Question

\(\dfrac{3}{5}\) x \(x\) \(-\) \(\dfrac{3}{2}\) = \(\dfrac{5}{6}\)

 

\(\dfrac{12}{15}+\dfrac{37}{7}+\dfrac{16}{5}+57\)

Answer 1

a: =>3/5x=5/6+3/2=5/6+9/6=14/6=7/3

=>x=35/9

b: =(4/5+16/5)+(37/7+57)

=61+37/7=464/7

Answer 2

\(\dfrac{3}{5}x=\dfrac{5}{6}+\dfrac{3}{2}=\dfrac{14}{6}=\dfrac{7}{3}\Leftrightarrow x=\dfrac{7}{3}:\dfrac{3}{5}=\dfrac{35}{9}\)

\(\dfrac{19}{5}+\dfrac{37}{7}+57=\dfrac{19.7+37.5}{35}+\dfrac{57.35}{35}=\dfrac{2313}{35}\)

Answer 3

\(\dfrac{3}{5}\times x-\dfrac{3}{2}=\dfrac{5}{6}\)

\(\dfrac{3}{5}\times x=\dfrac{5}{6}+\dfrac{3}{2}\)

\(\dfrac{3}{5}\times x=\dfrac{7}{3}\)

\(x=\dfrac{7}{3}:\dfrac{3}{5}\)

\(x=\dfrac{7}{3}\times\dfrac{5}{3}\)

\(x=\dfrac{35}{9}\)

 

 

\(\dfrac{12}{15}+\dfrac{37}{7}+\dfrac{16}{5}+57=\dfrac{4}{5}+\dfrac{37}{3}+\dfrac{16}{5}+57=\left(\dfrac{4}{5}+\dfrac{16}{5}\right)+\left(\dfrac{37}{7}+57\right)=4+\dfrac{436}{7}=\dfrac{464}{7}\)