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https://olm.vn/hoi-dap/question/374799.html
(x-3)+(x-2)+......+10+11=11
Tìm x : a) (x-3)+(x-2)+(x-1)+......+10+11=11 b)x+(x+1)+(x+2)+.......+2018+2019=2019
1) Tìm x biết
a) -3/7=x/91
B) x/5=6/-10
C) 2/x=x/8
d) x+1/3=-2/5
e)x -1/5=-2/7
f)-3/8-x=-2/5
g) x:8/11=11/3
h) -1/4.x=5/8.2/3
Tìm số nguyên x biết: (x-3)+(x-2)+(x-1)+10+11=110
tìm x
x-4=11-2x
(x-3).(x-2)=0
7x-10=x-28
\(\left|x-5\right|=10-\left|-2\right|\)
Tìm x thuộc Z, biết:
a.(7x-11)3=25.52+200
b.(8x -11)3=25.52+200
c.(2x)3.3=192
d.8x=43
e.x10=x
h.x10=1x
k.x10=x
i.(2x-15)5=(2x-15)3
l.(x+1)5=96:3
X+8/12+x+11/9+x+10/10+3=0
Hãy tìm x
Tìm x biết: (11/12+11/276+11/782+..............+11/8900).x=2/3