Question

Tính:

\(\sqrt{5,1^2}\);               \(\sqrt{\left(-4,9\right)^2}\);             \(-\sqrt{\left(-0,001\right)^2}\).

Answer 1

Ta có:

\(\sqrt {5,{1^2}}  = \left| {5,1} \right| = 5,1;\\\sqrt {{{\left( { - 4,9} \right)}^2}}  = \left| {-4,9} \right| = 4,9; \\- \sqrt {{{\left( { - 0,001} \right)}^2}}  =  - \left| {-0,001} \right| =  - 0,001.\)