\(\dfrac{30-x}{30}=\dfrac{5}{15};\dfrac{x+30}{72}=\dfrac{5}{8}\)
Tìm X: \(\dfrac{30-x}{30}=\dfrac{8}{15};\dfrac{x+30}{72}=\dfrac{5}{8}\)
\(\dfrac{30-x}{30}=\dfrac{8}{15}\)
\(\Rightarrow\left(30-x\right)15=30\times8\)
\(\Rightarrow\left(30-x\right)15=240\)
\(\Rightarrow30-x=240:15\)
\(\Rightarrow30-x=16\)
\(\Rightarrow x=30-16\)
\(\Rightarrow x=14\)
__
\(\dfrac{x+30}{72}=\dfrac{5}{8}\)
\(\Rightarrow\left(x+30\right)8=5\times72\)
\(\Rightarrow\left(x+30\right)8=360\)
\(\Rightarrow x+30=360:8\)
\(\Rightarrow x+30=45\)
\(\Rightarrow x=45-30\)
\(\Rightarrow x=15\)
\(\dfrac{11}{9}\) - \(\dfrac{5}{6}\) : 15
\(\dfrac{3}{16\:}\)+ \(\dfrac{ }{ }\)\(\dfrac{7}{30}\) x \(\dfrac{15}{28}\)
11/9-5/6:15
=11/9-5/6.1/15
=11/9-1/18
=7/6
3/16+(-7/30).15/28
=3/16+(-1/8)
=3/16+(-2/16)
=1/16
\(\dfrac{11}{9}-\dfrac{5}{6}:15=\dfrac{11}{9}-\dfrac{5}{6}\times\dfrac{1}{15}=\dfrac{11}{9}-\dfrac{5}{90}=\dfrac{110}{90}-\dfrac{5}{90}=\dfrac{105}{90}=\dfrac{7}{6}\)
\(\dfrac{3}{16}+\dfrac{-7}{30}\times\dfrac{15}{28}=\dfrac{3}{16}+\left(-\dfrac{1}{8}\right)=\dfrac{3}{16}-\dfrac{1}{8}=\dfrac{3}{16}-\dfrac{2}{16}=\dfrac{1}{16}\)
15: nếu \(\dfrac{x}{-15}\)=\(\dfrac{-60}{x}\) thì kết quả x bằng:
A) x=30 B) x=30 hoặc x=-1 C) x=3= hoặc x=-30 D) x=\(\dfrac{60}{15}\)
\(x^2=900\Leftrightarrow x^2=30^2\Rightarrow x=30\)
Chọn A
GIÚP MÌNH VỚI
a, x - \(\dfrac{5}{7}\)=\(\dfrac{19}{21}\)
b,\(\dfrac{5}{3}\)-I x - \(\dfrac{1}{5}\)I = \(\dfrac{1}{3}\)
c, (x - \(\dfrac{2}{5}\)) = \(\dfrac{1}{4}\)
d, 5\(\sqrt{x}\) - 30 = 15
\(a,x-\dfrac{5}{7}=\dfrac{19}{21}\\ x=\dfrac{34}{21}\\ b,\dfrac{5}{3}-\left|x-\dfrac{1}{5}\right|=\dfrac{1}{3}\\ \left|x-\dfrac{1}{5}\right|=\dfrac{4}{3}\\ TH1:x-\dfrac{1}{5}=\dfrac{4}{3}\\ x=\dfrac{23}{15}\\ TH2:x-\dfrac{1}{5}=-\dfrac{4}{3}\\ x=-\dfrac{17}{15}\\ c,x-\dfrac{2}{5}=\dfrac{1}{4}\\ x=\dfrac{13}{20}\\ d,5\sqrt{x}-30=15\\ 5\sqrt{x}=45\\ \sqrt{x}=9\\ x=9^2=81\)
Tìm x biết:
\(\dfrac{3}{5}\cdot\left(2x-\dfrac{1}{3}\right)+\dfrac{4}{15}=\dfrac{12}{30}\).
\(\Leftrightarrow2x-\dfrac{1}{3}=\left(\dfrac{12}{30}-\dfrac{4}{15}\right):\dfrac{3}{5}=\dfrac{2}{9}\)
=>2x=5/9
hay x=5/18
\(\dfrac{3}{5}.\left(\dfrac{ }{ }2x-\dfrac{1}{3}\right)=\dfrac{12}{30}-\dfrac{4}{15}\)
\(\dfrac{3}{5}.\left(2x-\dfrac{1}{3}\right)=\dfrac{2}{15}\)
\(2x-\dfrac{1}{3}=\dfrac{2}{9}\)
2x= \(\dfrac{2}{9}+\dfrac{1}{3}\)
2x = \(\dfrac{5}{9}\)
x = \(\dfrac{5}{18}\)
Trong phép tính sau, giá trị của x là :
\(\dfrac{5}{9}\) : x = \(\dfrac{8}{9}\) - \(\dfrac{1}{5}\)
a. \(\dfrac{11}{6}\)
b. \(\dfrac{44}{30}\)
c. \(\dfrac{25}{31}\)
d. \(\dfrac{22}{15}\)
\(\dfrac{5}{9}:x=\dfrac{40}{45}-\dfrac{9}{45}\)
\(\dfrac{5}{9}:x=\dfrac{31}{45}\)
\(x=\dfrac{5}{9}:\dfrac{31}{45}\)
\(x=\dfrac{225}{279}=\dfrac{25}{31}\)
`=>C`
Tìm x biết rằng:
\(\dfrac{-5}{6}-x=\dfrac{7}{12}+\dfrac{-2}{3}\)
b) Tìm tập hợp các số của x biết rằng:
\(\dfrac{-7}{15}+\dfrac{4}{30}+\dfrac{12}{45}< _-\dfrac{x}{15} < _-\dfrac{3}{5}+ \dfrac{4}{15}+\dfrac{-2}{5}\)
\(\dfrac{-5}{6}\)- x=\(\dfrac{7}{12}\)+\(\dfrac{-8}{12}\)=\(\dfrac{-15}{12}\)
\(\Rightarrow\)x=\(\dfrac{-5}{6}\)-\(\dfrac{-15}{12}\)=\(\dfrac{-10}{12}\)-\(\dfrac{-15}{12}\)=\(\dfrac{-25}{12}\)
Tìm x biết:
\(a,\dfrac{4}{5}+x=\dfrac{2}{3}\)
\(b,\dfrac{-5}{6}-x=\dfrac{2}{3}\)
\(c,\dfrac{1}{2}x+\dfrac{3}{4}=\dfrac{-3}{10}\)
\(d,\dfrac{x}{3}-\dfrac{1}{2}=\dfrac{1}{5}\)
\(e,\dfrac{x+3}{15}=\dfrac{1}{3}\)
\(h,x+30\%x=-1,3\)
\(k,3\dfrac{1}{3}x+16\dfrac{1}{4}=13,25\)
\(m,\dfrac{x-6}{2}=\dfrac{50}{x-6}\)
\(n,x-13,4=24,5-6,7.5,2\)
\(p,15,7x+3,6x=-96,5\)
\(q,2,5x-11,6=-59,1\)
a)4/5+x=2/3
x=2/3-4/5
x=-2/15
b)-5/6-x=2/3
x=-5/6-2/3
x=-3/2
c)1/2x+3/4=-3/10
1/2x=-3/10-3/4
1/2x=-21/20
x=-21/20:1/2
x=-21/10
d)x/3-1/2=1/5
x/3=1/5+1/2
x/3=7/10
10x/30=21/30
10x=21
x=21:10
x=21/10
a) \(\dfrac{2}{15}\cdot x-x=30\%\)
b) \(\dfrac{x}{2}\cdot\dfrac{x}{3}=\dfrac{5}{6}\)
a)\(\dfrac{2}{15}x-x=30\%\)
<=>x\(\left(\dfrac{2}{15}-1\right)=\dfrac{30}{100}\)
<=>\(-\dfrac{13}{15}x=\dfrac{3}{10}\)
<=>x=\(\dfrac{3}{10}\cdot\left(-\dfrac{15}{13}\right)\)
<=>x=\(-\dfrac{9}{26}\)
Vậy tập nghiệm S={\(-\dfrac{9}{26}\)}
b)\(\dfrac{x}{2}\cdot\dfrac{x}{3}=\dfrac{5}{6}\)
<=>\(\dfrac{x^2}{6}=\dfrac{5}{6}\)
<=>x2=5
<=>x=\(_-^+\sqrt{5}\)
Vậy tập nghiệm S={\(_-^+\sqrt{5}\)}
a, \(\dfrac{2}{15}x-x=30\%\)
\(\Rightarrow\left(\dfrac{2}{15}-1\right)x=\dfrac{3}{10}\)
\(\Rightarrow\dfrac{-13}{15}x=\dfrac{3}{10}\)
\(\Rightarrow x=\dfrac{3}{10}.\dfrac{-15}{13}\)
\(\Rightarrow x=\dfrac{-9}{26}\)Lời giải:
b, \(\dfrac{x}{2}.\dfrac{x}{3}=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{x.x}{2.3}=\dfrac{5}{6}\)
\(\Rightarrow\dfrac{x^2}{6}=\dfrac{5}{6}\)
\(\Rightarrow x^2=5\)
\(\Rightarrow x=\pm\sqrt{5}\)