Fe3O4
%Fe=\(\frac{\text{56.3}}{232}.100\%\)=72,41%
%O=100-72,41=27,59%
Na2CO3
%Na=\(\frac{\text{23.2}}{106}.100\%\)=43,4%
%C=\(\frac{12}{106}.100\)=11,3%
%O=100-43,4-11,3=45,3%
K3PO4
%K=\(\frac{\text{39.3}}{212}.100\%\)=55,19%
%P=\(\frac{31}{212}.100\)=14,62%
%O=100-55,19-14,62=30,19%
KMnO4
%K=\(\frac{39}{158}.100\%\)=24,68%
%Mn=\(\frac{55}{158}.100\%\)=34,81%
%O=100-24,68-34,81=40,51%
Các bài sau làm tương tự kết quả như sau
(NH4)2SO4
%N=21,21% %H=6,06% %S=24,24% %O=48,49%
Ba(OH)2
%Ba=80,17%
%O=18,71%
%H=1,17%
Al2(SO4)3
%Al=15,79%
%S=28,07%
%O=56,14%
