a) x-12=-9+15
b)4x -12=400
c)2x -35=15
d)3x+17=2
e)-5/8=x/16
f)y/10=-4/8
bài 7
4x3 + 12 = 120
b, ( x - 4 )2 = 64
c, ( x + 1 )3 - 2 = 52
d, 136 - ( x + 5)2 = 100
e, 4x = 16
f, 7x. 3 - 147 = 0
g, 2x+3 - 15 = 17
h, 52x-4. 4 = 102
i, (32 - 4x)(7 - x) = 0
k, ( 8 - x)(10 - 2x) = 0
m, 3x + 3x+1 = 108
n, 5x+2 + 5x+1 = 750
a: \(4x^3+12=120\)
=>\(4x^3=108\)
=>\(x^3=27=3^3\)
=>x=3
b: \(\left(x-4\right)^2=64\)
=>\(\left[{}\begin{matrix}x-4=8\\x-4=-8\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=12\\x=-4\end{matrix}\right.\)
c: (x+1)^3-2=5^2
=>\(\left(x+1\right)^3=25+2=27\)
=>x+1=3
=>x=2
d: 136-(x+5)^2=100
=>(x+5)^2=36
=>\(\left[{}\begin{matrix}x+5=6\\x+5=-6\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=1\\x=-11\end{matrix}\right.\)
e: \(4^x=16\)
=>\(4^x=4^2\)
=>x=2
f: \(7^x\cdot3-147=0\)
=>\(3\cdot7^x=147\)
=>\(7^x=49\)
=>x=2
g: \(2^{x+3}-15=17\)
=>\(2^{x+3}=32\)
=>x+3=5
=>x=2
h: \(5^{2x-4}\cdot4=10^2\)
=>\(5^{2x-4}=\dfrac{100}{4}=25\)
=>2x-4=2
=>2x=6
=>x=3
i: (32-4x)(7-x)=0
=>(4x-32)(x-7)=0
=>4(x-8)*(x-7)=0
=>(x-8)(x-7)=0
=>\(\left[{}\begin{matrix}x-8=0\\x-7=0\end{matrix}\right.\)
=>\(\left[{}\begin{matrix}x=8\\x=7\end{matrix}\right.\)
k: (8-x)(10-2x)=0
=>(x-8)(x-5)=0
=>\(\left[{}\begin{matrix}x-8=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=8\\x=5\end{matrix}\right.\)
m: \(3^x+3^{x+1}=108\)
=>\(3^x+3^x\cdot3=108\)
=>\(4\cdot3^x=108\)
=>\(3^x=27\)
=>x=3
n: \(5^{x+2}+5^{x+1}=750\)
=>\(5^x\cdot25+5^x\cdot5=750\)
=>\(5^x\cdot30=750\)
=>\(5^x=25\)
=>x=2
Tìm x, biết:
x.(2x-8).(x^2-4)=0
-17.|x|=-85
|x|=|-10|
3x + 5 = 4x - 9
72 - 3x=5x+8
(x^2 - 36).(2|x| - 12).x = 0
a)-5.(-x+7)-3.(-x-5)=-4.(12-x)+48
b) (-x-7)-5.(-x-3)=12.(3-x)
c)-2.(15-3x)-4.(7x+8)=-5-9.(-2x+1)
d) (-3x-7) - 4.(-2x-11)=7.(4x+10)+9
\(a,-5.\left(-x+7\right)-3.\left(-x-5\right)=-4.\left(12-x\right)+48\)
\(5x-35-3x+15=-48+4x+48\)
\(2x-10=4x\)
\(2x-4x=10\)
\(-2x=10\)
\(x=-5\)
\(b,\left(-x-7\right)-5.\left(-x-3\right)=12.\left(3-x\right)\)
\(-x-7+5x+15=36-12x\)
\(4x+8=36-12x\)
\(4x+12x=36-8\)
\(16x=28\)
\(x=1,75\)
các câu còn lại tương tự nha
Tìm x
a,-5×(-x+7)-3×(-x-5)=-4×(12-x)+48
b,-2×(15-3x)-4×(-7x+8)=,-5-9×(-2x+1)
c,7×(-x-7)-5×(-x-3)=12×(3-x)
d,5×(-3x-7)-4×(-2x-11)=7×(4x+10)+9
a ) \(-5\times\left(-x+7\right)-3\times\left(-x-5\right)=-4\times\left(12-x\right)+48\)
\(\Leftrightarrow5x-35+3x+15=-48+4x+48\)
\(\Leftrightarrow5x-3x+4x=35-15-48+48\)
\(\Leftrightarrow2x=20\)
\(\Leftrightarrow x=10\)
b ) \(-2\times\left(15-3x\right)-4\times\left(-7x+8\right)=-5-9\times\left(-2x+1\right)\)
\(\Leftrightarrow-30+6x-28x-32=-5+18x-9\)
\(\Leftrightarrow6x-28x-18x=30+32-5-9\)
\(\Leftrightarrow-40x=48\)
\(\Leftrightarrow x=-1.2\)
c, 7 . ( - x - 7 ) - 5 . ( - x - 3 ) = 12 . ( 3 - x)
<=> - 7x - 49 + 5x + 15 = 36 - 12x
<=> - 2x + 12x = 36 - 15 + 49
<=> 10 x = 70
<=> x = 7
Vẫy x = 7
d, 5 . ( - 3x - 7 ) - 4 . ( - 2x - 11 ) = 7 . ( 4x + 10) + 9
<=> - 15x + 8x + 44 = 28x + 70 + 9
<=> - 7x + 44 = 28x + 79
<=> - 7x - 28x = 79 - 44
<=> - 35x = 35
<=> x = - 1
Vậy x = - 1
Hc tốt
tìm x
a)-5.(-x+7)-3.(-x-5)=-4.(12-x)+48
b) (-x-7)-5.(-x-3)=12.(3-x)
c)-2.(15-3x)-4.(7x+8)=-5-9.(-2x+1)
d) (-3x-7) - 4.(-2x-11)=7.(4x+10)+9
Hướng dẫn cách làm:
B1:Bạn phá ngoặc ra
B2:Bạn chuyển hết x sang một bên(Nhớ sử dụng quy tắc chuyển vế đổi dấu)
B3:Bạn tính hai vế
(Áp dụng quy tắc chuyển vế đổi dấu)
(Hoặc)
B1:Bạn tính hai vế
B2:Chuyển hết x sang một vế
B3:Tính vế chứa x
(Áp dụng quy tắc lấy tiềnmở khóa cổng-mở khóa cửa-mở khóa két-thò tay vào lấy tiền)
P/s:Khi tìm x nhớ áp dụng hai quy tắc mình nói trên
a) -5.(-x+7)-3.(-x-5)= -4.(12-x)+48
5x - 35 +3x +15 = -48 + 4x +48
5x + 3x - 4x = 35 - 15 -48 + 48
2x = 20
x = 10
b) (-x-7)-5.(-x-3)= 12.(3-x)
-x-7+5x+15 = 36 -12x
-x + 5x +12x = 7 -15 +36
16x = 28
x = 1.75
c) -2.(15-3x)-4.(7x+8) = -5-9.(-2x+1)
-30 + 6x -28x -32 = -5 +18x -9
6x -28x - 18x = 30+32-5-9
-40x = 48
x = -1.2
d) (-3x-7)-4.(-2x-11)= 7.(4x+10)+9
-3x -7 + 8x + 44 = 28x+70 +9
-3x +8x-28x = 7-44 +70+9
-23x =42
x = -42/23
1) 10 -3 ( x -1 ) = -5
2) 3x + 75 = -15
3) 4x - 15 = -75 - x
4) 12 - ( x - 7 ) = -8
5) x + 75 = 15
6) x - 18 = 3x + 4
7) 2x + 18 = 10
8) 26 - 3x = 5
9) x - 12 = -15
10) 24 - 2 ( x + 5 ) = 38
11) 25 - 5 ( 3 - x ) = 15
12) x + ( -17 ) = -14
13) -5x - 13 = 47
14) 2x + 36 = -18
15) 9 . ( x + 7 ) - 12 = 24
Ai giải dùm mình nhanh nhất, đúng mình tick cho nha
1) 10 - 3 ( x - 1 ) = -5
3 ( x - 1 ) = 10 - ( - 5 )
3 ( x - 1 ) = 15
x - 1 = 15 : 3
x - 1 = 5
x = 5 + 1
x = 6
2) 3x + 75 = - 15
3x = - 15 - 75
3x = - 90
x = -90 : 3
x = -30
4) 12 - ( x - 7 ) = - 8
x - 7 = 12 - (- 8 )
x - 7 = 20
x = 20 + 7
x = 27
5) x + 75 = 15
x = 15 - 75
x = -60
7) 2x + 18 = 10
2x = 10 - 18
2x = -8
x = - 8 : 2
x = -4
8) 26 - 3x = 5
3x = 26 - 5
3x = 21
x = 21: 3
x = 7
9) x - 12 = - 15
x = -15 + 12
x =-3
10 ) 24 - 2 ( x + 5 ) = 38
2 ( x+ 5 ) = 24 - 38
2 ( x + 5 ) = - 14
x + 5 = -14 : 2
x + 5 = -7
x = -7 - 5
x = -12
còn là bạn tự làm tiếp nhé ! bạn gửi nhiều cầu qua bạn chỉ nên gửi ít một thời như vậy khó có thể giải làm bạn ạ!
25 - 5 (3- x) = 15
25 - 5 (3-x) = 15
5 (3-x) = 25 -15
5 (3-x) = 10
3 - x = 10 : 5
3 - x = 2
x = 3 - 2
x = 1
bài 1:
a)7x(x2-7x+3) b)(x+6)(x-7)
c)(x-8)2 d) (3x+2)2
e)(x-4)(x+4)-(5-x)2
Bài 2:
a)2(x-7)-9=10 b)(2x-5)2-x(4x-3)=2x+50
\(1,\\ a,=7x^3-49x^2+21x\\ b,=x^2-x-42\\ c,=x^2-16x+64\\ d,=9x^2+12x+4\\ e,=x^2-16-25+10x-x^2=10x-41\\ 2,\\ a,\Rightarrow2\left(x-7\right)=19\\ \Rightarrow x-7=\dfrac{19}{2}\Rightarrow x=\dfrac{33}{2}\\ b,\Rightarrow4x^2-20x+25-4x^2+3x-2x=50\\ \Rightarrow-19x=25\Rightarrow x=-\dfrac{25}{19}\)
Phân tích đa thức thành nhân tử:
a) x^2y + 2xy^2 + xy
b) x^3 + x^2 – 4x – 4
c) x^2 – 2x – 15
d) x^2 – 4 + (x – 2)^2
e) x^2 – y^2 + 2x + 1
g) (x + 9)^2 – 36x^2
h) x^2 – 2xy + y^2 – z^2 + 2zt – t^2
i) x^3 – 3x^2 + 3x – 1 – y^3
\(a,=xy\left(x+2y+1\right)\\ b,=x^2\left(x+1\right)-4\left(x+1\right)=\left(x+1\right)\left(x-2\right)\left(x+2\right)\\ c,=x^2-5x+3x-15=\left(x-5\right)\left(x+3\right)\\ d,=\left(x-2\right)\left(x+2\right)+\left(x-2\right)^2=\left(x-2\right)\left(x+2+x-2\right)=2x\left(x-2\right)\\ e,=\left(x+1\right)^2-y^2=\left(x+y+1\right)\left(x-y+1\right)\\ g,=\left(x+9-6x\right)\left(x+9+6x\right)=\left(9-5x\right)\left(7x+9\right)\\ h,=\left(x-y\right)^2-\left(z-t\right)^2=\left(x-y-z+t\right)\left(x-y+z-t\right)\\ i,=\left(x-1\right)^3-y^3=\left(x-y-1\right)\left(x^2-2x+1+xy+y+y^2\right)\)
c: =(x-5)(x+3)
e: =(x+1-y)(x+1+y)
Tìm x biết
a) (x+2).(x+3) - (x-2).(x+5)=10
b) (3x+2). (2x+9) - (x+2). (8x+11)=(x+1).(3-2x)
c) 3.(2x-1).(3x-1)-(2x-3).(9x-1)=0
d) (5x-8).(4x-5)-(3x-4).(2x+12)=12
a)(x+2).(x+3)-(x-2).(x+5)=10
( x^2 +3x+2x+6)-(x^2 +5x-2x-10)=10
x^2 +3x+2x+6-x^2 -5x+2x+10-10=0
2x+6=0
2x=-6
x=-3