(x-4\right)\left(x^2+4x+16\right)\)

7) \(=\left(x-5\right)\left(x^2+5x+25\right)\)

8) \(=\left(2x^2-3y\right)\left(4x^4+6x^2y+9y^2\right)\)

9) \(=\left(\dfrac{1}{4}x^2-5y\right)\left(\dfrac{1}{16}x^4+\dfrac{5}{4}x^2y+25y^2\right)\)

10) \(=\left(\dfrac{1}{2}x-2\right)\left(\dfrac{1}{4}x^2+x+4\right)\)

11) \(=\left(x+2\right)^3\)

12) \(=\left(x+3\right)^3\)

a) (1 - 2x) (2x + 1) = 1 - 4x² __ hằng đẳng thức số 3 (A + B) (A - B) = A² - B² (ở đây A = 1 , B = 2x)

câu b) có sai đề ko bn

câu b đúng đề mak bạn .

\(\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times\dfrac{4}{5}\times100\)

\(=\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times\dfrac{4}{5}\times\dfrac{100}{1}\)

\(=\dfrac{1\times2\times3\times4\times100}{2\times3\times4\times5\times1}\)

\(=\dfrac{100}{5}\)

\(=20\)

a²- 9 = a²-3²= (a-3).(a+3)

a²- 9 = a²-3²= (a-3).(a+3)

áp dụng hằng đẳng thức là đc

\(a^2-9=\left(a-3\right)\left(a+3\right)\)

a)(x+3y)(x²-3xy+9y²)=x³+27y³

b)(2x-3y)(4x²+6xy+9y²)=8x³-27y³