Question

Bài 1: Tính

a) \(\sqrt{49}+\sqrt{4}\)

b) \(\sqrt{0,25}-\sqrt{0,01}\)

c) \(\sqrt{\dfrac{16}{25}}-\sqrt{\dfrac{1}{81}}\)

d) \(\sqrt{64}-\sqrt{16}+\sqrt{\left(-3\right)^2}\)

e) \(2-\sqrt{0,36}\)

Answer 1

a\\(\sqrt{49}+\sqrt{4}=7+2=9\)

b\\(\sqrt{0,25}-\sqrt{0.01}=0.5-01=0.4\)

c\\(\sqrt{\dfrac{16}{25}}-\sqrt{\dfrac{1}{81}}=\dfrac{4}{5}-\dfrac{1}{9}=\dfrac{31}{45}\)

d\\(\sqrt{64}-\sqrt{16}+\sqrt{\left(-3\right)^2}=8-4+3=7\)

e\\(2-\sqrt{0,36}=2-0.6=1.4\)

Answer 2

a) \(\sqrt{49}+\sqrt{4}=7+2=9\)

b) \(\sqrt{0,25}-\sqrt{0,01}=0,5-0,1=0,4\)

c) \(\sqrt{\dfrac{16}{25}}-\sqrt{\dfrac{1}{81}}=\dfrac{4}{5}-\dfrac{1}{9}=\dfrac{31}{45}\)

d) \(\sqrt{64}-\sqrt{16}+\sqrt{\left(-3\right)^2}=8-4+3=4+3=7\)

e) \(2-\sqrt{0,36}=2-\dfrac{3}{5}=\dfrac{10}{5}-\dfrac{3}{5}=\dfrac{7}{5}\)