Question

A,\(\dfrac{3}{5}+\dfrac{1}{6}\)

 

B,\(4+\dfrac{2}{5}\)

 

C,\(\dfrac{25}{12}-\dfrac{7}{6}\)

 

D,\(\dfrac{9}{7}-\dfrac{7}{6}\)

 

E,\(\dfrac{3}{7}\) x \(\dfrac{2}{5}\)

Answer 1

a) \(\dfrac{3}{5}+\dfrac{1}{6}=\dfrac{18}{30}+\dfrac{5}{30}=\dfrac{23}{30}\)

b) \(4+\dfrac{2}{5}=\dfrac{20}{5}+\dfrac{2}{5}=\dfrac{22}{5}\)

c) \(\dfrac{25}{12}-\dfrac{7}{6}=\dfrac{25}{12}-\dfrac{14}{12}=\dfrac{11}{12}\)

d) \(\dfrac{9}{7}-\dfrac{7}{6}=\dfrac{54}{42}-\dfrac{49}{42}=\dfrac{5}{42}\)

d) \(\dfrac{3}{7}\times\dfrac{2}{5}=\dfrac{3\times2}{7\times5}=\dfrac{6}{35}\)

Answer 2

A=18/30+5/30=23/30

B=20/5+2/5=22/5

C=25/12-14/12=11/12

D=54/42-49/42=5/42

E=6/35

Answer 3

18/30 + 5/30 = 23/30

20/5 + 2/5 = 22/5

25/12 - 14/12 = 11/12

3/7 x 2/5 = 6/35

Answer 4

\(a.\dfrac{3}{5}+\dfrac{1}{6}=\dfrac{18}{30}+\dfrac{5}{30}=\dfrac{23}{30}\)

\(b.4+\dfrac{2}{5}=\dfrac{4}{1}+\dfrac{2}{5}=\dfrac{20}{5}+\dfrac{2}{5}=\dfrac{22}{5}\)

\(c.\dfrac{25}{12}-\dfrac{7}{6}=\dfrac{25}{12}-\dfrac{14}{12}=\dfrac{11}{12}\)

\(d.\dfrac{9}{7}-\dfrac{7}{6}=\dfrac{54}{42}-\dfrac{49}{42}=\dfrac{5}{42}\)

\(e.\dfrac{3}{7}\times\dfrac{2}{5}=\dfrac{6}{35}\)

Answer 5

a) 35+16=1830+530=233053​+61​=3018​+305​=3023​

b) 4+25=205+25=2254+52​=520​+52​=522​

c) 2512−76=2512−1412=11121225​−67​=1225​−1214​=1211​

d) 97−76=5442−4942=54279​−67​=4254​−4249​=425​

d) 37×25=3×27×5=63573​×52​=7×53×2​=356​