a) \(PTK_{Fe_2O_3}=56\times2+16\times3=160\left(đvC\right)\)
\(PTK_{CaO}=40+16=56\left(đvC\right)\)
b) \(PTK_{FePO_4}=56+31+16\times4=151\left(đvC\right)\)
\(PTK_{Ca_3\left(PO_4\right)_2}=40\times3+2\times\left(31+16\times4\right)=310\left(đvC\right)\)