Question

tính tổng

A = \(\frac{6}{5.8}+\frac{22}{8.19}+\frac{24}{19.31}+\frac{140}{31.101}+\frac{198}{101.200}\)

ai nhanh dc tick nhé

nhanh dc 5 tick

Answer 1

\(A=\frac{6}{5.8}+\frac{22}{8.19}+\frac{24}{19.31}+\frac{140}{31.101}+\frac{198}{101.200}\)

\(\Rightarrow A=\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{19}+\frac{1}{19}-\frac{1}{31}+\frac{1}{31}-\frac{1}{101}+\frac{1}{101}-\frac{1}{200}\)

\(\Rightarrow A=\frac{1}{5}-\frac{1}{200}\)

\(\Rightarrow A=\frac{39}{200}\)

Answer 2

Answer 3

A=2.(3\5.8+11\8.19+12\19.31+70\31.101+99\101\200)

A=2.(1\5-18+1\8-1\19+....+1\101-1\200)

A=2.(1\5-1\200)

A=2.39\200

A=39\100

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