Đề bài là:Tìm x:(1/1*2+1/1*3+1/3*4+...+1/8*9+1/9*10)*100-(5/2÷(x+206/100)÷1/2)=89
Những câu hỏi liên quan
Tìm x: (1/1×2+1^2×3+1/3×4+........+1/8×9+1/9×10) ×100-[5/2÷(x+206/100)÷1/2]=89
( 1/1x2 + 1/2x3 + 1/3x4 + ... + 1/9/10 ) x 100 - ( 5/2 : ( x + 206/100 ) : 1/2 = 89
bài 1 Tính nhanh
A=1+2-3-4+5+6-7-8+9+10-........................................................
Bài 2 Tìm x
a) (x-8)ngũ 5= (x-8)ngũ 9
b) (x+1)+(x+2)+................+(x+100)=5750
c) 1+2+3+.......................+x=820
Bài 1 :
\(A=1+2+3+4+5+6+7+8+9\)
\(=\left(1+9\right)+\left(2+8\right)+\left(3+7\right)+\left(4+6\right)+5\)
\(=10+10+10+10+5\)
\(=45\)
Bài 2 bạn tự làm nha
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Bài 2 : Tìm x :
a) ( x - 8 )5 = ( x - 8 )9
=> x - 8 thuộc { 0 ; 1 } vì :
Nếu x - 8 = 0 thì ( x - 8 )5 = 05 = 0
Nếu x - 8 = 0 thì ( x - 8 )9 = 09 = 0
Vậy x - 8 = 0 là thỏa mãn điều kiện.
Nếu x - 8 = 1 thì ( x - 8 )5 = 15 = 1
Nếu x - 8 = 1 thì ( x - 8 )9 = 19 = 1
Vậy x - 8 = 1 là thỏa mãn điều kiện.
=> x - 8 thuộc { 0 ; 1 }
=> x thuộc { 8 ; 9 }
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Bài 2 : Tìm x :
b) ( x + 1 ) + ( x + 2 ) +.....+ ( x + 100 ) = 5750
100x + ( 1 + 2 + 3 + 4 + .....+ 100 ) = 5750
100x + 5050 = 5750
100x = 5750 - 5050
100x = 700
x = 700 : 100
x = 7
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Xem thêm câu trả lời
a)(1/2 + 1/6 + 1/12 +...+1/90) . 100 - [5/2 : ( x + 206/100 )] : 1/2= 89
b) x9,85 + x0,15 = 0,1
c) 2/5 + 2022x = 4/10
giúp mình, 2h mình đi học r
a) \(\left(\dfrac{1}{2}+\dfrac{1}{6}+...+\dfrac{1}{90}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+...+\dfrac{1}{9\cdot10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\left(1-\dfrac{1}{2}+\dfrac{1}{2}-...+\dfrac{1}{9}-\dfrac{1}{10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\left(1-\dfrac{1}{10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\dfrac{9}{10}\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow90-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)=90-89\)
\(\Rightarrow\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)=1\)
\(\Rightarrow x+\dfrac{103}{50}=\dfrac{5}{2}\)
\(\Rightarrow x=\dfrac{11}{25}\)
b) \(x\cdot9,85+x\cdot0,15=0,1\)
\(\Rightarrow x\cdot\left(9,85+0,15\right)=0,1\)
\(\Rightarrow x\cdot10=0,1\)
\(\Rightarrow x=\dfrac{0,1}{10}\)
\(\Rightarrow x=0,01\)
c) \(\dfrac{2}{5}+2022x=\dfrac{4}{10}\)
\(\Rightarrow\dfrac{2}{5}+2022x=\dfrac{2}{5}\)
\(\Rightarrow2022x=\dfrac{2}{5}-\dfrac{2}{5}\)
\(\Rightarrow2022x=0\)
\(\Rightarrow x=\dfrac{0}{2022}\)
\(\Rightarrow x=0\)
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a) \(\left(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{90}\right).100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\left(1\right)\)
Ta có :
\(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+...+\dfrac{1}{90}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}\)
\(=1-\dfrac{1}{10}=\dfrac{9}{10}\)
\(\left(1\right)\Rightarrow\dfrac{9}{10}.100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow90-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right].2=89\)
\(\Rightarrow\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right].2=90-89\)
\(\Rightarrow\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)=\dfrac{1}{2}\)
\(\Rightarrow x+\dfrac{206}{100}=\dfrac{5}{2}:\dfrac{1}{2}\)
\(\Rightarrow x+\dfrac{103}{50}=\dfrac{5}{2}.\dfrac{2}{1}\)
\(\Rightarrow x+\dfrac{103}{50}=5\)
\(\Rightarrow x=5-\dfrac{103}{50}\)
\(\Rightarrow x=\dfrac{250}{50}-\dfrac{103}{50}\)
\(\Rightarrow x=\dfrac{147}{50}\)
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Tìm X:
a,2xX-5=21
b,3/4+1/4xX=5/6
c,7/8-1/2xX=5/6
d(1/1x2+1/2x3+1/3x4)x100-[5/2:(X+206/100)]:1/2=89
\(a)\) \(2x-5=21\)
\(\Leftrightarrow\) \(2x=21+5\)
\(\Leftrightarrow\) \(2x=26\)
\(\Leftrightarrow\) \(x=26:2\)
\(\Leftrightarrow\) \(=13\)
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\(b)\) \(\frac{3}{4}+\frac{1}{4}x=\frac{5}{6}\)
\(\Leftrightarrow\) \(\frac{1}{4}x=\frac{5}{6}-\frac{3}{4}\)
\(\Leftrightarrow\) \(\frac{1}{4}x=\frac{1}{12}\)
\(\Leftrightarrow\) \(x=\frac{1}{3}\)
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\(c)\) \(\frac{7}{8}-\frac{1}{2}x=\frac{5}{6}\)
\(\Leftrightarrow\) \(\frac{1}{2}x=\frac{7}{8}-\frac{5}{6}\)
\(\Leftrightarrow\) \(\frac{1}{2}x=\frac{1}{24}\)
\(\Leftrightarrow\) \(x=\frac{1}{12}\)
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Xem thêm câu trả lời
Xắp xếp theo thứ tự từ bé đến lớn ( a, 2 like ; b , 2 like ; c , 1like )a , 1 giờ ; 3 giờ 20 phút : 2 ; 3 giờ ; 10 phút 5 giây ; 8 giờ ; 3,5 giờ ; 2,5 giờ ; 5 phút ; 4 giờ 10 phút ; 10,5 phút ; 2 giờ 15 phút ; 90 phút ; 4 giờ 5 phút ; 20 phút ; 4,2 giờ ; 1 phút ; 4 giờ ; 0,5 giờ ; 5 giờb , 9/100 ; 9/89 ; 9/74 ; 9/68 ; 1/5 ; 9/61 ; 0,07 ; 1/7 ; 9/57 ; 1,9 ; 9/93 ; 1/4 ; 1,58 ; 1,79 ; 1,69 ; 9/92 ; 3/5 ; 8/9 ; 1,63 ; 12/11 c ,0,16 ; 0,35 ; 0,54 ; 0,71 ; 1,56 ; 9/100 ; 17/100 ; 31/100 ; 31/100 ; 27...
Đọc tiếp
Xắp xếp theo thứ tự từ bé đến lớn ( a, 2 like ; b , 2 like ; c , 1like )
a , 1 giờ ; 3 giờ 20 phút : 2 ; 3 giờ ; 10 phút 5 giây ; 8 giờ ; 3,5 giờ ; 2,5 giờ ; 5 phút ; 4 giờ 10 phút ; 10,5 phút ; 2 giờ 15 phút ; 90 phút ; 4 giờ 5 phút ; 20 phút ; 4,2 giờ ; 1 phút ; 4 giờ ; 0,5 giờ ; 5 giờ
b , 9/100 ; 9/89 ; 9/74 ; 9/68 ; 1/5 ; 9/61 ; 0,07 ; 1/7 ; 9/57 ; 1,9 ; 9/93 ; 1/4 ; 1,58 ; 1,79 ; 1,69 ; 9/92 ; 3/5 ; 8/9 ; 1,63 ; 12/11
c ,0,16 ; 0,35 ; 0,54 ; 0,71 ; 1,56 ; 9/100 ; 17/100 ; 31/100 ; 31/100 ; 27/100 ; 43/100 ; 0,1 ; 1,6 ; 117/100 ; 0,4 ; 1,2 ; 45/100 ; 15/10 ; 163/100 ; 63/100 ; 95/100
Tìm x,biết:
(dfrac{1}{1.2} + dfrac{1}{2.3} + dfrac{1}{3.4} + ........ + dfrac{1}{8.9} + dfrac{1}{9.10}) . 100 - [ dfrac{5}{2} : (x+dfrac{206}{100}) ] : dfrac{1}{2} 89
(Dấu . trong bài là dấu nhân ạ)
Đọc tiếp
Tìm x,biết:
(\(\dfrac{1}{1.2}\) + \(\dfrac{1}{2.3}\) + \(\dfrac{1}{3.4}\) + ........ + \(\dfrac{1}{8.9}\) + \(\dfrac{1}{9.10}\)) . 100 - [ \(\dfrac{5}{2}\) : (\(x+\dfrac{206}{100}\)) ] : \(\dfrac{1}{2}\) = 89
(Dấu . trong bài là dấu nhân ạ)
\(\left(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+...+\dfrac{1}{8.9}+\dfrac{1}{9.10}\right).100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{8}-\dfrac{1}{9}+\dfrac{1}{9}-\dfrac{1}{10}\right).100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\left(1-\dfrac{1}{10}\right).100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\left(100-10\right)-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow90-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Rightarrow\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=1\)
\(\Rightarrow\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)=1.2=2\)
\(\Rightarrow\left(x+\dfrac{206}{100}\right)=\dfrac{5}{2}:2=\dfrac{5}{2}.\dfrac{1}{2}=\dfrac{5}{4}\)
\(\Rightarrow x=\dfrac{5}{4}-\dfrac{206}{100}=\dfrac{125}{100}-\dfrac{206}{100}\)
\(\Rightarrow x=-\dfrac{81}{100}\)
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(1/1.2+1/2.3+1/3.4+.......+1/8.9+1/9.10) .100-(5/2:(x +206/100):1/2=89
Ta có: \(\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{8\cdot9}+\dfrac{1}{9\cdot10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Leftrightarrow100\left(\dfrac{1}{1}-\dfrac{1}{10}\right)-\left[\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)\right]\cdot2=89\)
\(\Leftrightarrow\dfrac{5}{2}:\left(x+\dfrac{103}{50}\right)=\dfrac{1}{2}\)
\(\Leftrightarrow x+\dfrac{103}{50}=5\)
hay \(x=\dfrac{147}{50}\)
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Tìm X trong biểu thức sau
( 1/1,2 + 1/2,3 + 1/3,4 + ... + 1/8,9 + 1/9,10 ) * 100 - [ 5/2 : ( x + 206/100) ] : 1/2 = 89
Ta có: \(\left(\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+...+\dfrac{1}{8\cdot9}+\dfrac{1}{9\cdot10}\right)\cdot100-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Leftrightarrow100\cdot\left(1-\dfrac{1}{10}\right)-\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=89\)
\(\Leftrightarrow\left[\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)\right]:\dfrac{1}{2}=1\)
\(\Leftrightarrow\dfrac{5}{2}:\left(x+\dfrac{206}{100}\right)=2\)
\(\Leftrightarrow x+\dfrac{103}{50}=\dfrac{5}{4}\)
hay \(x=\dfrac{331}{100}\)
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