tinh so phuc A=(1-\(\sqrt{3}\)i)5
trong ki thi vao trung hoc pho thong ,tong so diem 3 mon Toan , Van ,Anh(diem Toan,Van,Anh he so 2 )cua 4 ban Hoa , Binh, Hanh,Phuc nhu sau:ban Hoa dat 36 diem,diem Binh =14/43 tong so diem 3 ban con lai,diem Hanh =15/41 tong so diem 3 ban con lai.Diem phuc =2/5 tong so diem 3 ban con lai. Tinh diem cua moi ban
giup to giai bai nay voi.
Ba bạn co 671000nghin dong.
3/4 so tien cua phuc =1/5 cua Loc
3/7 cua Loc = 2/9 cua Tho.
Tinh moi ban ..?
Bai 1:Tinh: \(\sqrt{1}\) - \(\sqrt{4}\) + \(\sqrt{9}\) - \(\sqrt{16}\) + \(\sqrt{25}\)- \(\sqrt{36}\)+........- \(\sqrt{400}\)
Bai 2: Thuc hien phep tinh (bang cach hop li neu co the)
a, 15/34+7/21+19/24-1\(\dfrac{15}{17}\)+2/3 c, 1/2+3/2*5/6
b,\(\sqrt{25}\)+3^2-\(\sqrt{9}\)
Bai 3 : mot lop hoc co 35 hs sau khi khao sat so hs duoc xep thanh ba loai gioi,kha ,
trung binh.So hs gioi va kha ti le voi 2 va 3 ; so hs kha va trung binh la luot ti le voi 4 va 5 .Tinh
so hs moi loai?
Bai 4 : thuc hien phep tinh sau do lam tron den chu so thap hpan thu nhat
a, -5,18-0,479 c, ( | -2,45| + 3,1)*1/2 - 3/4
b, (3-1/2)^2 + (1-5/2)^2
Bài 3: Gọi số học sinh giỏi,khá,trung bình lần lượt là a,b,c
Theo bài ra ta có : \(\dfrac{a}{b}=\dfrac{2}{3}\Rightarrow\dfrac{a}{2}=\dfrac{b}{3}\); \(\dfrac{b}{c}=\dfrac{4}{5}\Rightarrow\dfrac{b}{4}=\dfrac{c}{5}\)
\(\Rightarrow\dfrac{a}{2}=\dfrac{b}{3};\dfrac{b}{4}=\dfrac{c}{5}\)
\(\Rightarrow\dfrac{a}{8}=\dfrac{b}{12}=\dfrac{c}{15}\); \(a+b+c=35\)
Áp dụng tính chất dãy tỉ số bằng nhau ta có:
\(\dfrac{a}{8}=\dfrac{b}{12}=\dfrac{c}{15}=\dfrac{a+b+c}{8+12+15}=\dfrac{35}{35}=1\)
Ta có : \(\dfrac{a}{8}=1\Rightarrow a=8\)
Làm tương tự ta tính được : \(b=12;c=15\)
Vậy số học sinh giỏi là 8 bạn
Số học sinh khá là 12 bạn
Số học sinh trung bình là 15 bạn
Bài 1:
\(\sqrt{1}-\sqrt{4}+\sqrt{9}-\sqrt{16}+\sqrt{25}-\sqrt{36}+.....-\sqrt{400}\)
\(=1-2+3-4+5-6+.....-20\)
\(=\left(1-2\right)+\left(3-4\right)-\left(5-6\right)+.....+\left(19-20\right)\)
\(=\left(-1\right)\times\dfrac{\dfrac{\left(20-1\right)\times1+1}{2}}{2}\)
\(=\left(-1\right)\times10\)
\(=-10\)
Dễ thế này mà ko ai lm à
Chúc bn học tốt
1) Cho so phuc z thoa man: /z+1-i/ = /z lien hop - 1 + 3i/ , biet /z/ min. Tim z
bai1 : cho day so Un=\(\frac{\left(5+\sqrt{7}\right)^n-\left(5-\sqrt{7}\right)^n}{2\sqrt{7}}\)voi n=0,1,2,3
a, tinh 5 so hang dau tien U0,U1,U2,U3,U4
b, CMR: Un+2=10Un+1-18Un
c, Lap quy trinh bam phim lien tuc tinh Un+2 theo Un+1 va Un
write the second sentences so that it has the same meaning to the first one
1. It's very important for you to be here at 6.00 - You...
2. Phuc wants to visit Ayres Rock - Phuc would....
3. The Sahara Desert is hotter than any other deserts in the world
- The Sahara is...............
1. It's very important for you to be here at 6.00
- You must be here at 6.00
2. Phuc wants to visit Ayres Rock
- Phuc would like to visit Ayres Rock
3. The Sahara Desert is hotter than any other deserts in the world
- The Sahara is the hottese desert in the world
bai 1 :
biet do thi ham so y=\(\left(\sqrt{a}-3\right)x\) di qua \(N\left(\sqrt{5};\sqrt{5}\right)\)( a la hang so)
vay a=?
Bai 2:
Cho \(Q\left(x\right)=ax^2+bx+c\)thoa man :
\(Q\left(0\right)=1;Q\left(1\right)=6;Q\left(2\right)=5\)Tinh b
bai 3 :tinh gia tri bieu thuc
\(A=3x+2y+z\)biet \(\left(x-3y^2\right)+\left(y-1\right)^2+\left(x+z\right)^2=0\)
Bài 1: Cho A = \(\dfrac{1}{2\sqrt{1}+1\sqrt{2}}+\dfrac{1}{3\sqrt{2}+2\sqrt{3}}+\dfrac{1}{4\sqrt{3}+3\sqrt{4}}+...+\dfrac{1}{100\sqrt{99}+99\sqrt{100}}\)
So sánh A với 1
Bài 2: Tính
A = \(\left(\dfrac{3}{\sqrt{2}+1}+\dfrac{14}{2\sqrt{2}-1}-\dfrac{4}{2-\sqrt{2}}\right).\left(\sqrt{8}+2\right)\)
Bài 3: Tính tổng
S=\(\dfrac{1}{\sqrt{2}+\sqrt{3}}+\dfrac{1}{\sqrt{3}+\sqrt{4}}+\dfrac{1}{\sqrt{4}+\sqrt{5}}+...+\dfrac{1}{\sqrt{2018}+\sqrt{2019}}\)
Bài 1:Với mọi n∈N*,ta có:
\(\dfrac{1}{\left(n+1\right)\sqrt{n}+n\sqrt{n+1}}=\dfrac{\left(n+1\right)\sqrt{n}-n\sqrt{n+1}}{\left(n+1\right)^2n-n^2\left(n+1\right)}=\dfrac{\left(n+1\right)\sqrt{n}-n\sqrt{n+1}}{n\left(n+1\right)}=\dfrac{1}{\sqrt{n}}-\dfrac{1}{\sqrt{n+1}}\)
Do đó :
A=\(\dfrac{1}{\sqrt{1}}-\dfrac{1}{\sqrt{2}}+\dfrac{1}{\sqrt{2}}-\dfrac{1}{\sqrt{3}}+...+\dfrac{1}{\sqrt{99}}-\dfrac{1}{\sqrt{100}}=1-\dfrac{1}{10}=\dfrac{9}{10}\)
Bài 2:
\(A=\left(3\sqrt{2}-3+4\sqrt{2}+2-4-2\sqrt{2}\right)\cdot\left(2\sqrt{2}+2\right)\)
\(=\left(5\sqrt{2}-5\right)\left(2\sqrt{2}+2\right)\)
=10
1.Put the conversation in the correct order then practice with your partner. The first and the last are your cue
A. Phuc: I think that "Adeline" is more interesting.
B. Phuc: Yes, sure. I'm free.
C.Mai: Let's me see. We have "Tomb of the Pharaoh Queen";"you are my grandma" and "Adeline". Do you love watching horrible movies or action movies?
D. Mai: Ok. See you soon.
E. Phuc: I will pick up at 7:00. By the way, lend me your English exercise book.
F. Phuc: I am hooked on horrible movies.
G. Mai: Would you like to go to see a movie?
H. Mai: Are you free tonight, Phuc?
I. Phuc: Yes, I'd love to. Which interesting movies are on?
J. Mai: Ok. So we'll see" Adeline" in Platinum Movie Center at 7:30pm.
K. Mai: That's interesting. Me,too.
Your answers:
1. H | 2. | 3. | 4. | 5. | 6. | 7. | 8. | 9. | 10. | 11. D |
Read the conversation again and answer the questions.
1. What kind of movies does Phuc kike?.........................................................................
2. Is Mai hooked on horrible movies?............................................................................
3. Where will they see the movie?..................................................................................
4. Which movies do they choose to see?.........................................................................
5. What time will they meet each other?..........................................................................