Tính hợp lí giá trị các biểu thức sau
I = \(10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)
giúp miình ới
1.
b) \(B=8\dfrac{1}{5}.\left(11\dfrac{94}{1591}-6\dfrac{38}{1517}\right):8\dfrac{11}{43}\)
c) \(C=10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)
b: \(=8.2\left(11+\dfrac{94}{1591}-6-\dfrac{38}{1517}\right):\left(8+\dfrac{11}{43}\right)\)
\(=\dfrac{41}{5}\cdot\left(5+\dfrac{60}{1763}\right):\dfrac{355}{43}\)
\(=\dfrac{41}{5}\cdot\dfrac{8875}{1763}\cdot\dfrac{43}{355}\)
\(=5\)
c: \(=10101\cdot\left(\dfrac{10+5}{222222}-\dfrac{4}{111111}\right)\)
\(=10101\cdot\dfrac{7}{222222}=\dfrac{7}{22}\)
TÍNH
\(10101.(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37})\)
\(10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3\cdot7\cdot11\cdot13\cdot37}\right)\)=\(10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)
= \(10101\cdot\left(\dfrac{5}{111111}-\dfrac{4}{111111}+\dfrac{5}{222222}\right)\)
= \(10101\cdot\left(\dfrac{1}{111111}+\dfrac{5}{222222}\right)\)
= \(10101\cdot\left(\dfrac{2}{222222}+\dfrac{5}{222222}\right)\)
= \(10101\cdot\dfrac{7}{222222}\)
= \(\dfrac{10101\cdot7}{222222}=\dfrac{10101\cdot7}{10101\cdot22}=\dfrac{7}{22}\)
10101.(\(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\))
= 10101.(\(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\))
= 10101.(\(\dfrac{1}{111111}+\dfrac{5}{222222}\))
= 10101. \(\dfrac{7}{222222}\)
= \(\dfrac{10101.7}{222222}\)= \(\dfrac{70707}{22222}\)=\(\dfrac{7}{22}\)
Chúc pạn hok tốt!!!!!!!
Tính nhanh:
10101.( \(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\))
\(10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)
\(=10101.\dfrac{5}{111111}+10101.\dfrac{5}{222222}-10101.\dfrac{4}{3.7.11.13.37}\)
\(=\dfrac{5}{11}+\dfrac{5}{22}-\dfrac{4}{11}\)
\(=\dfrac{7}{22}\)
Tính nhanh:
\(M=\dfrac{120-\dfrac{1}{2}.40.5.\dfrac{1}{5}.20.\dfrac{1}{4}-20}{1+5+9+...+33+37+41}\)
\(N=10101.\left(\dfrac{6}{111111}+\dfrac{6}{222222}-\dfrac{7}{3.7.11.13.37}\right)\)
\(M=\dfrac{120-\dfrac{1}{2}.40.5.\dfrac{1}{5}.20.\dfrac{1}{4}-20}{1+5+....+41}\\ =\dfrac{120-20.5-20}{1+5+...+41}\\ =\dfrac{0}{1+5+...+41}\\ =0\)
\(N=10101\left(\dfrac{6}{3.7.11.13.37}+\dfrac{6}{2.3.7.11.13.37}-\dfrac{7}{3.7.11.13.37}\right)\\ =10101\left(-\dfrac{2}{2.3.7.11.13.37}+\dfrac{6}{2.3.7.11.13.37}\right)\\ =3.7.13.37\left(\dfrac{4}{2.3.7.11.13.37}\right)=\dfrac{4}{2.11}=\dfrac{2}{11}\)
I= \(10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)
B=\(71\dfrac{38}{45}-\left(43\dfrac{8}{45}-1\dfrac{17}{57}\right)\)
D= \(\left(19\dfrac{5}{8}:\dfrac{7}{12}-13\dfrac{1}{4}:\dfrac{7}{12}\right).\dfrac{4}{5}\)
F= \(\left(9.75.21\dfrac{3}{7}+\dfrac{39}{4}.18\dfrac{4}{7}\right).\dfrac{15}{78}\)
Giups mk vs!!!!!!!!
Trời ơi cái đề bài !!!
Thoy thì làm từng câu vậy
a) \(I=10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)
\(I=10101.\left(\dfrac{10}{222222}+\dfrac{5}{222222}-\dfrac{8}{222222}\right)\)
\(I=10101.\left(\dfrac{15}{222222}-\dfrac{8}{222222}\right)\)
\(I=10101.\dfrac{7}{222222}\)
\(I=\dfrac{7}{22}\)
1.
a) \(A=10101\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)\(A=\dfrac{10101.5}{10101.11}+\dfrac{10101.5}{10101.22}-\dfrac{10101.4}{10101.11}\)
\(A=\dfrac{5}{11}+\dfrac{5}{22}-\dfrac{4}{11}=\dfrac{7}{22}\)
\(B=\dfrac{2698}{45}-\left(\dfrac{344}{45}-\dfrac{17}{57}\right)\)
(Áp dụng tính chất a - (b - c) = a-b-c)
\(B=\dfrac{2698}{45}-\dfrac{344}{45}-\dfrac{17}{57}\)
\(B=\dfrac{2354}{45}-\dfrac{17}{57}\)
\(B=\dfrac{44726}{855}-\dfrac{255}{855}\)
\(B=\dfrac{44471}{855}\)
\(I=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
B= 10101.\(\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(B=10101\cdot\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)
\(=10101\cdot\left(\dfrac{2}{222222}+\dfrac{5}{222222}\right)\)
\(=10101\cdot\dfrac{1}{31746}=\dfrac{7}{22}\)
\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{3.7.11.13.37}\right)\)
\(A=10101.\left(\frac{5}{111111}+\frac{5}{222222}-\frac{4}{111111}\right)\)
\(A=10101.\left(\frac{10}{222222}+\frac{5}{222222}-\frac{8}{222222}\right)\)
\(A=10101.\left(\frac{7}{222222}\right)\)
\(A=\frac{70707}{222222}\)
\(A=\frac{7}{22}\)
Vậy A = \(\frac{7}{22}\)
Chúc bạn học tốt!