a) nFe = \(\frac{3,6}{56}=0,06\left(mol\right)\)
b) nS = \(\frac{12}{32}=0,375\left(mol\right)\)
c) nAl = \(\frac{24}{22,4}\approx1,07\left(mol\right)\) đktc
d) nN = \(\frac{9}{14}=0,6\left(mol\right)\)
e) nP = \(\frac{16}{22,4}=0,7\left(mol\right)\) đktc