12x – 33 = 32.33

    12x - 33 = 9.27

    12x - 33 = 243

    12x = 243 + 33

    12x = 276

    x = 276:12

    x = 23

Vậy x = 23

12x - 33 = 3².3³

12x - 33 = 9.27

12x - 33 = 243

12x = 243 + 33

12x = 276

x = 276 : 12

x = 23

\(12x-33=3^2\cdot3^3\)

\(12x-33=3^{2+3}\)

\(12x-33=3^5\)

\(12x-33=243\)

\(12x=243+33\)

\(12x=276\)

\(x=\dfrac{276}{12}\)

\(x=23\)

d)12.x - 33= 3 2 . 3 3

12.x - 33 = 9.27

12.x - 33 = 243

12.x = 243 + 33

12.x = 276

x = 276:12

x = 23

a: Ta có: \(x^3+1=0\)

\(\Leftrightarrow x^3=-1\)

hay x=-1

b: Ta có: \(6x^2-12x-48=0\)

\(\Leftrightarrow\left(x-4\right)\left(x+2\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-2\end{matrix}\right.\)

96 - 3( x + 1 ) = 42

      3( x + 1 )  = 96 - 42

      3( x + 1 )  = 54

          x + 1    = 54 : 3 = 18

                 x   = 18 - 1 

                 x   = 17 

cau 1 

96-3(x+1)=42

=> 3(x-1)=54

=> x-1=18

=> x=19

cau 2 

12x-33=3².3³

=> 12x-33=243

=> 12x=276

=> x=23

12x - 33 = 3² . 3³

12x - 33 = 3⁵ = 243

      12x  = 243 + 33

       12x = 276

          x  = 276 : 12

          x  = 23

`@` `\text {Ans}`

`\downarrow`

`a)`

`3x ( 12x - 4 ) - 9x( 4x - 3 ) = 30`

`=> 3x (12x-4) - 3*3x (4x - 3) = 30`

`=> 3x [12x - 4 - 3(4x-3)] = 30`

`=> 3x (12x - 4 - 12x + 9) = 30`

`=> 3x (-4+9)=30`

`=> 3x*5=30`

`=> 3x=6`

`=> x=2`

Vậy, `x=2`

`b)`

`x( 5 - 2x) + 2x( x - 1)`

`=> x(5-2x) + 2x^2 - 2x=15`

`=> 5x - 2x^2 + 2x^2 - 2x =15`

`=> 3x = 15`

`=> x=5`

Vậy, `x=5.`

a: =>36x^2-12x-36x^2+27x=30

=>15x=30

=>x=2

b: =>5x-2x^2+2x^2-2x=15

=>3x=15

=>x=5

a)12x-33=3².3³

12x-33=243

12x=243+33

12x=276

x=276/12

x=23

a) 12x - 33 = \(3^2.3^3\)

\(\Rightarrow12x-33=3^5\)

\(\Rightarrow12x-33=243\)

\(\Rightarrow12x=243+33\)

\(\Rightarrow12x=276\)

\(\Rightarrow x=276:12\)

\(\Rightarrow x=23\)

b 96 - 3 (x + 10) = 42

\(\Rightarrow3\left(x+10\right)=96-42\)

\(\Rightarrow3\left(x+10\right)=54\)

\(\Rightarrow x+10=54:3\)

\(=>x+10=17\)

\(\Rightarrow x=17-10\)

\(\Rightarrow x=7\)

a)  12x - 33 = 3^2 . 3^3

     12x - 33 = 243

        12x     = 243 + 33

         12x    = 276

            x     = 276 : 12

            x     =  23

b)   96 - 3( x + 10 ) = 42

             3( x + 10 ) = 96 - 42

             3( x + 10 ) = 54

                x + 10    = 54 : 3

                x + 10    = 18

                  x          = 18 - 10

                  x          = 8

a ) 5(x + 35 ) = 515                               

       x + 35 = 515 : 5

       x + 35 = 103

              x = 103 - 35

              x = 68

a) x+35=515:5

   x+35=103

   x= 103-35=68

b) 96-3(x+1)=42

3(x+1)=96-42=54

x+1=54:3=18

x=18-1=17

c)  12x-33=3².3³

  12x - 33 = 9 . 27

  12x - 33=243

12x = 243 +33 

12x = 276

x= 276:12

x=23

a)  5(x + 35) = 515
=>    x + 35 = 103
=>    x         = 68

b)  96 - 3(x + 1) = 42
=>       3(x + 1) = 54
=>          x + 1  = 18
=>          x        = 17

c)  12x - 33 = 3² . 3³
=> 3(4x - 11) = 3⁵
=>    4x - 11  = 3⁴
=>    4x - 11  = 81
=>    4x        = 92
=>      x        = 23

a) 5 ( x + 35 ) = 515

         x + 35 = 103

         x         = 68

b) 96 - 3(x+1) = 49 

           3(x+1) = 47

              x + 1 = 47/3

              x = 44/3

c) 12x - 33 = 3^2 * 3^3

     12x - 33 = 243

      12x = 276

          x = 23

5 ( x + 35 ) = 515

     x + 35  = 515 : 5

      x + 35 = 103

      x        = 103 - 35

      x         = 68

96 - 3( x + 1 ) = 49

       3( x + 1 ) = 96 - 49

        3( x + 1 ) = 47

            x + 1   = 47/3

            x         = 47/3 - 1 

             x        = 44/3

12x - 33 = 3² . 3³

12x - 33 = 3⁵

12x - 33 = 243

12x        = 243 + 33

12x        = 276

    x       = 276 : 12

     x       = 23

\(a.5\cdot\left(x+35\right)=515\)         

\(x+35=515:5\)

\(x+35=103\)

\(x=103-35\)      

x=68

\(b.96-3\left(x+1\right)=49\)  

\(3\left(x+1\right)=96-49\)         

\(3\left(x+1\right)=47\)

\(x+1=\frac{47}{3}\) 

\(x=\frac{47}{3}-1\)

\(x=\frac{44}{3}\)

\(c.12x-33=3^2\cdot3^3\)

\(12x-33=243\)

\(12x=243+33\)

\(12x=276\)

\(x=276:12\)

\(x=23\)