| 2-x | + | x-3 | = 0
Tìm x
\(\dfrac{1}{3}x\)+\(\dfrac{2}{3}\)(x-1)=0
tìm x
\(\dfrac{1}{3}x+\dfrac{2}{3}\left(x-1\right)=0\\ \dfrac{1}{3}x+\dfrac{2}{3}x-\dfrac{2}{3}=0\\ x=\dfrac{2}{3}\)
`1/3x + 2/3(x-1) =0`
` 1/3x + 2/3x -2/3 = 0`
` ( 1/3 + 2/3) x -2/3 = 0`
` 3/3x -2/3 = 0`
` 1x-2/3 = 0`
`1/x = 0 + 2/3`
` 1x = 2/3`
` x = 2/3`
(x-2)3-x(x-1)(x+1)+x(7x-6)=0
Tìm x
Ta có: \(\left(x-2\right)^3-x\left(x-1\right)\left(x+1\right)+x\left(7x-6\right)=0\)
\(\Leftrightarrow x^3-6x^2+12x-8-x^3+x+7x^2-6x=0\)
\(\Leftrightarrow x^2+7x-8=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-8\\x=1\end{matrix}\right.\)
bạn có thể tách rõ hơn đoạn cuối dc khum mình cảm ơn
(x - 1 ) . ( x +2) . (-x - 3) = 0
Tìm các số nguyên x , thỏa mãn :
( x - 7 ) ( x + 3 ) < 0
a: (x-1)(x+2)(-x-3)=0
=>(x-1)(x+2)(x+3)=0
=>\(\left[{}\begin{matrix}x-1=0\\x+2=0\\x+3=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=1\\x=-2\\x=-3\end{matrix}\right.\)
b: (x-7)(x+3)<0
TH1: \(\left\{{}\begin{matrix}x-7>0\\x+3< 0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x>7\\x< -3\end{matrix}\right.\)
=>\(x\in\varnothing\)
TH2: \(\left\{{}\begin{matrix}x-7< 0\\x+3>0\end{matrix}\right.\)
=>\(\left\{{}\begin{matrix}x< 7\\x>-3\end{matrix}\right.\)
=>-3<x<7
mà x nguyên
nên \(x\in\left\{-2;-1;0;1;2;3;4;5;6\right\}\)
x ^ 2- ( 2 + √2 + √3 ) x + 1 + √2 + √3 + √6 = 0
Tìm x
giúp e với ạ
đánh đề bằng latex cho rõ đi bạn, không biết nào dấu nào biến:v
x(x-3)-x+3=0
Tìm x
\(\Rightarrow x\left(x-3\right)-\left(x-3\right)=0\\ \Rightarrow\left(x-1\right)\left(x-3\right)=0\\ \Rightarrow\left[{}\begin{matrix}x=1\\x=3\end{matrix}\right.\)
(x-2021)(x-5)=x-2021
(2x-3)^2-36^2=0
Tìm x giúp em với em cần gấp ah
\(\Leftrightarrow\left(x-2021\right)\left(x-5\right)-\left(x-2021\right)=0\\ \Leftrightarrow\left(x-2021\right)\left(x-6\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=2021\\x=6\end{matrix}\right.\)
Tìm x biết: (x + 2)^2 - (x + 2)(x - 3) = 0
Tìm x biết :
a,(x+2)^2-(x+2)(x-3)=0
b,2x^3-4x^2+2x=0
c,(x-1)^2-(2x+1)^2=0
\(a,\Leftrightarrow\left(x+2\right)\left(x+2-x+3\right)=0\\ \Leftrightarrow5\left(x+2\right)=0\Leftrightarrow x=-2\\ b,\Leftrightarrow2x\left(x-1\right)^2=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\\ c,\Leftrightarrow\left(x-1-2x-1\right)\left(x-1+2x+1\right)=0\\ \Leftrightarrow3x\left(-x-2\right)=0\Leftrightarrow-3x\left(x+2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x=-2\end{matrix}\right.\)
x-(m+3) căn x + m + 2=0
Tìm m để phương trình có 2 nghiệm phân loại
x-(m+3) căn x + m + 2=0
Tìm m để phương trình có 2 nghiệm phân loại
(1/2.x-7).(x+2)=0
tìm x
`(1/2x-7)(x+2)=0`
`<=>` \(\left[ \begin{array}{l}\dfrac12x-7=0\\x+2=0\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}\dfrac12x=7\\x=-2\end{array} \right.\)
`<=>` \(\left[ \begin{array}{l}x=14\\x=-2\end{array} \right.\)
Vậy `x=14` hoặc `x=-2`
Ta có: \(\left(\dfrac{1}{2}x-7\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{1}{2}x-7=0\\x+2=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=14\\x=-2\end{matrix}\right.\)