Câu hỏi của Thanh Bình - Hóa học lớp 9

\(PTHH:2CH_3COOH+Zn\rightarrow\left(CH_3COO\right)_2Zn+H_2\)

Ta có:

\(n_{CH3COOH}=\frac{5,8}{60}=\frac{29}{300}\left(mol\right)\)

\(\Rightarrow n_{H2}=\frac{29}{600}\left(mol\right)\)

\(\Rightarrow V_{H2}=\frac{29}{600}.22,4=1,08\left(l\right)\)

\(CH_3COOH+C_2H_5OH\underrightarrow{^{t^oH2SO4}}CH_3COOC_2H_5+H_2O\)

\(V_{C2H5OH}=15,5.45\%=6,975\left(ml\right)\Rightarrow n_{C2H5OH}=\frac{0,9.6,975}{46}=0,136\left(mol\right)\)

\(n_{C2H5OH\left(Dư\right)}=0,136-\frac{29}{300}=0,039\left(mol\right)\)

\(\Rightarrow m_{C2H5OH\left(dư\right)}=0,039.46=1,794\left(g\right)\)