Tính :
a) \(\sqrt{81}\) b) \(\sqrt{8100}\) c) \(\sqrt{64}\)
d) \(\sqrt{0,64}\) e) \(\sqrt{1000000}\) g) \(\sqrt{0,01}\)
h) \(\sqrt{\dfrac{49}{100}}\) i) \(\sqrt{\dfrac{4}{25}}\) k) \(\sqrt{\dfrac{0,09}{121}}\)
Tính:
a,\(\sqrt{81}\)
b,\(\sqrt{8100}\)
c,\(\sqrt{64}\)
d,\(\sqrt{0,64}\)
e,\(\sqrt{1000000}\)
g,\(\sqrt{0,01}\)
h,\(\sqrt{\frac{49}{100}}\)
i,\(\sqrt{\frac{4}{25}}\)
k,\(\sqrt{\frac{0,09}{121}}\)
Bài 2: Tính:
a.\(\sqrt{81}\)
b. \(\sqrt{8100}\)
c. \(\sqrt{64}\)
d. \(\sqrt{\dfrac{49}{100}}\)
e . \(\sqrt{\dfrac{4}{25}}\)
tính:
a. \(\sqrt{81}\)
b.\(\sqrt{8100}\)
c.\(\sqrt{64}\)
d.\(\sqrt{25}\)
e.\(\sqrt{0,64}\)
f.\(\sqrt{10000}\)
g.\(\sqrt{0,01}\)
h.\(\sqrt{\frac{49}{100}}\)
i.\(\sqrt{\frac{0,09}{121}}\)
j.\(\sqrt{\frac{4}{25}}\)
\(a,\sqrt{81}=9\)
\(b.\sqrt{8100}=90\)
\(c,\sqrt{64}=8\)
\(d,\sqrt{25}=5\)
\(e,\sqrt{0,64}=0,8\)
\(f,\sqrt{10000}=100\)
\(g,\sqrt{0,01}=0,1\)
\(h,\sqrt{\frac{49}{100}}=\frac{7}{10}\)
\(i,\sqrt{\frac{0,09}{121}}=\frac{0,3}{11}\)
\(j,\sqrt{\frac{4}{25}}=\frac{2}{5}\)
~Study well~
#JDW
a) 9
b) 90
c) 8
d) 5
e) 0,8
f) 100
g) 0,1
h) \(\frac{7}{10}\)
i) \(\frac{0,3}{11}\)
j) 0,4.
Tính giá trị của biểu thức:
\(\begin{array}{l}a)\sqrt {0,49} + \sqrt {0,64} ;b)\sqrt {0,36} - \sqrt {0,81} ;\\c)8.\sqrt 9 - \sqrt {64} ;d)0,1.\sqrt {400} + 0,2.\sqrt {1600} \end{array}\)
\(\begin{array}{l}a)\sqrt {0,49} + \sqrt {0,64} = 0,7 + 0,8 = 1,5;\\b)\sqrt {0,36} - \sqrt {0,81} = 0,6 - 0,9 = - 0,3;\\c)8.\sqrt 9 - \sqrt {64} = 8.3 - 8 = 24 - 8 = 16;\\d)0,1.\sqrt {400} + 0,2.\sqrt {1600} = 0,1.20 + 0,2.40 = 2 + 8 = 10\end{array}\)
Tính \(\sqrt{81=}\)
\(\sqrt{0,64=}\) \(\sqrt{\frac{49}{100}=}\)
\(\sqrt{8100=}\) \(\sqrt{100=}\)
\(\sqrt{0,01=}\) \(\sqrt{\frac{4}{25}=}\) \(\sqrt{\frac{0,09}{121}=}\)
Ng các bạn giúp mik xin cảm ơn
\(\sqrt{81}=9\)
\(\sqrt{0,64}=0,8\)
\(\sqrt{\frac{49}{100}}=\frac{7}{10}\)
\(\sqrt{8100}=90\)
\(\sqrt{100=}10\)
\(\sqrt{0,01}=0,1\)
\(\sqrt{\frac{4}{25}}=\frac{2}{5}\)
\(\sqrt{\frac{0,09}{121}}=\frac{0,3}{11}\)
\(\sqrt{81}=9\);\(\sqrt{0,64}=0,8\);\(\sqrt{\frac{49}{100}}=\frac{7}{10}\);\(\sqrt{8100}=90\); \(\sqrt{100}=10\); \(\sqrt{0,01}=0,1\); \(\sqrt{\frac{4}{25}}=\frac{2}{5}\); \(\sqrt{\frac{0,09}{121}}=\frac{0,3}{11}=\frac{3}{110}\)
\(\sqrt{81}=9\)
\(\sqrt{0.64}=\sqrt{\frac{64}{100}}=\frac{8}{10}\);\(\sqrt{\frac{49}{100}}=\frac{7}{10}\)
\(\sqrt{8100}=\sqrt{81}.\sqrt{100}=9.10=90\);\(\sqrt{100}=10\)
\(\sqrt{0,01}=0,1\);\(\sqrt{\frac{4}{25}}=\frac{2}{5}\);\(\sqrt{\frac{0,09}{121}}=\frac{0,3}{11}\)
TÍNH GIÁ TRỊ CÁC BIỂU THỨC SAU
A,\(\sqrt{0,09}-\sqrt{0,64}\)
B,\(0,1\times\sqrt{225}-\sqrt{\frac{1}{4}}\)
C,\(\sqrt{0,36}\times\sqrt{\frac{25}{16}+\frac{1}{4}}\)
D,\(\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}-1\frac{2}{5}}\)
a) \(\sqrt{0,09}-\sqrt{0,64}=\frac{-1}{2}=-0,5\)
b) \(0,1\cdot\sqrt{225}-\sqrt{\frac{1}{4}}=0,1\cdot15-\frac{1}{2}=1\)
c) \(\sqrt{0,36}\cdot\sqrt{\frac{25}{16}+\frac{1}{4}}=\frac{3\sqrt{29}}{20}\)
d) đề baì có sai ko ban?
a,\(\sqrt{1}+\sqrt{9}+\sqrt{25}+\sqrt{49}+\sqrt{81}\) c\(\sqrt{0,04}+\sqrt{0,09}+\sqrt{0,16}\)
b,\(\sqrt{\dfrac{1}{4}}+\sqrt{\dfrac{1}{9}}+\sqrt{\dfrac{1}{36}}+\sqrt{\dfrac{1}{16}}\) e\(\sqrt{2^2}+\sqrt{4^2}+\sqrt{\left(-6^2\right)}+\sqrt{\left(-8^2\right)}\)
j,\(\sqrt{1,44}-\sqrt{1,69}+\sqrt{1,96}\)
g, \(\sqrt{\dfrac{4}{25}}+\sqrt{\dfrac{25}{4}}+\sqrt{\dfrac{81}{100}}+\sqrt{\dfrac{9}{16}}\)
d\(\sqrt{81}-\sqrt{64}+\sqrt{49}\)
a)\(\sqrt{1}\)+\(\sqrt{9}\)+\(\sqrt{25}\)+\(\sqrt{49}\)+\(\sqrt{81}\)
=1+3+5+7+9
=25
b)=\(\dfrac{1}{2}\)+\(\dfrac{1}{3}\)+\(\dfrac{1}{6}\)+\(\dfrac{1}{4}\)
=\(\dfrac{6}{12}\)+\(\dfrac{4}{12}\)+\(\dfrac{2}{12}\)+\(\dfrac{3}{12}\)
=\(\dfrac{15}{12}\)
c) =0,2+0.3+0,4
= 0.9
d) =9-8+7
=8
j) =1,2-1,3+1.4
= (-0,1)+1,4
=1,4
g) \(\dfrac{2}{5}\)+\(\dfrac{5}{2}\)+\(\dfrac{9}{10}\)+\(\dfrac{3}{4}\)
= (\(\dfrac{4}{10}\)+\(\dfrac{15}{10}\)+\(\dfrac{9}{10}\))+\(\dfrac{3}{4}\)
= \(\dfrac{14}{5}\)+\(\dfrac{3}{4}\)
=\(\dfrac{56}{20}\)+\(\dfrac{15}{20}\)
= \(\dfrac{71}{20}\)
Nhớ tick cho mk nha~
Bài 1: Tính
a) \(\sqrt{49}+\sqrt{4}\)
b) \(\sqrt{0,25}-\sqrt{0,01}\)
c) \(\sqrt{\dfrac{16}{25}}-\sqrt{\dfrac{1}{81}}\)
d) \(\sqrt{64}-\sqrt{16}+\sqrt{\left(-3\right)^2}\)
e) \(2-\sqrt{0,36}\)
a\\(\sqrt{49}+\sqrt{4}=7+2=9\)
b\\(\sqrt{0,25}-\sqrt{0.01}=0.5-01=0.4\)
c\\(\sqrt{\dfrac{16}{25}}-\sqrt{\dfrac{1}{81}}=\dfrac{4}{5}-\dfrac{1}{9}=\dfrac{31}{45}\)
d\\(\sqrt{64}-\sqrt{16}+\sqrt{\left(-3\right)^2}=8-4+3=7\)
e\\(2-\sqrt{0,36}=2-0.6=1.4\)
a) \(\sqrt{49}+\sqrt{4}=7+2=9\)
b) \(\sqrt{0,25}-\sqrt{0,01}=0,5-0,1=0,4\)
c) \(\sqrt{\dfrac{16}{25}}-\sqrt{\dfrac{1}{81}}=\dfrac{4}{5}-\dfrac{1}{9}=\dfrac{31}{45}\)
d) \(\sqrt{64}-\sqrt{16}+\sqrt{\left(-3\right)^2}=8-4+3=4+3=7\)
e) \(2-\sqrt{0,36}=2-\dfrac{3}{5}=\dfrac{10}{5}-\dfrac{3}{5}=\dfrac{7}{5}\)
\(b.\sqrt{\frac{25}{36}}\)
\(a.\sqrt{\left(-0,001\right)}\)
\(c.-\sqrt{\frac{0,64}{81}}\)
\(Tính\)
b) \(\sqrt{\frac{25}{36}}=\sqrt{\frac{5^2}{6^2}}=\frac{5}{6}\)
a) \(\sqrt{\left(-0,001\right)}=\varnothing\)
c) \(-\sqrt{\frac{0,64}{81}}=-\sqrt{\frac{0,8^2}{9^2}}=-\frac{0,8}{9}=\frac{-4}{45}\)