a, = 3.25 + 15.4 - 16 : 2 = 75 + 60 - 8 = 135 - 8 = 127

a: =75+60-8=127

\(a,3^3+3^2-\left(2^7:2^5+7^8:7^7\right)=27+9-\left(2^2+7\right)=36-11=25\)

\(b,27.77+27.27-27=27\left(77+27-1\right)=27.103=2781\)

\(c,52:\left(43-30\right)+144-16=52:13+128=4+128=132\)

\(f,3^2.101-3^2.101^0=3^2\left(101-101^0\right)=9\left(101-1\right)=9.100=900\)

a.=27+9-(2^2+7^1)                                                 =36-(4+7)                                                               =36-11                                                                   =25

3³+3²-(2⁷:2⁵+7⁸:7⁷)

=27+9-(2²+7)

=36-(4+7)

=36-11

=25

b.bạn tự lm nha

c.52:(43-30)+144-16

=52:13+144-16

=4+144-16

=148-16

=132

d.174:{2[36+(4²-23)]}

=174:{2[36+(16-23)]}

=174:{2[36+-7]}

=174:{2.29}

=174:58

=3

Giúp mink vs ~

a) \(\frac{4}{3}-\frac{2}{5}\)

\(=\frac{20}{15}-\frac{6}{15}=\frac{14}{15}\)

b) \(\left|-\frac{1}{10}\right|-\left(-\frac{1}{3}\right)^2\div\frac{5}{9}\)

\(=\frac{1}{10}-\frac{1}{9}\cdot\frac{9}{5}\)

\(=\frac{1}{10}-\frac{1}{5}=\frac{1}{10}-\frac{2}{10}\)

\(=-\frac{1}{10}\)

c) Đề bài có vấn đề!!!

d) \(\left(-0,2\right)^2\cdot5-8^2\cdot\frac{9^4}{3^7}\cdot4^3\)

\(=0,04\cdot5-64\cdot\frac{\left(3^2\right)^4}{3^7}\cdot64\)

\(=0,2-4096\cdot\frac{3^8}{3^7}=0,2-4096\cdot3\)

\(=0,2-12288=-128878\)

a: \(=15x^5-25x^4+15x^3\)

b: \(=2x^3+10x^2-8x-x^2-5x+4\)

\(=2x^3+9x^2-13x+4\)

\(a,3^6:3^5=3^{6-5}=3\\ b,5^7:5^5=5^{7-5}=5^2=25\\ c,14^5:2^3:7^4=\left(2^5:2^3\right)\cdot\left(7^5:7^4\right)=2^2\cdot7=28\\ d,5^4-2\cdot5^3=5^3\left(5-2\right)=3\cdot5^3=375\)

a) 3^6 : 3^5 = 729 : 243 = 3

b) 5^7 : 5^5 = 78125 : 3125 = 25

c) 14^5 : 2^3 : 7^4 = 537824 : 8 : 2401 = 89

d) 5^4 - 2 * 5^3 = 625 - 2 * 125 = 625 - 250 = 375

\(a,3^6:3^5=3^{6-5}=3^1=3\\ b,5^7:5^5=5^{7-5}=5^2=25\\ c,14^5:2^3:7^4=\left(2^5:2^3\right).\left(7^5:7^4\right)=2^{5-3}.7^{5-4}=2^2.7^1=4.7=28\\ d,5^4-2.5^3=5.5^3-2.5^3=\left(5-2\right).5^3=3.5^3=3.125=375\)

\(a,=4x^2-4x+1-4x^2+4-x^2-x+6=-x^2-5x+11\\ b,=8x^3+27-8x^3+72x=72x+27\)

a) \(=4x^2-4x+1-4\left(x^2-1\right)-\left(x^2-2x+3x-6\right)=4x^2-4x+1-4x^2+4-x^2-x+6=-x^2-5x+11\)

b) \(=8x^3+27-8x\left(x^2-9\right)=8x^3+27-8x^3+72x=72x+27\)