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a: \(A=\dfrac{-7}{28}\cdot\dfrac{15}{25}=\dfrac{-1}{4}\cdot\dfrac{3}{5}=\dfrac{-3}{20}\)

b: \(B=\dfrac{-5\cdot7}{14\cdot\left(-3\right)}=\dfrac{35}{42}=\dfrac{5}{6}\)

c: \(C=\dfrac{-1}{5}-\dfrac{1}{5}\cdot\dfrac{3}{5}=\dfrac{-1}{5}-\dfrac{3}{25}=\dfrac{-8}{25}\)

d: \(D=\dfrac{-3}{4}-\dfrac{1}{4}=-1\)

e: \(E=\dfrac{-4}{5}\left(1-\dfrac{15}{16}\right)=\dfrac{-4}{5}\cdot\dfrac{1}{16}=\dfrac{-1}{20}\)

f: \(F=\dfrac{6-7}{4}\cdot\dfrac{4+12}{22}=\dfrac{-1}{4}\cdot\dfrac{8}{11}=\dfrac{-2}{11}\)

giúp mik nhoa mik đag cần gấp hihi

a) \(x=\dfrac{-3.\left(-5\right)}{15}=1\)

b) \(x=\dfrac{5.1173}{3}=1955\)

c) Tách làm 2 phép tính

(1) \(\dfrac{y}{15}=\dfrac{-25}{75}\rightarrow y=\dfrac{-25.15}{75}=-5\)

(2) \(\dfrac{2}{x}=\dfrac{-25}{75}\rightarrow x=\dfrac{75.2}{-25}=-6\)

a) 15/3 - 2/3 = 13/3

b) 15/20 = 3/4

c) 1/24

d) 2/5 - 1/5 = 1/5

a, = 17/3

b, = 3/4

c, = 1/24

d, = 6/15 - 1/5 = 1/5

a, \(\dfrac{5}{1}+\dfrac{2}{3}=\dfrac{15}{3}+\dfrac{2}{3}=\dfrac{17}{3}\)

b, \(3\times\dfrac{1}{4}=\dfrac{3}{1}\times\dfrac{1}{4}=\dfrac{3}{4}\)

c, \(\dfrac{3}{8}-\dfrac{1}{3}=\dfrac{9}{24}-\dfrac{8}{24}=\dfrac{1}{24}\)

d, \(\dfrac{6}{15}-\left(\dfrac{1}{3}:\dfrac{5}{3}\right)=\dfrac{6}{15}-\left(\dfrac{1}{3}\times\dfrac{3}{5}\right)=\dfrac{6}{15}-\dfrac{3}{15}=\dfrac{3}{15}=\dfrac{1}{5}\)

\(\dfrac{15-x}{14}=\dfrac{5}{7}\\ \left(15-x\right)\times7=5\times14\\ \left(15-x\right)\times7=70\\ 15-x=70:7\\ 15-x=10\\ x=15-10\\ x=5\)

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\(\dfrac{x}{9}=\dfrac{17}{3}\\ x\times3=17\times9\\ x\times3=153\\ x=153:3\\ x=51\)

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\(15-\dfrac{x}{2}=\dfrac{3}{7}\\ \dfrac{x}{2}=15-\dfrac{3}{7}\\ \dfrac{x}{2}=\dfrac{102}{7}\\ x\times7=102\times2\\ x\times7=204\\ x=204:7\\ x=\dfrac{204}{7}\)

???

1) PT \(\Leftrightarrow\dfrac{x+3}{15}=\dfrac{4}{15}\) \(\Rightarrow x+3=4\) \(\Rightarrow x=1\)

  Vậy ...

2) Mạnh dạn đoán đề là \(\left(2x-5\right)\left(x-3\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}2x-5=0\\x-3=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=3\end{matrix}\right.\)

  Vậy ...

3) PT \(\Rightarrow3x-4-2x+5=3\)

          \(\Rightarrow x=2\)

 Vậy ...

4) PT \(\Rightarrow\left[{}\begin{matrix}2x+1=0\\\dfrac{1}{2}x-1=0\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=2\end{matrix}\right.\)

  Vậy ...

3) Ta có: \(\left(3x-4\right)-\left(2x-5\right)=3\)

\(\Leftrightarrow3x-4-2x+5=3\)

\(\Leftrightarrow x+1=3\)

hay x=2

Chọn B

Chọn B

a)\(x=\left(\dfrac{3}{56}\cdot\dfrac{28}{9}\right):\dfrac{-3}{7}=\dfrac{1}{6}:\dfrac{-3}{7}=-\dfrac{7}{18}\)

b)\(x=\left(\dfrac{7}{15}\cdot\dfrac{5}{3}\right)+\dfrac{3}{16}=\dfrac{7}{9}+\dfrac{3}{16}=\dfrac{139}{144}\)

c)\(x=\left(\dfrac{5}{6}-\dfrac{2}{5}\right).5=\dfrac{13}{6}\)

d)\(=>x\left(\dfrac{3}{4}-\dfrac{2}{5}\right)=\dfrac{1}{6}\cdot\left(\dfrac{3}{7}+\dfrac{5}{7}\right)\)

\(x\cdot\dfrac{7}{20}=\dfrac{4}{21}=>x=\dfrac{4}{21}\cdot\dfrac{20}{7}=\dfrac{80}{147}\)

a: =>3/5x=5/6+3/2=5/6+9/6=14/6=7/3

=>x=35/9

b: =(4/5+16/5)+(37/7+57)

=61+37/7=464/7

\(\dfrac{3}{5}x=\dfrac{5}{6}+\dfrac{3}{2}=\dfrac{14}{6}=\dfrac{7}{3}\Leftrightarrow x=\dfrac{7}{3}:\dfrac{3}{5}=\dfrac{35}{9}\)

\(\dfrac{19}{5}+\dfrac{37}{7}+57=\dfrac{19.7+37.5}{35}+\dfrac{57.35}{35}=\dfrac{2313}{35}\)

\(\dfrac{3}{5}\times x-\dfrac{3}{2}=\dfrac{5}{6}\)

\(\dfrac{3}{5}\times x=\dfrac{5}{6}+\dfrac{3}{2}\)

\(\dfrac{3}{5}\times x=\dfrac{7}{3}\)

\(x=\dfrac{7}{3}:\dfrac{3}{5}\)

\(x=\dfrac{7}{3}\times\dfrac{5}{3}\)

\(x=\dfrac{35}{9}\)

\(\dfrac{12}{15}+\dfrac{37}{7}+\dfrac{16}{5}+57=\dfrac{4}{5}+\dfrac{37}{3}+\dfrac{16}{5}+57=\left(\dfrac{4}{5}+\dfrac{16}{5}\right)+\left(\dfrac{37}{7}+57\right)=4+\dfrac{436}{7}=\dfrac{464}{7}\)