Ta có: \(\overrightarrow a \)= \({a_1}\overrightarrow i \)+\({a_2}\overrightarrow j \)+\({a_3}\overrightarrow k \)
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Ta có: \(\overrightarrow a \)= \({a_1}\overrightarrow i \)+\({a_2}\overrightarrow j \)+\({a_3}\overrightarrow k \)