I= \(10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)
B=\(71\dfrac{38}{45}-\left(43\dfrac{8}{45}-1\dfrac{17}{57}\right)\)
D= \(\left(19\dfrac{5}{8}:\dfrac{7}{12}-13\dfrac{1}{4}:\dfrac{7}{12}\right).\dfrac{4}{5}\)
F= \(\left(9.75.21\dfrac{3}{7}+\dfrac{39}{4}.18\dfrac{4}{7}\right).\dfrac{15}{78}\)
Giups mk vs!!!!!!!!
Trời ơi cái đề bài !!!
Thoy thì làm từng câu vậy
a) \(I=10101.\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{111111}\right)\)
\(I=10101.\left(\dfrac{10}{222222}+\dfrac{5}{222222}-\dfrac{8}{222222}\right)\)
\(I=10101.\left(\dfrac{15}{222222}-\dfrac{8}{222222}\right)\)
\(I=10101.\dfrac{7}{222222}\)
\(I=\dfrac{7}{22}\)
1.
a) \(A=10101\left(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\right)\)\(A=\dfrac{10101.5}{10101.11}+\dfrac{10101.5}{10101.22}-\dfrac{10101.4}{10101.11}\)
\(A=\dfrac{5}{11}+\dfrac{5}{22}-\dfrac{4}{11}=\dfrac{7}{22}\)
\(B=\dfrac{2698}{45}-\left(\dfrac{344}{45}-\dfrac{17}{57}\right)\)
(Áp dụng tính chất a - (b - c) = a-b-c)
\(B=\dfrac{2698}{45}-\dfrac{344}{45}-\dfrac{17}{57}\)
\(B=\dfrac{2354}{45}-\dfrac{17}{57}\)
\(B=\dfrac{44726}{855}-\dfrac{255}{855}\)
\(B=\dfrac{44471}{855}\)
\(D=\left(\dfrac{95}{8}:\dfrac{7}{12}-\dfrac{13}{4}:\dfrac{7}{12}\right).\dfrac{4}{5}\)
(Áp dụng tính chất)
\(D=\left(\dfrac{95}{8}-\dfrac{13}{4}\right):\dfrac{7}{12}\)
\(D=\left(\dfrac{95}{8}-\dfrac{26}{8}\right):\dfrac{7}{12}\)
\(D=\dfrac{69}{8}:\dfrac{7}{12}\)
\(D=\dfrac{69}{8}.\dfrac{12}{7}\)
\(D=\dfrac{207}{14}\)
\(F=\left(9.75.9+\dfrac{39}{4}.\dfrac{72}{7}\right).\dfrac{5}{26}\)
\(F=\left(675.9+\dfrac{702}{7}\right).\dfrac{5}{26}\)
\(F=\left(6075+\dfrac{702}{7}\right).\dfrac{5}{26}\)
\(F=\left(\dfrac{42525}{7}+\dfrac{702}{7}\right).\dfrac{5}{26}\)
\(F=\dfrac{43227}{7}.\dfrac{5}{26}\)
\(F=1187.554945\) ( Không biết, máy tính ghi vậy =='' )
I = 10101 . (\(\dfrac{5}{111111}+\dfrac{5}{222222}-\dfrac{4}{3.7.11.13.37}\))
= 10101 . (\(\dfrac{10}{222222}+\dfrac{5}{222222}-\dfrac{8}{222222}\))
= 10101 . \(\dfrac{7}{222222}\)
= \(\dfrac{70707}{222222}\)
= \(\dfrac{7}{22}\)
@Sweet Cake
B = 71\(\dfrac{38}{45}-\left(43\dfrac{8}{45}-1\dfrac{17}{57}\right)\)
= 71\(\dfrac{38}{45}-43\dfrac{8}{45}+1\dfrac{17}{57}\)
= (71 - 43 + 1) + (\(\dfrac{38}{45}-\dfrac{8}{45}+\dfrac{17}{57}\))
= 29 + \(\dfrac{55}{57}\)
= 29\(\dfrac{55}{57}\)
@Sweet Cake