\(3x\left(x-1\right)+2\left(1-x\right)=0.\)

\(\Leftrightarrow3x\left(x-1\right)-2\left(x-1\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(3x-2\right)=0\)

\(\Rightarrow x=1\) hoặc \(x=\frac{2}{3}\)

=>x(x^2-9/16)=0

=>x(x-3/4)(x+3/4)=0

=>x=0; x=3/4; x=-3/4

1)

xy=2

=>x=1 thì y =2   ;   x=2 thì y=1

2)

xy=42

=>Ư(42)={1;2;3;6;7;14;21;42}

vì x>y

nên x=42 thì y=1 

x=14 thì y=3

x=21 thì y=2

x=7 thì y=6

3)

ta có xy=35

=> Ư(35)={1;;5;7;35}

vì x<y 

nên x=1 thì y=35

x=5 thì y=7

cảm ơn nha !

\(5x\left(x-3\right)=x-3\)

\(\Rightarrow5x\left(x-3\right)-\left(x-3\right)=0\)

\(\Rightarrow\left(x-3\right)\left(5x-1\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x-3=0\\5x-1=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=3\\x=\frac{1}{5}\end{cases}}}\)

a)\(2x\left(x-2016\right)-2x+4032=0\)

\(\Leftrightarrow2x\left(x-2016\right)-2\left(x-2016\right)=0\)

\(\Leftrightarrow\left(2x-2\right)\left(x-2016\right)=0\)

\(\Leftrightarrow2\left(x-1\right)\left(x-2016\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x-1=0\\x-2016=0\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=1\\x=2016\end{array}\right.\)

b)\(5x\left(x-3\right)=x-3\)

\(\Leftrightarrow5x\left(x-3\right)-\left(x-3\right)=0\)

\(\Leftrightarrow\left(x-3\right)\left(5x-1\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x-3=0\\5x-1=0\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=3\\x=\frac{1}{5}\end{array}\right.\)

c)\(\left(3x-1\right)^2=\left(x+2\right)^2\)

\(\Leftrightarrow\left(3x-1\right)^2-\left(x+2\right)^2=0\)

\(\Leftrightarrow\left(3x-1+x+2\right)\left[\left(3x-1\right)-\left(x+2\right)\right]=0\)

\(\Leftrightarrow\left(4x+1\right)\left(2x-3\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}4x+1=0\\2x-3=0\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-\frac{1}{4}\\x=\frac{3}{2}\end{array}\right.\)

11 x ( X - 5 ) = 5 x X + 11

11 x X - 11 x 5 = 5 x X + 11

11 x X - 55 = 5 x X + 11

11 x X - 55 - 11 = 5 x X

11 x X - ( 55 + 11 ) = 5 x X

11 x X - 66 = 5 x X

Vậy 66 tương ứng với :

11 - 5 = 6 lần X

X = 66 : 6 = 11

11 x (X - 5) = 5X + 11

11X - 55 = 5X + 11

11X - 5X = 11 + 55

6X = 66

X = 66:6

X = 11

toán 5 chưa được viết tắt là 5X mà b

1. 

\(\left(12x^2+6x\right)\left(y+z\right)+\left(12x^2+6x\right)\left(y-z\right)\\ =\left(12x^2+6x\right)\left(y+z+y-z\right)\\ =2y\left(12x^2+6x\right)\\ =2y.6x\left(2x+1\right)\\ =12xy\left(2x+1\right)\)

2. 

\(x\left(x-6\right)+10\left(x-6\right)=0\\ \Leftrightarrow\left(x-6\right)\left(x+10\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=6\\x=-10\end{matrix}\right.\)

Vậy \(x\in\left\{6;-10\right\}\) là nghiệm của pt

Bài 1:

Ta có: \(\left(12x^2+6x\right)\left(y+z\right)+\left(12x^2+6x\right)\left(y-z\right)\)

\(=\left(12x^2+6x\right)\left(y+z+y-z\right)\)

\(=6x\left(2x+1\right)\cdot2y\)

\(=12xy\left(2x+1\right)\)

Bài 2: 

Ta có: \(x\left(x-6\right)+10\left(x-6\right)=0\)

\(\Leftrightarrow\left(x-6\right)\left(x+10\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=6\\x=-10\end{matrix}\right.\)

\(x^3+9x^2+27x+26=0\)

\(\Leftrightarrow\left(x+2\right)\left(x^2+7x+13\right)=0\Rightarrow x=-2\)

\(x^3+9x^2+27x+26=0\)

\(\Leftrightarrow x^3+9x^2+27x+27=1\)

\(\Leftrightarrow\left(x+3\right)^3=1^3\)

\(\Leftrightarrow x+3=1\Leftrightarrow x=-2\)

k bt bn có ghi sai đề hông nhưng mà mik xin phép sửa đề

\(x^3+9x^2+27x+27=0\)

\(x^3+3x^2.3+3x.3^2+3^3=0\)

\(\Rightarrow x+3=0\)

\(x=-3\)

Vậy