Question

Trục căn thức ở mẫu: \(\dfrac{x-1}{\sqrt{x}-1}\) với x > 1.

Answer 1

\(\dfrac{x-1}{\sqrt{x}-1}=\dfrac{\left(x-1\right)\left(\sqrt{x}+1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)

\(=\dfrac{\left(x-1\right)\left(\sqrt{x}+1\right)}{x-1}=\sqrt{x}+1\)