16. 7 x − 16. 5 2 x  = 0

⇔  7 x  =  5 2 x  ⇔  7 / 25 x  =  7 / 25 0  ⇔ x = 0

Ta có: \(100< 5^{2x-1}\le5^6\)

\(\Leftrightarrow5^2< 5^{2x-1}\le5^6\)

\(\Leftrightarrow2x-1\in\left\{3;5\right\}\)

\(\Leftrightarrow2x\in\left\{4;6\right\}\)

hay \(x\in\left\{2;3\right\}\)

Ta có: 100 < 52x – 1 < 56

=> 52 < 100 < 52x-1 < 56

=> 2 < 2x – 1 < 6

=> 2 + 1 < 2x < 6 + 1

=> 3 < 2x < 7

Vì x ∈ N nên suy ra: x ∈ {2; 3} là thỏa mãn.

Ta có 100=5².4

\(\Rightarrow5^3\le5^{2x-1}< 5^6\)

\(\Rightarrow3\le2x-1< 6\)

\(\Rightarrow4\le2x< 7\)

\(\Rightarrow2\le x< 3,5\)

Mà \(x\) là số tự nhiên

\(\Rightarrow x=2\) hoặc \(x=3\)

x ϵ {2;3}

\(5^{2x-1}=125\cdot5^4\)

\(\Leftrightarrow2x-1=7\)

hay x=4

x=3

\(\Rightarrow5^{2x-3}=5^2\cdot3+5^2\cdot2=5^2\cdot5=5^3\\ \Rightarrow2x-3=3\\ \Rightarrow x=3\)

5^2x-3-10=75

5^2x-3=85

\(5^{2x-3}-2.5^2=5^2.3\)

\(\Rightarrow5^{2x-3}-50=75\)

\(\Rightarrow5^{2x-3}=125=5^3\)

\(\Rightarrow2x-3=3\Rightarrow2x=6\Rightarrow x=3\)

Tham Khảo]

(5^2x.5^x+2) : 25 = 125²

5^2x.5^x+2 = 125².25 = 5⁶.5²

5^2x+x+2 = 5⁸

5^3x+2 = 5⁸

=> 3x + 2 = 8

=> 3x = 6

=> x = 2

Ta có: \(\left(5^{2x}\cdot5^{x+2}\right):25=125^2\)

\(\Leftrightarrow5^{3x+2}=5^6\cdot5^2=5^8\)

hay x=2

5^2x-3-2.5² =5² . 3

⇔5^2x-1.5²-2.5²=5².3

⇔5².(5^2x-1-2)=5².3

⇔5^2x-1-2=3

⇔5^2x-1=5

⇔2x-1=1

⇔2x=2

⇔x=1

vay x=1

af nham mink sai :>