a)\(x^2-6xy+9y^2-25z^2=\left[x^2-2.x.3y+\left(3y\right)^2\right]-\left(5z\right)^2\)

\(=\left(x-3y\right)^2-\left(5z\right)^2=\left(x-3y-5z\right)\left(x-3y+5z\right)\)

b)\(xyz+x^2yz-6yz=yz\left(x^2+x-6\right)=yz\left(x^2+3x-2x-6\right)\)

\(=yz\left[x\left(x+3\right)-2\left(x+3\right)\right]=yz\left(x-2\right)\left(x+3\right)\)

a.x²-6xy+9y²​-25z^​2

​= ( x^​2-6xy+9y²)-25z²

​= [x^​2-2x3y+(3y)²]-25z²​

​= (x-3y)²-25²

​= (x-3y+25)(x-3y-25)

Câu 1: 3x² - 6xy + 3y² - 12z²

= 3(x² - 2xy + y² - 4z²)

= 3[(x² -2xy+y²)- (2z)²]

= 3[(x-y)² - (2z)²]

=3(x-y-2z)(x-y +2z)

Câu 2: x² - 6xy - 25z²+ 9y²

= x² - 2x.3y + (3y)² - (5z)²

= (x-3y)² - (5z)²

= (x-3y-5z)(x-3y+5z) 

\(5x^2-10xy+5y^2-20z^2=5\left(x^2-2xy+y^2-4z^2\right)=5.\left[\left(x-y\right)^2-\left(2z\right)^2\right]=5.\left(x-y-2z\right).\left(x-y+2z\right)\)

\(x^2-z^2+y^2-2xy=\left(x-y\right)^2-z^2=\left(x-y+z\right)\left(x-y-z\right)\)

\(x^2-2xy-4z^2+y^2=\left(x-y\right)^2-4z^2=\left(x-y-2z\right)\left(x-y+2z\right)\)

a) 5x² - 10xy + 5y²

= 5 (x² - 2xy + y²)

= 5 (x - y)²

b) x² - z² + y² - 2xy

= (x² + y² - 2xy) - z²

= (x² - 2xy + y²) - z²

= (x - y)² - z²

= (x - y + z)(x - y - z)

c) x² - 6xy - 25z² : hinh nhu de bi sai , ban xem lai giup minh

d) x² - 2xy - 4z² + y²

= (x² - 2xy + y²) - 4z²

= (x - y)² - (2z)²

= (x - y + 2z)(x - y - 2z)

 Chuc ban hoc tot

mình k ghi lại đề nha bạn

\(=\left(x-y\right)^2-16z^2\\ =\left(x-y-4z\right)\left(x-y+4z\right)\)

x²-6xy+9y²-16z²

=[x²-2.3xy+(3y)²]-16z²

=[x-3y]²-[4y]²

=[x-3y-3z][x-3y+3z]

Lời giải trước mk đánh nhầm nha

x²-6xy+9y²-16z²

=[x²-2.3xy+(3y)²]-16z²

=[x-3y]²-[4z]²

=[x-3y-4z][x-3y+4z]

x²-6xy+9y²-36 =(x²-6xy+9y²)-36 =(x-3y)²-6² =(x-3y+6)(x-3y-6)

=[x²-6xy+(3y)²-49]

=[(x-3y)²-7²]

=(x-3y-7)*(x+3y+7)

= x^2 - 6xy + 9y^2 - 49

= x^2 - 6xy + ( 3y )^2 - 49

= (x - 3y)^2 - 7^2

= (x - 3y -7)( x-3y +7) tk cho mk nha

\(x^2-49-6xy+9y^2\)

\(=\left(x^2-6xy+9y^2\right)-7^2\)

\(=\left(x-3y\right)^2-7^2\)

\(=\left(x-3y-7\right)\left(x-3y+7\right)\)

k mk nha ^_^

a) \(x^3+8y^3+4x+8y\)

\(=x^3-2x^2y+4xy^2+4x+2x^2y-4xy^2+8y^3+8y\)

\(=\left(x^3-2x^2y+4xy^2+4x\right)+\left(2x^2y-4x^2y+8y^3+8y\right)\)

\(=x\left(x^2-2xy+4y^2+4\right)+2y\left(x^2-2xy+4y^2+4\right)\)

\(=\left(x^2-2xy+4y^2+4\right)\left(x+2y\right)\)

b) \(x^2+6xy+9y^2+5x+15y\)

\(=\left(x^2+6xy+9y^2\right)+\left(5x+15y\right)\)

\(=\left(x+3y\right)^2+5\left(x+3y\right)\)

\(=\left(x+3y\right)\left(x+3y+5\right)\)

c) \(25-x^2+2xy-y^2\)

\(=25-\left(x^2-2xy+y^2\right)\)

\(=25-\left(x-y\right)^2\)

\(=5^2-\left(x-y\right)^2\)

\(=\left(5+x-y\right)\left(5-x+y\right)\)

`x^3+8y^3 +4x+8y`

`=(x+2y)(x^2 - 2xy + 4y^2 ) +4 (x+2y)`

`= (x+2y) (x^2 -2xy +4y^2 +4)`

__

`x^2 +6xy +9y^2 +5x+15y`

`= (x+3y)^2 + 5(x+3y)`

`=(x+3y)( x+3y +5)`

__

`25-x^2 +2xy -y^2`

`= 25 - (x^2 -2xy+y^2)`

`=25-(x-y)^2`

`=(5-x+y)(5+x-y)`

a. \(x^2-y^2=\left(x-y\right)\left(x+y\right)\)

b. \(x^2-6xy+9y^2-36=\left(x-3y\right)^2-6^2=\left(x-3y-6\right)\left(x-3y+6\right)\)

a: \(x^2-y^2=\left(x-y\right)\left(x+y\right)\)

b: \(x^2-6xy+9y^2-36=\left(x-3y\right)^2-6^2=\left(x-3y-6\right)\left(x-3y+6\right)\)

a) Ta có: \(x^2y^2-x^2+6xy-9y^2\)

\(=x^2y^2-\left(x^2-6xy+y^2\right)\)

\(=\left(xy\right)^2-\left(x-3y\right)^2\)

\(=\left(xy-x+3y\right)\left(xy+x-3y\right)\)

b) Ta có: \(9-x^2+2xy-y^2\)

\(=9-\left(x^2-2xy+y^2\right)\)

\(=9-\left(x-y\right)^2\)

\(=\left(9-x+y\right)\left(9+x-y\right)\)