a) $\frac{4.7}{9.32}=\frac{4.7}{\mathrm{9.4.8}}=\frac{7}{9.8}=\frac{7}{72}$

b) $\frac{3.21}{14.15}=\frac{\mathrm{3.3.7}}{\mathrm{2.7.3.5}}=\frac{3}{2.5}=\frac{3}{10}$

c) $\frac{\mathrm{2.5.13}}{26.35}=\frac{\mathrm{2.5.13}}{\mathrm{2.13.5.7}}=\frac{1}{7}$

d) $\frac{9.6–9.3}{18}=\frac{9.(6–3)}{9.2}=\frac{6–3}{2}=\frac{3}{2}$

e) $\frac{17.5–17}{3–20}=\frac{17.(5–1)}{–17}=\frac{5–1}{–1}=–4$

f) $\frac{49+7.49}{49}=\frac{49.(1+7)}{49}=1+7=8$

a) \(\dfrac{4.7}{9.32}=\dfrac{4.7}{9.4.8}=\dfrac{7}{72}\)

b) \(\dfrac{3.21}{14.15}=\dfrac{3.3.7}{2.7.3.5}=\dfrac{3}{10}\)

c) \(\dfrac{2.5.13}{26.35}=\dfrac{2.5.13}{2.13.5.7}=\dfrac{1}{7}\)

d) \(\dfrac{9.6-9.3}{18}=\dfrac{9\left(6-3\right)}{9.2}=\dfrac{3}{2}\)

e) \(\dfrac{17.5-17}{3-20}=\dfrac{17\left(5-1\right)}{-17}=\dfrac{5-1}{-1}=-4\)

f) \(\dfrac{49+7.49}{49}=\dfrac{49\left(1+7\right)}{49}=8\)

\(\frac{4\cdot7}{9\cdot32}=\frac{4\cdot7}{9\cdot8\cdot4}=\frac{7}{8\cdot9}=\frac{7}{72}\)

\(\frac{2\cdot5\cdot13}{26\cdot35}=\frac{2\cdot5\cdot13}{2\cdot13\cdot7\cdot5}=\frac{1}{7}\)

\(\frac{3\cdot21}{14\cdot15}=\frac{3\cdot3\cdot7}{2\cdot7\cdot3\cdot5}=\frac{3}{2\cdot5}=\frac{3}{10}\)

\(\frac{9\cdot6-9\cdot3}{18}=\frac{9\cdot\left(6-3\right)}{9\cdot2}=\frac{9\cdot3}{9\cdot2}=\frac{3}{2}\)

\(\frac{17\cdot5-17}{3-20}=\frac{17\cdot\left(5-1\right)}{-17}=\frac{17\cdot4}{17\cdot\left(-1\right)}=\frac{4}{-1}=-4\)

\(45dm^2=0,45m^2\)

\(300cm^2=0,03m^2\)

\(57500mm^2=0,0575m^2\)

a) \(\dfrac{32}{12}=\dfrac{4.8}{4.3}=\dfrac{8}{3}\)

b) \(\dfrac{-26}{156}=\dfrac{-26}{26.6}=\dfrac{-1}{6}\)

c) \(\dfrac{4.7}{9.32}=\dfrac{4.7}{9.4.8}=\dfrac{7}{9.8}=\dfrac{7}{72}\)

d) \(\dfrac{2.5.13}{26.35}\dfrac{2.5.13}{2.13.5.7}=\dfrac{1}{7}\)

e)\(\dfrac{7.6-9.13}{18}=\dfrac{42-117}{18}=\dfrac{-75}{18}=\dfrac{-25.3}{6.3}=\dfrac{-25}{6}\)

f) \(\dfrac{17.5-17}{3-20}=\dfrac{17.\left(5-1\right)}{-17}=-4\)

g) \(\dfrac{49+7.49}{49}=\dfrac{49.\left(1+7\right)}{49}=8\)

a, \(\dfrac{32}{12}=\dfrac{8}{3}\)

b, \(\dfrac{-26}{156}=\dfrac{-1}{6}\)

c, \(\dfrac{4.7}{9.32}=\dfrac{4.7}{9.4.8}=\dfrac{7}{72}\)

d,\(\dfrac{2.5.13}{26.35}=\dfrac{2.5.13}{2.13.7.5}=\dfrac{1}{7}\)

e,\(\dfrac{7.6-9.13}{18}=\dfrac{3\left(7.2-3.13\right)}{18}=\dfrac{-25}{6}\)

f ,\(\dfrac{17.5-17}{3-20}=\dfrac{17\left(5-1\right)}{-17}=-4\)

g,\(\dfrac{49+7.49}{49}=\dfrac{49\left(1+7\right)}{49}=8\)

a, \(\dfrac{32}{12}\) = \(\dfrac{8}{3}\)

b. \(\dfrac{-26}{156}\) = \(\dfrac{-1}{6}\)

c, \(\dfrac{4.7}{9.32}\) = \(\dfrac{7}{72}\)

d, \(\dfrac{2.5.13}{25.36}\) = \(\dfrac{936}{5}\)

e, \(\dfrac{7.6-9.13}{18}\) = \(\dfrac{-25}{6}\)

f, \(\dfrac{17.5-17}{3-20}\) = -4

g, \(\dfrac{49+7.49}{49}\) = 8

a, \(\frac{4.7}{9.32}\)= \(\frac{7}{9.8}\)=\(\frac{7}{72}\) 

54

ủng hộ mk đi các bạn

chao ôi , mk chưa học

giúp mik đi nhé 

mik đang cần gấp nèeee

a,-7/12

b,5/14

c,-3/8

d,-1

,

,,,,,,,,,ư

4/ 3; 1/ 12

\(\dfrac{4}{3}\) và \(\dfrac{1}{12}\)

a: \(=\dfrac{13\cdot\left(9-2\right)}{13}=7\)

b: \(=\dfrac{14\left(3-8\right)}{7\left(1+3\cdot3\right)}=2\cdot\dfrac{-5}{10}=-1\)

c: \(=\dfrac{54-72}{36}=\dfrac{-18}{36}=-\dfrac{1}{2}\)

d: \(=\dfrac{5^3}{10^2\cdot5}=\dfrac{5^2}{100}=\dfrac{1}{4}\)

a. \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{3}{160}\)

b. \(\dfrac{2\cdot14}{7\cdot8}=\dfrac{1\cdot2}{1\cdot4}=\dfrac{2}{4}=\dfrac{1}{2}\)

c. \(\dfrac{11\cdot4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{1\cdot3}{-1}=-3\)

d. \(\dfrac{49+7\cdot49}{49}=\dfrac{49\cdot\left(1+7\right)}{49}=\dfrac{8}{1}=8\)