Question

Tìm x biết:

\(\dfrac{3}{5}\cdot\left(2x-\dfrac{1}{3}\right)+\dfrac{4}{15}=\dfrac{12}{30}\).

Answer 1

\(\Leftrightarrow2x-\dfrac{1}{3}=\left(\dfrac{12}{30}-\dfrac{4}{15}\right):\dfrac{3}{5}=\dfrac{2}{9}\)

=>2x=5/9

hay x=5/18

Answer 2

x= 5/18

Answer 3

\(\dfrac{3}{5}.\left(\dfrac{ }{ }2x-\dfrac{1}{3}\right)=\dfrac{12}{30}-\dfrac{4}{15}\)

\(\dfrac{3}{5}.\left(2x-\dfrac{1}{3}\right)=\dfrac{2}{15}\)

\(2x-\dfrac{1}{3}=\dfrac{2}{9}\)

2x= \(\dfrac{2}{9}+\dfrac{1}{3}\)

2x = \(\dfrac{5}{9}\)

x = \(\dfrac{5}{18}\)

Answer 4

\(\dfrac{3}{5}.\left(2x-\dfrac{1}{3}\right)+\dfrac{4}{15}=\dfrac{12}{30}\)

\(\dfrac{3}{5}.\left(2x-\dfrac{1}{3}\right)\)           \(=\dfrac{12}{30}+\left(\dfrac{-4}{15}\right)=\dfrac{2}{15}\)

     \(\left(2x-\dfrac{1}{3}\right)\)           \(=\dfrac{2}{15}.\dfrac{5}{3}=\dfrac{2}{9}\)

        \(2x\)                     \(=\dfrac{2}{9}+\dfrac{1}{3}=\dfrac{5}{9}\)

          \(x\)                     \(=\dfrac{5}{9}.\dfrac{1}{2}=\dfrac{5}{18}\)