\(2x-7\sqrt{x}+3\\ =2x-6\sqrt{x}-\sqrt{x}+3\\ =\left(2x-6\sqrt{x}\right)-\left(\sqrt{x}-3\right)\\ =2\sqrt{x}\left(\sqrt{x}-3\right)-\left(\sqrt{x}-3\right)\\ =\left(\sqrt{x}-3\right)\left(2\sqrt{x}-1\right)\)

=2x-6căn x-căn x+3

=2*căn x*(căn x-3)-(căn x-3)

=(căn x-3)(2*căn x-1)

\(2x-7\sqrt{x}+3\)

\(=\left(2x-\sqrt{x}\right)-\left(6\sqrt{x}-3\right)\)

\(=\sqrt{x}\left(2\sqrt{x}-1\right)-3\left(2\sqrt{x}-1\right)\)

\(=\left(\sqrt{x}-3\right)\left(2\sqrt{x}-1\right)\)

\(x^3+2x^2+3x\)

\(=x\left(x^2+2x+3\right)\)

#Ayumu

\(a,2x^2+3x-2xy-3y\)

\(=x\left(2x+3\right)-y\left(2x+3\right)\)

\(=\left(2x+3\right)\left(x-y\right)\)

\(b,x^3-4x^2+4x\)

\(=x\left(x^2-4x+4\right)\)

\(=x\left(x-2\right)^2\)

#Urushi

a) \(2x^2+3x-2xy-3y\)

\(\text{=}2x\left(x-y\right)+3\left(x-y\right)\)

\(\text{=}\left(2x+3\right)\left(x-y\right)\)

b) \(x^3-4x^2+4x\)

\(\text{=}x\left(x^2-4x+4\right)\)

\(\text{=}x\left(x-2\right)^2\)

8: \(=\left(x-2y\right)\cdot x\cdot\left(x+3\right)\)

9: \(=\left(5x+2\right)\left(x-3\right)-x\left(x-3\right)\)

\(=\left(x-3\right)\left(4x+2\right)\)

=2(2x+1)(x-3)

3: \(=2\left(x+2\right)\left(25x-15-x\right)\)

\(=2\left(x+2\right)\left(24x-15\right)\)

=6(x+2)(8x-5)

cái này trong sách í

\(2ab^2-a^2b-b^3=b^2\left(2a-a^2-b\right)\)

\(2ab^2-a^2b-b^3\)

\(=-b\left(a^2-2ab+b^2\right)\)

\(=-b\left(a-b\right)^2\)

-(2ab² - a²b - b³)

= b(-2ab + a² + b²)

= b(a² - 2ab + b²)

= b(a - b)²

\(x^3-4x\)

\(=x\cdot\left(x^2-4\right)\)

\(=x\cdot\left(x^2-2^2\right)\)

\(=x\left(x+2\right)\left(x-2\right)\)

\(x^3-4x\)

\(=x\left(x^2-4\right)\)

\(=x\left(x-2\right)\left(x+2\right)\)

#Ayumu

a) x.(x-1) - 2(1-x) =0

=> x.(x-1) + 2(x-1) =0

=> (x-1)(x+2) =0

b) (x-3)^3 + (3-x) =0

=> (x-3)^3 - (x-3) =0

=> (x-3)​​[(x-3)^2 - 1 ] =0

=> (x-3)(x-3-1)(x-3+1) =0

=> (x-3)(x-4)(x-2) =0