A= \(\frac{x^2+3}{x^2-9}\)+ \(\frac{2}{x+3}\)- \(\frac{1}{x-3}\) (x \(\ge\)0 ; x \(\ne\)9)
a.Rút gọn A
b.Tìm x, A= \(\frac{x+1}{x+2}\)
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Rút gọn:
a, A frac{sqrt{x}}{sqrt{x}-6}-frac{3}{sqrt{x}+6}+frac{x}{36-x} (đk: x ≥ 0 và x ≠ 36)
b, B frac{9-x}{sqrt{x}+3}-frac{x-6sqrt{x}+9}{sqrt{x}-3}-6 (đk: x ≥ 0 và x ≠ 9)
c, C frac{a+b}{left(sqrt{a}-sqrt{b}right)^2}-frac{2}{sqrt{ab}}:left(frac{1}{sqrt{a}}-frac{1}{sqrt{b}}right)^2 (đk: a 0, b 0 và a ≠ b)
d, D left(frac{2-asqrt{a}}{2-sqrt{a}}+sqrt{a}right)left(frac{2-sqrt{a}}{2-a}right) (đk: a ≥ 0, a ≠ 2, a ≠ 4)
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Rút gọn:
a, A = \(\frac{\sqrt{x}}{\sqrt{x}-6}-\frac{3}{\sqrt{x}+6}+\frac{x}{36-x}\) (đk: x ≥ 0 và x ≠ 36)
b, B = \(\frac{9-x}{\sqrt{x}+3}-\frac{x-6\sqrt{x}+9}{\sqrt{x}-3}-6\) (đk: x ≥ 0 và x ≠ 9)
c, C = \(\frac{a+b}{\left(\sqrt{a}-\sqrt{b}\right)^2}-\frac{2}{\sqrt{ab}}:\left(\frac{1}{\sqrt{a}}-\frac{1}{\sqrt{b}}\right)^2\) (đk: a > 0, b > 0 và a ≠ b)
d, D = \(\left(\frac{2-a\sqrt{a}}{2-\sqrt{a}}+\sqrt{a}\right)\left(\frac{2-\sqrt{a}}{2-a}\right)\) (đk: a ≥ 0, a ≠ 2, a ≠ 4)
\(B=\frac{9-x}{\sqrt{x}+3}-\frac{x-6\sqrt{x}+9}{\sqrt{x}-3}-6\)(đk: x ≥ 0 và x ≠ 9)
\(B=\frac{\left(3-\sqrt{x}\right)\left(3+\sqrt{x}\right)}{\sqrt{x}+3}-\frac{\left(\sqrt{x}-3\right)^2}{\sqrt{x}-3}-6\)
\(B=\left(3-\sqrt{x}\right)-\left(\sqrt{x}-3\right)-6\)
\(B=3-\sqrt{x}-\sqrt{x}+3-6\)
\(B=-2\sqrt{x}\)
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\(A=\frac{\sqrt{x}}{\sqrt{x}-6}-\frac{3}{\sqrt{x}+6}+\frac{x}{36-x}\)(đk: x ≥ 0 và x ≠ 36)
\(=\frac{\sqrt{x}}{\sqrt{x}-6}-\frac{3}{\sqrt{x}+6}-\frac{x}{x-36}\)
\(=\frac{\sqrt{x}}{\sqrt{x}-6}-\frac{3}{\sqrt{x}+6}-\frac{x}{x-36}\)
\(=\frac{\sqrt{x}\left(\sqrt{x}+6\right)-3\left(\sqrt{x-6}\right)-x}{(\sqrt{x}-6)\left(\sqrt{x}+6\right)}\)
\(=\frac{x+6\sqrt{x}-3\sqrt{x}+18-x}{(\sqrt{x}-6)\left(\sqrt{x}+6\right)}\)
\(=\frac{3\sqrt{x}+18}{(\sqrt{x}-6)\left(\sqrt{x}+6\right)}\)
\(=\frac{3(\sqrt{x}+6)}{(\sqrt{x}-6)\left(\sqrt{x}+6\right)}\)
\(=\frac{3}{\sqrt{x}-6}\)
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a) Rút gọn biểu thức sau A=\(\sqrt{3+2\sqrt{2}}-\frac{1}{1+\sqrt{2}}\)
b)Chứng minh rằng:\(\left(\frac{\sqrt{x}}{\sqrt{x}+3}+\frac{3}{\sqrt{x}-3}\right).\frac{\sqrt{x}+3}{x+9}=\frac{1}{\sqrt{x}-3}\)với x≥0 và x ≠ 9
a) Ta có: \(A=\sqrt{3+2\sqrt{2}}-\frac{1}{1+\sqrt{2}}\)
\(=\sqrt{1+2\cdot1\cdot\sqrt{2}+2}-\frac{1}{1+\sqrt{2}}\)
\(=\sqrt{\left(1+\sqrt{2}\right)^2}-\frac{1}{1+\sqrt{2}}\)
\(=1+\sqrt{2}-\frac{1}{1+\sqrt{2}}\)
\(=\frac{\left(1+\sqrt{2}\right)^2}{1+\sqrt{2}}-\frac{1}{1+\sqrt{2}}\)
\(=\frac{1+2\sqrt{2}+2-1}{1+\sqrt{2}}\)
\(=\frac{2\sqrt{2}+2}{1+\sqrt{2}}\)
\(=\frac{2\left(\sqrt{2}+1\right)}{\sqrt{2}+1}=2\)
b) Ta có: \(\left(\frac{\sqrt{x}}{\sqrt{x}+3}+\frac{3}{\sqrt{x}-3}\right)\cdot\frac{\sqrt{x}+3}{x+9}\)
\(=\left(\frac{\sqrt{x}\left(\sqrt{x}-3\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}+\frac{3\left(\sqrt{x}+3\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\right)\cdot\frac{1}{\sqrt{x}-3}\)
\(=\frac{x-3\sqrt{x}+3\sqrt{x}+9}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\cdot\frac{1}{\sqrt{x}-3}\)
\(=\frac{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}-3\right)}\cdot\frac{1}{\sqrt{x}-3}\)
\(=\frac{1}{\sqrt{x}-3}\)(đpcm)
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bài 2: giải các bpt sau:
1) (x-2)(9-x^2)≤0
2) (x^2-x-6)(x^2-3x+2)≥0
3) frac{left(x-2right)left(9-xright)}{x-1}≤0
4) frac{xleft(x^2-3x+2right)}{x+4}≥0
5) frac{left(x+2right)}{left(x+1right)left(x-2right)}0
6) frac{left(x-2right)left(9-x^2right)}{x-1}≥0
7) frac{x^2left(x-3right)}{3x^2+x-4}≥0
8) frac{x^2-3x+2}{9-x}≥0
9) frac{x^2+1}{x^2+3x-10}≤0
10) frac{x^2-9x+14}{x^2+9x+14}≥0
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bài 2: giải các bpt sau:
1) (x-2)(\(9-x^2\))≤0
2) (\(x^2-x-6\))(\(x^2-3x+2\))≥0
3) \(\frac{\left(x-2\right)\left(9-x\right)}{x-1}\)≤0
4) \(\frac{x\left(x^2-3x+2\right)}{x+4}\)≥0
5) \(\frac{\left(x+2\right)}{\left(x+1\right)\left(x-2\right)}\)<0
6) \(\frac{\left(x-2\right)\left(9-x^2\right)}{x-1}\)≥0
7) \(\frac{x^2\left(x-3\right)}{3x^2+x-4}\)≥0
8) \(\frac{x^2-3x+2}{9-x}\)≥0
9) \(\frac{x^2+1}{x^2+3x-10}\)≤0
10) \(\frac{x^2-9x+14}{x^2+9x+14}\)≥0
giải các bất phương trình sau:
1) (x-2)(9-x2)≤0
2) (x2-x-6)(x2-3x+2)≥0
3) frac{left(x-2right)left(9-xright)}{x-1}≤0
4) frac{xleft(x^2-3x+2right)}{x+4}≥0
5) frac{left(x+2right)}{left(x+1right)left(x-2right)}0
6) frac{left(x-2right)left(9-x^2right)}{x-1}≥0
7) frac{x^2left(x-3right)}{3x^2+x-4}≥0
8) frac{x^2-3x+2}{9-x}≥0
9) frac{x^2+1}{x^2+3x-10}≤0
10) frac{x^2-9x+14}{x^2+9x+14}≥0
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giải các bất phương trình sau:
1) (x-2)(9-x2)≤0
2) (x2-x-6)(x2-3x+2)≥0
3) \(\frac{\left(x-2\right)\left(9-x\right)}{x-1}\)≤0
4) \(\frac{x\left(x^2-3x+2\right)}{x+4}\)≥0
5) \(\frac{\left(x+2\right)}{\left(x+1\right)\left(x-2\right)}\)<0
6) \(\frac{\left(x-2\right)\left(9-x^2\right)}{x-1}\)≥0
7) \(\frac{x^2\left(x-3\right)}{3x^2+x-4}\)≥0
8) \(\frac{x^2-3x+2}{9-x}\)≥0
9) \(\frac{x^2+1}{x^2+3x-10}\)≤0
10) \(\frac{x^2-9x+14}{x^2+9x+14}\)≥0
rút gọn bt A=\(\frac{2\sqrt{x}-9}{x-5\sqrt{x}+6}-\frac{\sqrt{x}-3}{\sqrt{x}-2}-\frac{2\sqrt{x}+1}{3-\sqrt{x}}\) với x≥0, x≠4,x≠9
1/ Cho Dfrac{x^2-sqrt{x}}{x+sqrt{x}+1}-frac{x^2+sqrt{x}}{x-sqrt{x}+1}với 0≤x≤1
a) Rút gọn
b) CMinh 1-sqrt{D+x+1}sqrt{x}
2/Cho Efrac{15sqrt{x}-11}{x+2sqrt{x}-3}+frac{3sqrt{x}-2}{1-sqrt{x}}-frac{2sqrt{x}+3}{sqrt{x}+3}với x≥0 và x≠1
a) Rút gọn
b) Tìm giá trị của x để E frac{1}{2}
c) So sánh E với frac{2}{3}
3/Cho Gleft(frac{x-3sqrt{x}}{x-9}-1right):left(frac{9-x}{x+sqrt{x}-6}+frac{sqrt{x}-3}{sqrt{x}-2}-frac{sqrt{x}+2}{sqrt{x}+3}right)với x≥0,x≠4,x≠9
a) Rút gọn
b) Tìm x để G1
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1/ Cho D=\(\frac{x^2-\sqrt{x}}{x+\sqrt{x}+1}-\frac{x^2+\sqrt{x}}{x-\sqrt{x}+1}\)với 0≤x≤1
a) Rút gọn
b) CMinh 1\(-\sqrt{D+x+1}=\sqrt{x}\)
2/Cho E=\(\frac{15\sqrt{x}-11}{x+2\sqrt{x}-3}+\frac{3\sqrt{x}-2}{1-\sqrt{x}}-\frac{2\sqrt{x}+3}{\sqrt{x}+3}\)với x≥0 và x≠1
a) Rút gọn
b) Tìm giá trị của x để E = \(\frac{1}{2}\)
c) So sánh E với \(\frac{2}{3}\)
3/Cho G=\(\left(\frac{x-3\sqrt{x}}{x-9}-1\right):\left(\frac{9-x}{x+\sqrt{x}-6}+\frac{\sqrt{x}-3}{\sqrt{x}-2}-\frac{\sqrt{x}+2}{\sqrt{x}+3}\right)\)với x≥0,x≠4,x≠9
a) Rút gọn
b) Tìm x để G<1
Bài 1:
a) ( x + 1 )( x - 3 ) ≤ 0
b) left(x^2+1right)left(x-2right) ≥ 0
Bài 2:
a) frac{x-2}{x+1} 0
b) frac{-2}{x-1}0
c) frac{x-1}{x+3}0
d)frac{x^2-x+1}{x+3}0
e) frac{x-2}{x+1} ≤ 0
f) frac{x^2}{x-3} ≥ 0
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Bài 1:
a) ( x + 1 )( x - 3 ) ≤ 0
b) \(\left(x^2+1\right)\left(x-2\right)\) ≥ 0
Bài 2:
a) \(\frac{x-2}{x+1}< 0\)
b) \(\frac{-2}{x-1}>0\)
c) \(\frac{x-1}{x+3}>0\)
d)\(\frac{x^2-x+1}{x+3}>0\)
e) \(\frac{x-2}{x+1}\) ≤ 0
f) \(\frac{x^2}{x-3}\) ≥ 0
cho bt với x≥0 , x≠9
P=\(\left(\frac{2\sqrt{2}}{\sqrt{x}+3}+\frac{\sqrt{x}}{\sqrt{x}-3}-\frac{3x+3}{x-9}\right):\left(\frac{2\sqrt{x}-2}{\sqrt{x}-3}-1\right)\)
a) rút gọn
b)tìm x để P<\(-\frac{1}{3}\)
c)tìm GTNN của P
a) \(P=\left(\frac{2\sqrt{2}}{\sqrt{x}+3}+\frac{\sqrt{x}}{\sqrt{x}-3}-\frac{3x+3}{x-9}\right):\left(\frac{2\sqrt{x}-2}{\sqrt{x}-3}-1\right)\)
\(=\left(\frac{2\sqrt{x}\left(\sqrt{x}-3\right)+\sqrt{x}\left(\sqrt{x}+3\right)-\left(3x+3\right)}{x-9}\right):\left(\frac{2\sqrt{x}-2}{\sqrt{x}-3}-\frac{\sqrt{x}-3}{\sqrt{x}-3}\right)\)\(=\frac{2x-6\sqrt{x}+x+3\sqrt{x}-3x-3}{\left(\sqrt{x}+3\right).\left(\sqrt{x}+1\right)}\)
\(=\frac{-3\left(\sqrt{x}+1\right)}{\left(\sqrt{x}+3\right)\left(\sqrt{x}+1\right)}\)
\(=\frac{-3}{\sqrt{x}+3}\)
cho bt với x≥0 , x≠9
P=\(\left(\frac{2\sqrt{2}}{\sqrt{x}+3}\frac{\sqrt{x}}{\sqrt{x}-3}-\frac{3x+3}{x-9}\right):\left(\frac{2\sqrt{x}-2}{\sqrt{x}-3}-1\right)\)
a) rút gọn
b) tìm x để P<\(-\frac{1}{3}\)
c) tìm GTNN của P