\(\Leftrightarrow\left(\dfrac{x-1}{99}-1\right)+\left(\dfrac{x-99}{1}-1\right)+\left(\dfrac{x-3}{97}-1\right)+\left(\dfrac{x-97}{3}-1\right)+\left(\dfrac{x-5}{95}-1\right)+\left(\dfrac{x-95}{5}-1\right)=0\)

=>x-100=0

=>x=100

\(\Leftrightarrow\left(\dfrac{x-1}{99}-1\right)+\left(\dfrac{x-99}{1}-1\right)+\left(\dfrac{x-3}{97}-1\right)+\left(\dfrac{x-7}{93}-1\right)+\left(\dfrac{x-5}{95}-1\right)+\left(\dfrac{x-95}{5}-1\right)=0\)=>x-100=0

hay x=100

ai tick mình mình tick cho100 cái nhé!!!

a) x + (-5) = 6

x = 6 -(-5) = 11

b) -5.6 = x

x = -5.6 = -30

c) -95-  95 = x

x = -95 - 95 = -190

a,x+-5=6

   x     =6--5

    x    =11

b,-5.6=x

    -30=x

c,-95-95=x

    -190=x

tick nha

\(\left(x+9\right)+\left(x-2\right)+\left(x+7\right)+\left(x-4\right)+\left(x+5\right)+\left(x-6\right)+\left(x+3\right)+\left(x-8\right)+\left(x+1\right)=95\)

\(x+9+x-2+x+7+x-4+x+5+x-6+x+3+x-8+x+1=95\)

\(\left(x\times9\right)+\left(9-2+7-4+5-6+3-8+1\right)=95\)

\(x\times9+5=95\)

\(x\times9=95-5\)

\(x\times9=90\)

\(x=90:9\)

\(x=10\)

(x + 9) + (x - 2) + (x + 7) + (x - 4) + (x + 5) + (x - 6) + (x + 3) + (x - 8) + (x + 1) = 95

x + 9 + x - 2 + x + 7 + x - 4 + x + 5 + x - 6 + x + 3 + x - 8 + x + 1

(x + x + x + x + x + x + x + x + x) + (9 - 8 + 7 - 6 + 5 - 4 + 3 - 2 + 1) = 95

9 × x + 5 = 95

9 × x = 95 - 5

9 × x = 90

x = 90 : 9

x = 10

$\left(x+9\right)+\left(x-2\right)+\left(x+7\right)+\left(x-4\right)+\left(x+5\right)+\left(x-6\right)+\left(x+3\right)+\left(x-8\right)+\left(x+1\right)=95$

$x+9+x-2+x+7+x-4+x+5+x-6+x+3+x-8+x+1=95$

$\left(x\times 9\right)+\left(9-2+7-4+5-6+3-8+1\right)=95$

$x\times 9+5=95$

$x\times 9=95-5$

$x\times 9=90$

$x=90:9$

$x=10$

14 và 19

. Cám ơn bợn những tớ cũng cần cách trình bày nữa :3

ta có : x+6+95+100 chia hết cho 5

=> x+6 chia hết cho 5

=> x+6 thuộc B(5)

 mà B(5)= 0;5;10;15;20;25;30;...

=> x+6= 0;5;10;15;20;25;30;...

=> x= 4;9;14;19;22;...

mà 12<x<22

=> x=14;19